Title: Applications of Aqueous Equilibria
1Applications of Aqueous Equilibria
- Acid-Base Equilibria
- More Acid-Base Equilibria
- Solubility of Salts
- Formation of Complex Ions
2Applications of Aqueous Equilibria
- Natural processes that involve these equilibria
- weathering of minerals
- uptake of nutrients by plants
- tooth decay
- formation of limestone caverns, stalactites, and
stalagmites
3Applications of Aqueous Equilibria
- Common Ion Problems
- Involve solutions that contain a weak acid, HA,
and its salt, NaA - Ex Given a solution containing HF
(Ka 7.2 x 10-4) and its salt, NaF. What
happens to the dissociation of HF? - NaF is a strong electrolyte, i.e. it ionizes 100
- NaF ---gt Na F-
4Applications of Aqueous Equilibria
- HF is a weak acid
- HF ltgt H F-
- Therefore, the major species in the solution is
Na, F-, HF, and H2O - F- is a common ion, since it is produced by both
HF and NaF.
5Applications of Aqueous Equilibria
- Apply Le Chateliers Principle. The F- present
from the ionization of NaF forces the HF to
ionize less as the reverse reaction is favored. - The acidity of a solution with a common ion
present is less than a solution of HF alone, i.e.
the H is less, or the pH is greater.
6Applications of Aqueous Equilibria
- Buffered Solutions
- consists of a solution that contains a weak acid
and its salt or a weak base and its salt. - resists changes in pH upon the addition of an
acid or base - Ex Our blood is a buffered solution which can
absorb acids or bases without changing its pH,
which is important because our cells can only
survive in a narrow pH range.
7Applications of Aqueous Equilibria
- A solution can be buffered to any pH by choosing
the appropriate components and concentrations. - Buffered solutions are still only solutions of
weak acids or weak bases containing a common ion.
The pH calculations are the same as presented
before.
8Applications of Aqueous Equilibria
- How does buffering work?
- Buffered solution contains HA and A-.
- Add OH-
- OH- reacts with the HA
- OH- HA --gt H2O A-
- The OH- gets eaten up as it forms water, so
with no extra OH- in the system, the pH remains
the same.
9Applications of Aqueous Equilibria
- Add H
- The H reacts with the A- to reform HA
- H A- --gt HA
- The added H gets eaten up as it reforms HA,
with no extra H in the system, the pH remains
the same.
10Applications of Aqueous Equilibria
- Buffered solutions can be formed with a weak
base, B, and its salt, BH. - Add OH-
- the OH- will react with the BH
- OH- BH --gt B H2O
- the extra OH- gets eaten up by the H to form
water. - With no extra OH- in the system, the pH stays the
same.
11Applications of Aqueous Equilibria
- Add H
- The H will react with the B to form the salt
- H B --gt BH
- The extra H is eaten up by the B, with no
extra H in the system, the pH remains the same.
12Applications of Aqueous Equilibria
- Henderson-Hasselbach equation
- Start with Ka expression
- Ka HA-/HA
- Rearrange to get H KaHA/A-
- Take the negative log of both sides
- pH pKa - log(HA/A-) or
- pH pKa log (A-/HA) or
- pH pKa log (base/acid)
- Useful for calculating the pH when the HA/A-
ratio is known.
13Applications of Aqueous Equilibria
- Important characteristics of buffered solutions
- they contain large concentrations of a weak acid
and the corresponding weak base - HA and A- or
- B and BH
14Applications of Aqueous Equilibria
- Important characteristics of buffered solutions
- Add H, it will react with the weak base to form
a weak acid - H A- --gt HA or
- H B --gt BH
- Add OH-, it will react with the weak acid to form
a weak base and water - OH- HA --gt H2O A- or
- OH- BH --gt H2O B
15Applications of Aqueous Equilibria
- Important characteristics of buffered solutions
- the pH of a buffered solution depends on the
ratio of the concentrations of the weak acid and
the weak base. - While this ratio remains constant, the pH will
remain constant.
16Applications of Aqueous Equilibria
- This ratio will remain constant as long as the
concentrations of the buffering materials are
large compared to the amounts of H or OH- added
17Applications of Aqueous Equilibria
- Buffer Capacity
- the amount of H or OH- a buffer can absorb
without a significant change in the pH - a buffer with a large capacity can absorb a large
amount of H or OH- with only a little change in
the pH - a buffer with a large capacity contains a large
concentration of the weak acid and its salt
18Applications of Aqueous Equilibria
- pH of a buffered solution
- determined by the ratio of A-/HA
- optimal buffering (least change in pH) will occur
when A- HA - so pH pKa log (1)
- so pH pKa 0
- so pH pKa
- Pick an acid with a Ka closest to the desired pH
of the buffered solution.
19Applications of Aqueous Equilibria
- Titration and pH curves
- Titration
- used to determine the concentration or amount of
an unknown acid or base - uses a solution of known concentration (the
titrant) - uses a buret (for precision)
- uses an indicator to show the endpoint
- can be monitored by plotting pH vs. amount of
titrant added
20Applications of Aqueous Equilibria
- Strong Acid-Strong Base Titrations
- millimoles may be used because of the small
quantities used in a titration - 1000 millimoles 1000mmoles 1 mole
- Molarity moles/liter mmoles/mL
- mmoles Volume (in mL) x Molarity
21Applications of Aqueous Equilibria
- Strong Acid-Strong Base Titration
- Ex Titration of 50.0 mL of 0.200 M HNO3 with
0.100 M NaOH - What is the pH at various stages of the
titration? - Initially...No NaOH has been added
- pH is determined by H from the 0.200 M HNO3
- pH - log (0.200) 0.699
- 50.0 mL x 0.200 M H 10.0 mmol H present
22Applications of Aqueous Equilibria
- Still the beginning of the reaction10.0 mL of
0.100 M NaOH has been added - The added OH- will neutralize an equivalent
amount of H, I.e., 10.0 ml x 0.100 M or 1.00
mmole. - How much H is left? 10.0 mmole - 1.00 mmole
9.0 mmole H - What is the concentration of H now?
- 9.0 mmole/ (50.0 mL 10.0 mL) 0.15 M
- pH -log (0.15) 0.82pH is increasing
23Applications of Aqueous Equilibria
- 20.0 mL of NaOH has been added
- pH 0.942
- 50.0 mL of NaOH as been added
- pH 1.301
24Applications of Aqueous Equilibria
- Strong Acid-Strong Base Titration
- At the equivalence point100.0 mL of NaOH has
been added - 100.0 mL x 0.100 M 10.0 mmole OH-
- This is enough OH- to completely react with the
H in solution. - At the equivalence point, the pH is 7, the
solution is neutral
25Applications of Aqueous Equilibria
- 150.0 mL of NaOH has been added
- now OH- is in excess, the pH is determined by the
excess OH- - 150.0 mL x 0.100 M 15.00 mmoles OH-
- 15.00 mmoles OH- - 10.0 mmoles H 5.0 mmoles
OH- in solution - 5.0 mmoles/ (50.0 150.0 mL) 0.025 M OH-.so
H 4.0 x 10-13pH 12.40
26Applications of Aqueous Equilibria
- 200.0 mL of NaOH has been added
- still excess OH-
- pH 12.60
27Applications of Aqueous Equilibria
- Strong Acid-Strong Base Titration
- pH changes very little initially until close to
the equivalent point (lots of H, added OH-
doesnt change the pH much) - Near the equivalence point, there is less H, so
added OH- changes the pH a lot - At the equivalence point, the pH 7.00
- Just after the equivalence point, added OH- also
changes the pH a lot
28Applications of Aqueous Equilibria
- Weak Acid-Strong Base Titration
- Calculating the titration curve is like solving a
series of buffer problems. - Involves a stoichiometry problem where the
reaction goes to completion and the
concentrations of the weak acid and the conjugate
base are calculated - Involves an equilibrium problem, calculate pH
from this
29Applications of Aqueous Equilibria
- pH curve for this titration is different before
the equivalence point from the strong acid-strong
base titration - after the equivalence point, the titration curves
are the same
30Applications of Aqueous Equilibria
- For a weak acid-strong base titration, the pH
rises more rapidly in the beginning of the
titration, then levels off at the halfway point
due to buffering effects. - pH at the equivalence point is higher than for a
strong acid-strong base titration
31Applications of Aqueous Equilibria
- Weak acid-Strong Base titration
- The amount of acid determines the equivalence
point - The pH value at the equivalence point depends on
the acid strength - the weaker the acid, the higher the pH at the
equivalence point
32Applications of Aqueous Equilibria
- Acid-Base Indicators
- Two common methods for determining the
equivalence point of a titration - Use a pH meter and then plot the titration curve.
The center of the vertical region of the pH
curve indicates the equivalence point. - Use an acid-base indicator to mark the end point
with a change in color.
33Applications of Aqueous Equilibria
- Acid-Base Indicators
- The endpoint (when the indicator changes color)
may not be the same as the equivalence point. - An indicator must be chosen based on the acid and
base used in the titration so that the endpoint
is as close to the equivalence point as possible.
34Applications of Aqueous Equilibria
- Acid-Base Indicators
- Indicators are usually complex molecules that are
weak acids (HIn) - HIn is one color while In is another color.
- For example, phenolphthalein is colorless in the
HIn form, but pink in the In form.
35Applications of Aqueous Equilibria
- HIn (Red) --gt In (blue) H
- Ka HIn-/HIn
- Rearrange to get
- Ka In-
- H HIn
- Lets say the indicators Ka 1 x 10-8
- Add a few drops of the indicator to an acidic
solution of pH 1.0
36Applications of Aqueous Equilibria
- 1 x 10-8 In-
- 1 x 10-1 HIn
- 1 x 10-7 1 In-
- 10,000,000 HIn
- So in an acidic solution, most of the Indicator
will be in the red HIn form. - As OH- is added, the H dcreases, shifting the
equilibrium so more In- and less HIn is present. - When will the color change, or rather, when can
the human eye detect the color change? - At a pH when In- /HIn 1/10
37Applications of Aqueous Equilibria