Differentiability for Functions of Two Variables - PowerPoint PPT Presentation

About This Presentation
Title:

Differentiability for Functions of Two Variables

Description:

Differentiability for Functions of Two Variables Local Linearity What is meant by sufficiently nice ? Suppose we zoom in on the function z=f(x,y) centering our ... – PowerPoint PPT presentation

Number of Views:118
Avg rating:3.0/5.0
Slides: 12
Provided by: www2Kenyo
Learn more at: https://www2.kenyon.edu
Category:

less

Transcript and Presenter's Notes

Title: Differentiability for Functions of Two Variables


1
Differentiability for Functions of Two Variables
  • Local Linearity

2
Recall that when we zoom in on a sufficiently
nice function of two variables, we see a plane.
3
What is meant by sufficiently nice?
  • Suppose we zoom in on the function zf(x,y)
    centering our zoom on the point (a,b) and we see
    a plane. What can we say about the plane?
  • The partial derivatives for the plane at the
    point must be the same as the partial derivatives
    for the function.
  • Therefore, the equation for the tangent plane is

4
In particular. . .The Partial Derivatives Must
Exist
  • If the partial derivatives dont exist at the
    point (a,b), the function f cannot be locally
    planar at (a,b).

Example (as given in text) A cone with vertex
at the origin cannot be locally planar there, as
it is clear that the x and y cross sections are
not differentiable there.
5
Not enough A Puny Condition
Whoa! The existence of the partial derivatives
doesnt even guarantee continuity at the point!
Suppose we have a function
  • Notice several things
  • Both partial derivatives exist at x0.
  • The function is not locally planar at x0.
  • The function is not continuous at x0.

6
Directional Derivatives?
  • Its not even good enough for all of the
    directional derivatives to exist!
  • Just take a function that is a bunch of straight
    lines through the origin with random slopes. (One
    for each direction in the plane.)

7
Directional Derivatives?
  • Its not even good enough for all of the
    directional derivatives to exist!

Locally Planar at the origin? What do you think?
8
Directional Derivatives?
  • If you dont believe this is a function, just
    look at it from above.
  • Theres one output (z value) for each input
    (point (x,y)).

9
Differentiability
The function z f(x,y) is differentiable
(locally planar) at the point (a,b) if and
only if the partial derivatives of f exist and
are continuous in a small disk centered at (a,b).

10
Differentiability A precise definition
  • A function f(x,y) is said to be differentiable at
    the point (a,b) provided that there exist real
    numbers m and n and a function E(x,y) such that
    for all x and y
  • and

11
E(x) for One-Variable Functions
But E(x)?0 is not enough, even for functions of
one variable!
E(x) measures the vertical distance between f (x)
and Lp(x)
What happens to E(x) as x approaches p?
Write a Comment
User Comments (0)
About PowerShow.com