Title: John A. Schreifels
1Chapter 9
- Ionic and Covalent Bonding
2Overview
- Ionic Bonds
- Describing Ionic Bonds
- Electron Configuration of Ions
- Ionic Radii
- Covalent Bonds
- Describing Covalent Bonds
- Polar Covalent Bonds Electronegativity
- Writing Lewis Electron-Dot Formulae
- Bond Length and Order
- Bond Energy
3IONIC BONDING
- Ionic bonds are electrically neutral groups that
are held together by the attraction arising from
the opposite charges of a cation and an anion. - Substances that have ionic bonds in a solid form
a salt having high melting point and high
crystallinity. - Bonding thought of as the result of the
combination of neutral atoms with transfer of one
or more electrons from one atom to the other.
4LEWIS SYMBOLS AND THE OCTET RULE
- It was observed that the electron configuration
of many substances after ion formation was that
of an inert gas ? octet rule. - Octet rule Main-group elements gain, lose, or
share in chemical bonding so that they attain a
valence octet (eight electrons in an atoms
valence shell). - E.g. The electron configuration of each reactant
in the formation of KCl gives - K is that of Ar
- Cl? is also that of Ar.
- The other electrons in the atom are not as
important in determining the reactivity of that
substance. - The octet rule is particularly important in
compounds involving nonmetals.
5Energy in Ionic Bonding
- When potassium and chlorine atoms approach each
other we have - K(g)? K(g) e? Ei 418 kJ
- Cl(g) e?? Cl?(g) Eea ?349 kJ
- K(g)Cl(g)? K(g) Cl?(g) ?E 69 kJ
- Positive ?E energy absorbed ? energetically not
allowed. - Driving force must be the formation of the
crystalline solid. - K(g) Cl?(g) ? KCl(s)
6Formation of Crystalline Lattice
- Energy of crystallization estimated from
Coulombs Law by - assuming ions are spheres.
- Use ionic radii to determine charge separation.
- rK 133x10?12 m rCl? 181x10?12 m
- d 133x10?12 m 181x10?12 m 314x10?12 m
- z1 z2 1.602x10?12 C(oulombs) actually one is
the negative of the other. - k 8.99x109 J?m/C2
- This is related to the negative of the lattice
energy, as discussed later.
7BORN-HABER CYCLE AND LATTICE ENERGIES
- Overall energetics for the formation of
crystalline solids can be determined from a
Born-Haber cycle that accounts for all of the
steps towards the formation of solid salts from
the elements. For the formation of KCl from its
elements we have - Net energy change of ?434 kJ/mol indicates
energetically favored. - Energy for the fifth step is the negative of the
- lattice energy energy required to break ionic
bonds and sublime (always positive). - E.g. Determine the lattice energy of BaCl2 if
the heat of sublimation of Ba is 150.9 kJ/mol and
the 1st and 2nd ionization energies are 502 and
966 kJ/mol, respectively. The heat for the
synthesis of BaCl2(s) from its elements is
?806.06 kJ/mol.
8Energy Level Diagram of Born Haber Cycle
9LATTICE ENERGIES AND PERIODICITY
- Lattice energy can also be determined from
Coulombs law - Directly proportional to charge on each ion.
- Inversely proportional to size of compound (sum
of ionic radii). - Table (right) presents the lattice energies for
alkali and alkaline earth ionic compounds. The
lattice energies - decrease for compounds of a particular cation
with atomic number of the anion. - decrease for compounds of a particular anion with
atomic number of the cation.
10Ionic Radii
- Ionic radius a measure of the size of a
spherical region around the nucleus of an atom
where electrons are most likely to reside. - Cation loses electrons from its valence shell.
Electrons from other valence shells are closer to
the nucleus. - Cation also has more protons than electrons which
adds to the pull on the remaining electrons and
decreases the radius.
- Anion has more electrons than protons the pull
of the nucleus is less per valence electron.
Also, the electron electron repulsion is
greater. These lead to larger radius for an
anion.
11Ionic Radii - Trends
- Ionic radii increase down any column because of
the addition of electron shells. - In general, across any period the cations
decrease in radius. When you reach the anions,
there is an abrupt increase in radius, and then
the radius again decreases.
12Ionic Radii - Isoelectronic Ions
- Isoelectronic substances have the same number of
electrons and electron configuration.
All have 18 electrons
- Largest radius ion with smallest number of
protons. - Smallest radius ion (atom) with largest number
of protons.
13The Covalent Bond
- Repulsive forces of the electrons offset by the
attractive forces between the electrons and the
two nuclei. - Most stable bond energy and bond distance
characterizes bonds between two atoms. - Strengths of Covalent Bonds
- Bonds form because their formation produces lower
energy state than when atoms are separated. - Breaking bonds increases the overall energy of
the system. Energy for breaking bonds has a
positive sign (negative means that energy is
given off). - H - H (g) ? 2H(g) DH 436 kJ.
- Ionic vs. Covalent Bonds
- Ionic compounds have high melting and boiling
points and tend to be crystalline - Covalently bound compounds tend to have lower
melting points since the attractive forces
between the molecules are relatively weak.
14Lewis Structures
- Lewis structure valence electrons represented by
dots and are placed where they would be in any
bonding that might exist. - Lewis structures of second row elements
- H2 BH3
- CH4 NH3
- H2O HF
- Each has 8 electrons around the central atom
thus we can predict the number of bonds that will
form from the position in the periodic table. - E.g. The structure of chlorine is
- Bonding electrons shared electrons.
- Non-bonding or lone pair unshared electrons
15Lewis Structures(contd)
- Octet can be filled by donation of electrons from
each atom or one atom can supply both electrons. - E.g. H NH3 ? . "co-ordinate covalent bond".
- E.g.2
- Multiple bonds may form as a result when the two
atoms forming the bond do not have enough
electrons. - OO
- N?N
- Multiple bonds are shorter and stronger than
single bonds because of the extra electrons
holding the two atoms together.
16Polar Bonds Electronegativity
- Electronegativity is a measure of the atoms
ability to gain or lose electrons. It is
directly related to its ionization tendency and
its ability to form the inert gas configuration.
Obtained by - where Ei ionization energy and Eea the
electron affiinity. - E.g. Li has a very low ionization energy and
electron affinity, while Cl has a both a high
ionization energy and high electron affinity.
Electronegativity will be high for Cl and low for
Li. - Fluorine has the highest electronegativity of
4.0. - Electronegativities (see Fig. 9.15)
- increase from bottom to top of periodic table and
- increase to a maximum towards the top right.
- Combination of elements with intermediate
electronegativities forms bonds that are
intermediate between covalent and ionic. - can provide an insight as to the type of bond
that would be expected. - Ionic bonds formed when ?? ? 2
- covalent bonds forms when ?? ? 1.
- Polar covalent forms when 1 ? ?? ? 2, the bonding
is "intermediate" between the two.
17Polar Bonds Electronegativity2
- E.g.1 Determine the polarity of the N H in
NH3. - E.g. 2 Predict the type of bond formed in CCl4.
- The magnitude of ?? indicates if electrons are
polarized around one element in preference to the
other. - Polar bond polar. With intermediate ??, a small
charge on the atom due to that bond develops. ?
and ?? designates which is the positive and
negative side respectively. - E.g.3 Determine the relative polarities of HF,
HCl, HBr and HI.
18Lewis Structures of Polyatomic Molecules
- Procedure for more complicated molecules
- Determine the total number of valence electrons
from each atom. - Distributed atoms around the central atom (least
electronegative. Hydrogen atoms are usually
attached to any oxygen. - Satisfy the octet of the atoms bonded to the
central atom. - Satisfy the octet of the central atom by
distributing the remaining electrons as electron
pairs around it. (multiple bonds may be
necessary) - E.g. Determine the Lewis structure of H2SO4.
- E.g. Draw the Lewis dot structures of NCl3, CSe2,
and CO.
19FORMAL CHARGES
- Formal Charge (of an atom in a Lewis formula) the
hypothetical charge obtained by assuming that
bonding electrons are equally shared between the
two atoms involved in the bond. Lone pair
electrons belong only to the atom to which they
are bound. - E.g. determine the formal charge on all
elements PCl3, PCl5, and HNO3. - formal charge (FC) allows the prediction of the
more likely resonance structure. - To determine the more likely resonance structure
- FC should be as close to zero as possible.
- Negative charge should reside on the most
electronegative and positive charge on the least
electronegative element. - E.g. draw the resonance structures of H2SO4
determine the formal charge on each element and
decide which is the most likely structure.
20Lewis Structures and Resonance
- Quantum theory indicates that any position
possible for an electron. - Equivalent electron positions often possible
- E.g. SO2 OS-O and O-SO.
- Each structure equally likely.
- the true form of the molecule is a hybrid of
these and is called resonance and the hybrid form
is called a resonance hybrid.
21Exceptions to the Octet Rule
- Although many molecules obey the octet rule,
there are exceptions where the central atom has
more than eight electrons. - Generally, if a nonmetal is in the third period
or greater it can accommodate as many as twelve
electrons, if it is the central atom. - These elements have unfilled d subshells that
can be used for bonding. - E.g determine the Lewis dot structure of XeF4,
ICl3, and SF4
22Bond Dissociation Enthalpies
- Bond dissociation energy, D the energy required
to break one mole of a type of bond in an
isolated molecule in the gas phase. - Useful for estimation of heat of unknown
reactions. - Average bond energies listed in tables (e.g. C
H bond) rest pf structure not very important - HO-H bond in H2O and CH3O-H bond are 492 and 435
kJ/mol. - Hesss law can be used with bond dissociation
energies to estimate the enthalpy change of a
reaction. The breaking in a C H bond would be C
H(g) ? C(g) H(g) ?H D 410 kJ. - Sign always positive since energy must be
supplied to break bond.
23Using Bond Dissociation Enthalpies
- E.g. Estimate the heat of formation of H2O(g)
from bond dissociation energies. Thus determine
- H2(g) ½ O2(g) ? H2O(g) ?
- From the book (Table 9.5)
- H H (g) ? 2H(g) ?H D1 436 kJ
- ½ OO ? O(g) ?H D2 494/2 247 kJ
- 2H(g) O(g) ? H O H (g) ?H ?2D3 ?2459
kJ - H2(g) ½ O2(g) ? H2O(g) ?235 kJ
- Actual ?241.8 kJ
- Can be determined by suming all the energies for
the bonds broken and subtract from if the sum of
the energies for the bonds formed. - E.g. 2 Estimate the energy change for the
chlorination of ethylene - CH2CH2(g) Cl2(g)? CH2ClCH2Cl
24Using Bond Dissociation Enthalpies
- It may be necessary to include a phase change
since many reactions or reactants are not in the
gas phase. - E.g. Determine the heat of formation of CCl4(l).
- Solution The reaction is
- C(gr) 2Cl2(g) ? CCl4(l) ?
- Write the reactions and sum energies
25Electronegativities
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26Return to Slide 23