Title: APSTAT SECTION IV PROBABILITY
1APSTAT SECTION IVPROBABILITY
2CHAPTER 14From Justin To Kelly(or from
randomness to probability)
3Randomenss and Probability Basics
- What is Random?
- Individual outcomes are unpredictable in the
short run - In the long run, however, outcomes are regular
AND predictable (LOLN - Law of Large Numbers) - Lets do a simulation
- Flip 10, 100, 1000, 10000 coins
- Find of heads to nearest whole
- sum(randint(0,1,10))
4Random Simulation
- Short Run Long Run
- 10 Flips 100 Flips 999Flips
5What is Probability
- Over a HUGE number of trials (probability is
Long-Term), the proportion of times an outcome
would occur. - Typically expressed by P and a range from 0 to 1
- 0 being never ever happens
- 1 being always happens
- We can only ESTIMATE real-world probabilities
- Can be expressed as a , but not as cool.
6Models of Probability
- Two Main Thangs
- LIST all possible outcomes
- ASSIGN a probability to each outcome
- ie. Year in school probability _at_ WPS
FROSH SOPH JUNIOR SENIOR
60/230 60/230 70/230
40/230
P .261 .261 .304 .164
Should add up to 1.0, but may be a bit off due to
ROUNDING ERROR
7Vocab Time
- Sample Space S Set of all possible outcomes
- Event Any outcome or set of outcomes
- ie. Freshman
- ie. Juniors AND seniors
8CRAPS! Roll Them Bones!
- Disclaimer Gambling can be dangerous and
addictive, plus over the LONG RUN, the casino
always wins. So dont gamble, buy a casino! - Sample space when 2 die are rolled
36 potential outcomes
9CRAPS! Roll Them Bones!
- Event Rolling a 7 when pips are added
- ProbSpeak P(Roll a 7)
P(Roll 7) 6/36 .167
10CRAPS! Roll Them Bones!
- Event Rolling a 8 when pips are added
- ProbSpeak P(8)
P(8) 5/36 .139
11CRAPS! Roll Them Bones!
- Event Rolling a Hard 8 (two 4s)
- ProbSpeak P(Hard 8)
P(8) 1/36 .028
12More Sample Space
- Same problem can have different look at sample
space - If in craps, if all we care about are pips
- S (2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)
P(2) 1/36 .028
P(3) 2/36 .056
13Key Points -
- Independence
- One outcome does not affect another outcome
- ie. If I roll a 6 with one die, it wont affect
my chances of rolling a 6 with the second die - WITH Replacement
- Example pick a card from a deck, put it back and
pick anotherP(2 Aces) - WITHOUT Replacement
- Example pick two cards from a deck without
replacing the first cardP(2 Aces)
14Rules o Probability
- Probability of an event is between 0 and 1
- PROBSPEAK
- All possible probabilities add up to 1
- PROBSPEAK
- Probability of an event NOT happening is 1 minus
the probability of the event happening. The
probability of an event NOT happening is called
the COMPLIMENT of an event and is written Ac - PROBSPEAK
15Rules o Probability Continued
- If two events are disjoint (mutually exclusive),
they have no outcomes in common. For example, in
craps, rolling a 5 AND a 7 is disjoint, one roll
cant produce both outcomes. - Therefore (for disjoint events)
- AND (for disjoint events)..
S
A
B
16Rules o Probability Continued Again
- If two events are NOT disjoint (not mutually
exclusive) but ARE independent . For example,
roll 2 dice - Event A Die 1 Shows a 6 P(A)1/6
- Event B Die 2 Shows a 6 P(B)1/6
- P(A and B) P(A)P(B)
- 1/6 1/6 1/36 .028ish
S
A
AB
B
17Disjoint Events Are NOT Independent
- Hurting your brain?
- Just thinkIf I roll two die and add up the pips,
what are the chances that I get a 5 and a 7. - Thats why (in disjoint
- events)
- P(A and B)0
S
Roll 5
Roll 7
18CHAPTER 15Probability Goes Crazy with the Cheez
Whiz
19Tree Diagrams
OUTCOMES
- ie. Flip 3 Coins, Count of Heads
3H, 0T
H
H
2H, 1T
T
H
H
2H, 1T
T
T
1H, 2T
H
2H, 1T
H
T
1H, 2T
T
H
1H, 2T
T
FLIP 1
T
0H, 3T
FLIP 2
FLIP 3
203 Flip outcomes
3 Heads 2 Heads 1 Head 0 Heads
1/8 3/8 3/8
1/8
P .125 .375 .375 .125
21More (and evilererer) Probability Rules
- Addition Rule 3 or more disjoint events
S
A
C
B
22Addition Rule Non-Disjoint Events
- Find P(A or B)
- If I do P(A)P(B) the area AB gets counted twice
- To make it work, I do P(A) P(B) and then
subtract one P(AB)
S
A
AB
B
23Example P(Male Or Senior Citizen)
- P(Male)0.5
- P(65)0.2
- Assume independence for Maleness Oldness
S
A
AB
B
.5 .2 -
(.5)(.2) .7 - .1
.6
24Joint Events
- Not always independent - Cant assume
- Example Survey of music tastes at WPS
- Probability of student liking hip-hop (A)
- P(A)0.5
- Probability of student liking rap (B)
- P(B)0.4
- Think! Isnt there a decent chance that people
who like hip hop may be more likely to like rap
as well. - Proportion of students who like BOTH rap and hip
hop - P(A and B)0.3
25Joint Events - Continued
- Probability of student liking hip-hop (A)
- P(A)0.5
- Probability of student liking rap (B)
- P(B)0.4
- Proportion of students who like BOTH rap and hip
hop - P(A and B)0.3
S
HipHop
BOTH
0.1
0.2
0.3
RAP
0.4
26Joint Events Same thing Using a table
- Probability of student liking hip-hop (A)
- P(A)0.5
- Probability of student liking rap (B)
- P(B)0.4
- Proportion of students who like BOTH rap and hip
hop - P(A and B)0.3
Rap
0.2
Hip-Hop
0.4
0.5
0.1
0.6
S
HipHop
BOTH
0.1
0.2
0.3
RAP
0.4
27Conditional Probability
- Main Idea
- Probability can change if we know some other
event has occurred - World Poker Championships
- Flushes are good All same suit
- You get 2 cards that are secret, then 5 cards
are dealt for the community - You make the best 5-card hand you can
28World Poker Championships
- My Hand Community Cards
- ? ? ? ? ? ?
- Wow, Im close to a flush! What is the
probability that the last card (the river) is a
?? - Overall, the chance of a ? is 13/52 or .25, but
we already know what 6 cards are and that 4 of
them are ?s - Find Probability(? given that 4 of 6 visible
cards are ?s) - ProbSpeak P(Spade 4 of 6 visible spades)
- Think
?
29General Rule for Any Two Events
- P (A and B) P(A)P(B?A)
- Example
- Probability of getting 2 aces in two successive
draws (no replacement) - P(Ace on 1st and Ace on 2nd)
- P(Ace on 1st)P(Ace on 2nd ? Ace on 1st)
- 4/523/510.0045
- Notice if replacement (independence), the formula
still works since P(Ace on 2nd ? Ace on 1st)
P(Ace on 1st) - Therefore 4/524/520.0059
30Definition for Conditional Probability
- P (A and B) P(A)P(B?A)
- Take this old Formula and solve for P(B?A)
31Using Decision Trees
- The following information gives information on
DVD players sold by a certain electronics store - Let B1 Event that Brand 1 is purchased
- Let B2 Event that Brand 2 is purchased
- Let E Event that Warranty is purchased
- Therefore P(B1).7 P(B2).3
- AND!!!!!! P(E ? B1).2 P(E ? B2).4
32Using Decision Trees - Continued
- P(B1).7 P(B2).3 P(E ? B1).2 P(E ?
B2).4
(.7)(.2).14
(.7)(.8).56
(.3)(.4).12
(.3)(.6).18
33Using Decision Trees Continued 2
What proportion of DVD purchasers also purchased
the warranty? P(B1 and E) P(B2 and
E) P(E).14.12.26
(.7)(.2).14
(.7)(.8).56
(.3)(.4).12
(.3)(.6).18
34Using Decision Trees Bayess Rule
- What is probability of B1 given E
What proportion of DVD purchasers also purchased
the warranty?
(.7)(.2).14
P(B1 and E) .14 P(E).14.12.26
(.7)(.8).56
P(B1 ? E) .14/.26
P(B1 ? E) 0.539
(.3)(.4).12
(.3)(.6).18
35CHAPTER 16Random Variables
36Discrete Random Variables
- Discrete????
- Just means that there are a reasonable
(countable) number of options. - What do we do with them? List outcomes and then
probabilities - Answer questions
- Easy as pie
37Example Rolling 2 dice
- Find P(Xgt9) P(10)P(11)P(12).083.055.027
.165
- Find P(X?9) P(9)P(10)P(11)P(12)
- .121.083.055.027 .286
- Find P(5ltXlt8) P(6)P(7).139.167 .316
Really bad Histogram Thanks Microsoft!
38Continuous Random Variables
- Continuous?
- Not countable
- Example, think of all possible decimals between 0
and 1Boy thats a lot! - If we threw down a histogram of a gazillion
random numbers between 0 and 1, wed get this
Density Curve Area underneath is 1.0
Uniform Distribution
1.0
0.0
39Find Probabilities (Just area of rectangle)
1.0
0.8
0.0
0.2
40Find Probabilities (Just area of rectangle)
1.0
0.8
0.2
0.0
0.6
41Check this out!
- What is the probability P(X0.8)?
1.0
0.8
0.0
0! ZERO! ZIP! NADA!
Why? Area of a straight line is Zero, Yeah?
42SO
- P(Xgt0.8) is the same as P(X?0.8)
- With Continuous Variables, It does not matter
which one you use - Cool, Huh???
1.0
0.8
0.0
43Whats the sassiest density curve?
- NORMAL DISTRIBUTION. YEAH!!!
44Male Height N(68,2)
- Let XHt in Inches
- Find P(Xgt71)
- Normalcdf(71,100000000,68,2)
- P(Xgt71)_____
45Means and Variances of Random Variables
- Example 2005 AP Stat Scores
Remember x-bar is a sample mean, but we are
talking about the entire population of AP Stat
test takers, so we must use m (population mean).
mx 1(.13)2(.23)3(.25)4(.19)5(.20) 3.1
46Variances of Random Variables
- Recall Variance is (Standard Deviation)2
- Here is the formula, It looks icky, but its
pretty easy to use
Outcome Value
Sum
Variance of X
Mean of outcomes
Outcome Probability
47Means and Variances of Random Variables
mx 3.1
1.7903
Standard deviation would be the square root of
this. 1.31ish
48Law of Large Numbers
- How can we find the actual m of mens heights?
- Not really realistic to measure every man in the
world - Use x-bar as a reasonable estimate
- Gets more reasonable as the sample size increases
Thats the LAW OF LARGE NUMBERS. - The larger the sample size, the more likely x-bar
will approach the m.
49Rules for Means
- If I taught in Canada, they would not dig the
average height of males in inches, they like
centimeters. Plus, all men there measure their
heights while wearing 8cm high pumps. Very
stylish! - How does that change the mean???
50Rules for Means
- Here is the rule
- Here is what we do with those Canadian heights
(1in?2.54cm)
51Rules for Means 2
- In volleyball there are two main blocking
statistics, solo blocks (by self) and assisted
blocks (with a buddy). If Chrissa Trudelle
averaged .5 solo blocks and 1.3 assisted blocks
per match, how many total blocks did she average? - Rule
- DO IT!
52Rules For Variances
- OK, the last rule was ridiculously easy, but this
next stuff is a bit rough. - Think about the mens height and the changes in
Canada with the centimeters and 8cm pumps. - How would these change the variance?
53Rules For Variances
- If we add the same value (8cm) to every height,
how does variance (and standard deviation) change?
- Right, variance does not change if I add the same
value to each height
54Rules For Variances
- If we multiply each observation by the same
amount what will that do?
- Right, multiplying the variance by a factor will
change the variance. Greater if gt1 or if lt-1.
Less if between 1 and -1
55Rules For Variances Linear Transform
- If given N(68,2) for average male height, and we
transform it again with 82.5X, what happens to
the variance? - Rule
- DO IT!
Standard deviation would be the square root of
this. 5
56Rules For Variances Add/Subtract
p (rho) is like r, it shows the correlation
between X and Y and is between -1 and 1. Should
be stated unless X and Y are independent
Dont these look familiar???
57Check this out
- Rearrange the formulas a bit..
Perfect square trinomials???
58Speaking of Rho
- That little p only affects things if there is
some correlation between the variables - If the problem lists a rho, you gotta use it
- If it doesnt list a rho, but it should have, do
the problem without it, but talk about how there
could be some correlation which would affect the
variance (or standard deviation) - If no correlation p 0. Therefore
59Lets use it now!
- Coach Boff sweeps the gym floor in N(10,2)
minutes and mops the floor in N(15,3) minutes.
Assume that the time sweeping and mopping are
independent. Find the mean and standard
deviation of the combined time. - Mean is easy. 1015 25 minutes
- Now lets find the standard deviation
60Lets use it now!
REMEMBER! You can not add standard deviations,
you must square them to get variances, add the
variances and then square root the sum!
61But if X and Y had p .5
Why more? If rho is positive, X more likely to
be higher if Y is also higher. Variation moving
in the same way will increase the variance.
62Now you try!
- Mr. Riebhoff and Mr. Marsheck are the nations
1030th best partner biathlon team. Mr. Riebhoff
will do the running leg which is a 10k road race
where he has historically had a time of N(48,5)
in minutes. Marsheck will do the bike ride of
50k where he has historically had a time of
N(106, 10) in minutes. What are the mean and
standard deviation of their combined finish times?
63Remember
- Show formula(ae) first
- Talk about any assumptions you are making
- Dont forget that standard deviation is the
square root of variance - Have fun!
64CHAPTER 17Probability Models
65Binomial Distribution
- 4 Requirements for a Binomial Distribution
- 2 outcomes Success/Failure
- I.e. Heads or Tails, Boy or Girl Baby, Make or
Miss a Shot - Independent observations
- Probability does not change when you learn the
result of a previous event - Probability for success (p) is constant for all
observations - FIXED NUMBER OF OBSERVATIONS!!!!!!!!!
- 5 Free throws, 17 exam questions, 20 Students
THE KEY
66Important parts
- n of Observations
- Fixed for a binomial distribution
- p Probability of success
- Defined by you or the question
- x of successes
- Can be from 0 to n
67Do you remember
- Normal Distribution
- N(m,s) ex. N(68,2)
- NOW! Binomial Distribution
- B(n,p)
- Example
- A 70 free throw shooter shoots
- 10 Free throws
- B(10,0.7)
68Which of these would be Binomial?
- Flip a fair coin and count number of flips until
a head appears. - 350 students at WPS. 10 are 6th graders.
Choose 10 names at random with no replacement and
count of 6th graders. - Shaq is a 52 free throw shooter. Observe next
10 free throws and count of makes.
69Binomial PDF
- Remember Normal CDF?
- NOW Binomial PDF
Cumulative Distribution Function
Probability Distribution Function
70Binomial PDF 10 FT _at_ 70
.3
.2
.1
0 1 2 3 4
5 6 7 8 9
10
Binompdf(10,0.7,0)
Binompdf(10,0.7,1)
71Cumulative Distribution Function
- Cumulative
- It accumulates, adds up
- EXAMPLE 70 FT Shooter, 10 FTs
X
PDF
CDF
72Graph the CDF
1.0
.75
.50
.25
0 1 2 3 4
5 6 7 8 9
10
73Formulae for Binomial Distribution
- Mean For Binomial Distribution
- m np
- Makes sense yeah?
- Example, I flip a coin 16 times, how many heads?
- m 16(.5) 8
74Formulae for Binomial Distribution
- Standard Deviation For Binomial Distribution
- s
- Why? Sausage. Just deal and know where it is on
the Formulae Sheet. - Ex. Find SD of 10 FT Problem
- s
- s 1.449
75LETS DO IT!
- Find Mean and Standard Deviation on 20 Free
Throws if - p0.7
- p0.8
- p0.9
- p0.99
- What happens to m as p approaches 1.0?
76Math Attack
- Remember Factorials? -- n!
- Examples
- 5! 54321 120
- 3! 321 6
- Now the crazy stuff
- 0! 1
- Kinda Like a0 1, yah?
- Well need these in a minute, youll see why.
77Binomial Coefficient
- of ways I can get k successes in n tries.
- Example How many ways can I get three tails in
5 flips? - Old Skool Way (easy to mess up)
- TTTHH TTHTH TTHHT THTTH
- THTHT THHTT HTHTT HTTTH
- HTTHT HHTTT
78Impress your friends at the next math party way
- Pascals Triangle
- 1
- 1 1
- 1 2 1
- 1 3 3 1
- 1 4 6 4 1
- 1 5 10 10 5 1
5 Choose 0
5 Choose 1
5 Choose 2
5 Choose 3
79Formula Way
- Formula
- Use it! 5 Choose 3
n choose k
80Binomial Probability
- Recall 3 coins flipped, X of Heads
X 0 1 2 3 1
3 3 1
P(X0) 1P(HC)3 .125
P(X1) 3P(HC)2 P(H) .375
P(X2) 3P(H)2 P(HC) .375
P(X3) 1P(H)3 .125
81Imagine doing P(5 heads in 9 flips)
- What we need is a formula
Insert binomial coefficient here
82Lets do 3 flips P(2 heads)
83Now You Try!
- In a previous chapter, we found that the
probability of rolling a 7 (craps!) with two fair
die is 0.167. Let X be the number of 7s rolled
in a series of 10 rolls
84Now You Try!
- 1 Find the probability that 3 7s will be
rolled in the 10 attempts
85Now You Try!
- 2 Use your TI-83 and find the distribution of
X - binompdf(trials,p,x)
- 0 1 2 3 4 5 6 7 8
9 10
86Now You Try!
- 3 Find the m and s of the number of 7s that
would be rolled in 10 attempts - m
- s
87Geometric Distribution
- 4 Requirements for a Geometric Distribution
- 2 outcomes Success/Failure
- I.e. Heads or Tails, Boy or Girl Baby, Make or
Miss a Shot - Independent observations
- Probability does not change when you learn the
result of a previous event - Probability for success (p) is constant for all
observations - Looking for of trials needed for 1
success!!!!!!! - Flip a coin, how many flips until 1st Head?
THE KEY
88Geometric vs. Binomial
- Binomial
- Shoot 10 FTs with p(make)0.7 find p(8 makes)
- Geometric
- With p(make) 0.7, Shoot until 1st make, count
the number of attempts
89Identify the Geometric Distributions
- A Flip a coin until you get a head
- B Record the number of times a player makes
both shots in a one-and-one foul-shooting
situation. (In this situation, you get to
attempt a second shot only if you make the first) - C Draw a card from the deck, observe it and
replace it into the deck. Count the number of
times you draw a card in this manner until you
observe a jack.
90Identify the Geometric Distributions
- D Buy a pick 6 lottery ticket every week
until you win the lottery. Count the of weeks
it takes for you to win. - E There are 10 red marbles and 5 blue marbles
in a jar. You reach in, and without looking,
select a marble. You want to know how many
marbles you need to draw (without replacement),
on average, in order to be sure that you have 3
red marbles.
91CRAPS! Roll till a 7 shows up
FORMULA FOR GEOMETRIC PROBABILITIES
92Lets try it!
- Mr. Riebhoff is U-G-L-Y (he aint got no alibi).
In college, he had only a 20 chance of a
randomly selected woman (he used a random
table) agreeing to meet him for a soda.
93Lets try it!
- 1 Find a probability distribution from x
1 to x 5 that shows x the of females he
would ask before getting a yes - 1 2 3 4 5
94Lets try it!
- 2 Make a CDF of the data from 1
- 1 2 3 4 5
1.0
0.0
95Lets try it!
- 3 What is the probability that after 5 girls
asked, Riebhoff would still be dateless?
96Using the TI-83
- geometpdf(p,x)
- In Riebhoff Date Example
- geometpdf(0.2,1)
- geometpdf(0.2,2)
- geometpdf(0.2,3)
- geometpdf(0.2,4)
Number if trials till success
97Mean of Geometric Random Variable
- Common Sense
- Guess what the mean number of rolls I would need
to roll a 5 on a fair die? - Guess the mean number of flips I would need to
get a head on a fair coin? - m 1/p