Title: Midpoints
1Midpoints
2What is the midpoint?
4
0
3How did you get it?
4
0
2
4/2 2
4What is the midpoint?
5
1
5How did you get it?
5
1
(15)/2 3
6In other words,its just the average!
5
3
3
6
1
7In two dimensions
(8, 6)
(2, 2)
8Average the x-coords
2
8
92
8
10(5, _ )
2
8
(28)/2
11Average the y-coords
6
(5, _ )
2
126
(5, _ )
2
136
(26)/2
(5, 4 )
2
14The Midpoint (5,4)
(8, 6)
(26)/2
(5, 4)
(2, 2)
(28)/2
15(No Transcript)
16The Algorithm Method
2. ( 2 , 2 ) 2nd Point
3. 10 8 sums
4. ( 5 , 4 ) halves
17Find the midpoint between
(6, 0) and (2, 4)
(4, 2)
18Find the midpoint between
(2, -3) and (4, 2)
(3, -½)
19Find the midpoint between
(-4, -3) and (2, 2)
(-1, -½)
20The Distance Formula
21The Pythagorean Theorem
5
3
4
22The Pythagorean Theorem
9
5
3
4
23The Pythagorean Theorem
9
5
3
4
16
24The Pythagorean Theorem
25
9
5
3
4
16
25The Pythagorean Theorem
25
9
5
3
25 9 16
4
16
26The Pythagorean Theorem
25
9
5
3
52 32 42
4
16
27The Pythagorean Theorem
c
a
c2 a2 b2
b
28The Pythagorean Theorem
c
a
b
The length of the hypotenuse of a right triangle
is equal to the square root of the sum of the
squares of the length of the legs.
29Finding distance
(6, 5)
(2, 2)
30using the right triangle.
(6, 5)
5
2
(2, 2)
6
2
31We need a and b to get c.
5
c
b
2
a
6
2
32The Difference of the Coordinates
5
c
b5-2
2
a6-2
6
2
33The Difference of the Coordinates
5
c
b5-2
2
a6-2
6
2
34c
3
4
35Finding distance
(x2, y2)
(x1, y1)
36using the right triangle.
(x2, y2)
y2
y1
(x1, y1)
x2
x1
37The Difference of the Coordinates
y2
c
b y2- y1
y1
a x2-x1
x2
x1
38c v(x2-x1)2 (y2- y1 ) 2
c
y2- y1
x2-x1
39Does order matter? Why?
distance v(x2-x1)2 (y2- y1 ) 2
distance v(x1-x2)2 (y1- y2 ) 2
(5-3)2 (2)2 4
(3-5)2 (-2)2 4
40The Algorithm Method
2. - ( 2 , 2 ) 2nd Point
3. 4 3 differences
4. 16 9 squares
5. 25 sum
6. 5 sq. root
41Find the distance between
(2, -3) and (4, 2)
v29
42Find the distance between
(-4, -3) and (-6, 2)
5v5
43Find the distance between
(6, 0) and (2, 4)
4v2
44Homework