Title: King Fahd University of Petroleum
1King Fahd University of Petroleum Minerals
- Mechanical Engineering
- Dynamics ME 201
- BY
- Dr. Meyassar N. Al-Haddad
- Lecture 2
2Objective
- To introduce the concepts of position,
displacement, velocity, and acceleration. - To study particle motion along a straight line.
3Rectilinear KinematicsSection 12.2
- Rectilinear Straight line motion
- Kinematics Study the geometry of the motion
dealing with s, v, a. - Rectilinear Kinematics To identify at any given
instant, the particles position, velocity, and
acceleration. - (All objects such as rockets, projectiles, or
vehicles will be considered as particles has
negligible size and shape - particles has mass but negligible size and
shape
4Position
- Position Location of a particle at any given
instant with respect to the origin -
- r Displacement ( Vector )
- s Distance ( Scalar )
5Distance Displacement
- Displacement defined as the change in position.
- r Displacement ( 3 km )
- s Distance ( 8 km )
- Total length
- For straight-line
- Distance Displacement
- s r
- D s D r
- Vector is direction oriented
- Dr positive (left )
- Dr negative (right)
6Velocity Speed
- Velocity Displacement per unit time
- Average velocity
- V Dr / Dt
- Speed Distance per unit time
- Average speed
- usp sT / Dt (Always positive scalar )
- Speed refers to the magnitude of velocity
- Average velocity
- uavg Ds / Dt
7Velocity (con.)
- Instantaneous velocity
- For straight-line Dr Ds
8Problem
- A particle moves along a straight line such that
its position is defined by s (t3 3 t2 2 )
m. Determine the velocity of the particle when t
4 s.
At t 4 s, the velocity 3 (4)2 6(4) 24 m/s
9Acceleration
- Acceleration The rate of change in velocity
(m/s)/s - Average acceleration
- Instantaneous acceleration
- If v gt v Acceleration
- If v lt v Deceleration
10Problem
- A particle moves along a straight line such that
its position is defined by s (t3 3 t2 2 )
m. Determine the acceleration of the particle
when t 4 s. - At t 4
a(4) 6(4) - 6 18 m/s2
11Problem
- A particle moves along a straight line such that
its position is defined by s (t3 12 t2 36
t -20 ) cm. Describe the motion of P during the
time interval 0,9
t 0 2 4 6 9
s -20 12 -4 -20 61
v 36 0 -12 0 63
a -24 -12 0 12 30
Total time 9 seconds Total distance
(323281) 145 meter Displacement form -20 to
61 81 meter Average Velocity 81/9 9 m/s to
the right Speed 9 m/s Average speed 145/9
16.1 m/s Average acceleration 27/9 3 m/s2 to
the right
12Relation involving s, v, and aNo time t
Position s
Velocity
Acceleration
13Problem 12.18
- A car starts from rest and moves along a straight
line with an acceleration of a ( 3 s -1/3 )
m/s2. where s is in meters. Determine the cars
acceleration when t 4 s. - Rest t 0 , v 0
14For constant accelerationa ac
15Velocity as a Function of Time
16Position as a Function of Time
17velocity as a Function of Position
18Free Fall
- Ali and Omar are standing at the top of a cliff
of height H. Both throw a ball with initial
speed v0, Ali straight down and Omar straight up.
The speed of the balls when they hit the ground
are vA and vO respectively. Which of the
following is true - (a) vA lt vO (b) vA vO (c) vA gt
vO
v0
Omar
Ali
v0
H
vA
vO
19 Free fall
- Since the motion up and back down is symmetric,
intuition should tell you that v v0 - We can prove that your intuition is correct
Equation
This looks just like Omar threw the ball down
with speed v0, sothe speed at the bottom
shouldbe the same as Alis ball.
Omar
v0
v v0
H
y 0
20Free fall
- We can also just use the equation directly
Ali
same !!
Omar
v0
Ali
Omar
y H
v0
y 0
21Summary
- Time dependent acceleration
This applies to a freely falling object
22Thank you
23Gravity facts
- g does not depend on the nature of the material!
- Galileo (1564-1642) figured this out without
fancy clocks rulers! - Nominally, g 9.81 m/s2
- At the equator g 9.78 m/s2
- At the North pole g 9.83 m/s2
- More on gravity in a few lectures!