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Transformers

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Equivalent circuit referred to the LT side of a 250/2500 single phase transformer is shown in fig. The load impedance connected to HT is 380+j230 . – PowerPoint PPT presentation

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Title: Transformers


1
Transformers
Purpose to change alternating (AC) voltage to
a bigger (or smaller) value
changing flux in secondary induces emf
input AC voltage in the primary produces a flux
2
Principle of Transformer Action
3
Principle of Transformer Action
  • Principal of Transformer Action
  • Principle of electromagnetic induction.
  • Ideal t?o ?inding transformer
  • ?inding resistances are negligible
  • Fluxes confined to magnetic core
  • Core lose negligible
  • Core has constant permeability
  • V1 I1 MMF N1Ie
  • Core flux f follo?s, Ie very closely.
  • Ie f sinusoidal
  • f fmax sin?t

4
Principle of Transformer Action
5
Transformers
  • Nothing comes for free, however!
  • Increase in voltage comes at the cost of current.
  • Output power cannot exceed input power!
  • power in power out

6
Transformers Sample Problem
  • A transformer has 330 primary turns and 1240
    secondary turns. The input voltage is 120 V and
    the output current is 15.0 A. What is the output
    voltage and input current?

step-up transformer
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9
Ideal Transformer on an inductive load
10
  • The exciting current leads the flux by hysteretic
    angle,

11
Transformer on LOAD
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  • Equivalent circuit referred to the LT side of a
    250/2500 single phase transformer is shown in
    fig. The load impedance connected to HT is
    380j230?. For a primary voltage of 250V, compute
  • the secondary terminal voltage
  • primary current and power factor
  • Power output and efficiency

20
Equivalent circuit referred to the LT side of a
250/2500 single phase transformer is shown in
fig. The load impedance connected to HT is
380j230?. For a primary voltage of 250V,
compute
  • the secondary terminal voltage
  • primary current and power factor
  • Power output and efficiency
  • Z'L (380j230) (N1 / N2)2
  • (380j230) (250/2500)2
  • 3.8j2.3
  • Total impedance in the primary
  • Secondary terminal voltage I2ZL

21
  • Im V1/jXm 250?0/250?90 1?-90 0-j1
  • I'e Ic Im 0.5 (0-j1) 0.5-j1
  • I'1 I'1 Ie 40- j300.5- j1 51?-37.4
  • b) Primary current I1 51A
  • Primary p.f cos?1 cos37.4 0.794
    lagging
  • (c) Load p.f
  • cos?2 380/ (38022302 ) 0.855
  • Power Output V2I2cos?2 222050.855
  • 9500 Watts
  • Power Output I'12RL 5023.8 9500 Watt
  • Core Loss ,PC v12 / RC Ic2 RC 0.520.2 500
    Watts
  • Power Input V1I1cos?1 250510.794 10123.5

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