Title: ENVIRONMENTAL ENGINEERING CONCRETE STRUCTURES
1ENVIRONMENTAL ENGINEERING CONCRETE STRUCTURES
- CE 498 Design Project
- November 16, 21, 2006
2OUTLINE
- INTRODUCTION
- LOADING CONDITIONS
- DESIGN METHOD
- WALL THICKNESS
- REINFORCEMENT
- CRACK CONTROL
3INTRODUCTION
- Conventionally reinforced circular concrete tanks
have been used extensively. They will be the
focus of our lecture today - Structural design must focus on both the strength
and serviceability. The tank must withstand
applied loads without cracks that would permit
leakage. - This is achieved by
- Providing proper reinforcement and distribution
- Proper spacing and detailing of construction
joints - Use of quality concrete placed using proper
construction procedures - A thorough review of the latest report by ACI 350
is important for understanding the design of
tanks.
4LOADING CONDITIONS
- The tank must be designed to withstand the loads
that it will be subjected to during many years of
use. Additionally, the loads during construction
must also be considered. - Loading conditions for partially buried tank.
- The tank must be designed and detailed to
withstand the forces from each of these loading
conditions
5LOADING CONDITIONS
- The tank may also be subjected to uplift forces
from hydrostatic pressure at the bottom when
empty. - It is important to consider all possible loading
conditions on the structure. - Full effects of the soil loads and water pressure
must be designed for without using them to
minimize the effects of each other. - The effects of water table must be considered for
the design loading conditions.
6DESIGN METHODS
- Two approaches exist for the design of RC members
- Strength design, and allowable stress design.
- Strength design is the most commonly adopted
procedure for conventional buildings - The use of strength design was considered
inappropriate due to the lack of reliable
assessment of crack widths at service loads. - Advances in this area of knowledge in the last
two decades has led to the acceptance of strength
design methods - The recommendations for strength design suggest
inflated load factors to control service load
crack widths in the range of 0.004 0.008 in.
7Design Methods
- Service state analyses of RC structures should
include computations of crack widths and their
long term effects on the structure durability and
functional performance. - The current approach for RC design include
computations done by a modified form of elastic
analysis for composite reinforced steel/concrete
systems. - The effects of creep, shrinkage, volume changes,
and temperature are well known at service level - The computed stresses serve as the indices of
performance of the structure.
8DESIGN METHODS
- The load combinations to determine the required
strength (U) are given in ACI 318. ACI 350
requires two modifications - Modification 1 the load factor for lateral
liquid pressure is taken as 1.7 rather than 1.4.
This may be over conservative due to the fact
that tanks are filled to the top only during leak
testing or accidental overflow - Modification 2 The members must be designed to
meet the required strength. The ACI required
strength U must be increased by multiplying with
a sanitary coefficient - The increased design loads provide more
conservative design with less cracking. - Required strength Sanitary coefficient X U
- Where, sanitary coefficient 1.3 for flexure,
1.65 for direct tension, and 1.3 for shear beyond
the capacity provided by the concrete.
9WALL THICKNESS
- The walls of circular tanks are subjected to ring
or hoop tension due to the internal pressure and
restraint to concrete shrinkage. - Any significant cracking in the tank is
unacceptable. - The tensile stress in the concrete (due to ring
tension from pressure and shrinkage) has to kept
at a minimum to prevent excessive cracking. - The concrete tension strength will be assumed 10
fc in this document. - RC walls 10 ft. or higher shall have a minimum
thickness of 12 in. - The concrete wall thickness will be calculated as
follows
10WALL THICKNESS
- Effects of shrinkage
- Figure 2(a) shows a block of concrete with a
re-bar. The block height is 1 ft, t corresponds
to the wall thickness, the steel area is As, and
the steel percentage is r. - Figure 2(b) shows the behavior of the block
assuming that the re-bar is absent. The block
will shorten due to shrinkage. C is the shrinkage
per unit length. - Figure 2(c) shows the behavior of the block when
the re-bar is present. The re-bar restrains some
shortening. - The difference in length between Fig.2(b) and
2(c) is xC, an unknown quantity.
11WALL THICKNESS
- The re-bar restrains shrinkage of the concrete.
As a result, the concrete is subjected to
tension, the re-bar to compression, but the
section is in force equilibrium - Concrete tensile stress is fcs xCEc
- Steel compressive stress is fss (1-x)CEs
- Section force equilibrium. So, rfssfcs
- Solve for x from above equation for force
equilibrium - The resulting stresses are
- fssCEs1/(1nr) and fcsCEsr/(1nr)
- The concrete stress due to an applied ring or
hoop tension of T will be equal to - T Ec/(EcAcEsAs) T 1/AcnAs
T/Ac(1nr) - The total concrete tension stress CEsAs
T/AcnAs
12WALL THICKNESS
- The usual procedure in tank design is to provide
horizontal steel As for all the ring tension at
an allowable stress fs as though designing for a
cracked section. - Assume AsT/fs and realize Ac12t
- Substitute in equation on previous slide to
calculate tension stress in the concrete. - Limit the max. concrete tension stress to fc
0.1 fc - Then, the wall thickness can be calculated as
- t CEsfsnfc/12fcfs T
- This formula can be used to estimate the wall
thickness - The values of C, coefficient of shrinkage for RC
is in the range of 0.0002 to 0.0004. - Use the value of C0.0003
- Assume fs allowable steel tension 18000 psi
- Therefore, wall thickness t0.0003 T
13WALL THICKNESS
- The allowable steel stress fs should not be made
too small. Low fs will actually tend to increase
the concrete stress and potential cracking. - For example, the concrete stress fc
CEsfs/AcfsnTT - For the case of T24,000 lb, n8, Es29106 psi,
C0.0003 and Ac12 x 10 120 in3 - If the allowable steel stress is reduced from
20,000 psi to 10,000 psi, the resulting concrete
stress is increased from 266 psi to 322 psi. - Desirable to use a higher allowable steel stress.
14REINFORCEMENT
- The amount size and spacing of reinforcement has
a great effect on the extent of cracking. - The amount must be sufficient for strength and
serviceability including temperature and
shrinkage effects - The amount of temperature and shrinkage
reinforcement is dependent on the length between
construction joints
15REINFORCEMENT
- The size of re-bars should be chosen recognizing
that cracking can be better controlled by using
larger number of small diameter bars rather than
fewer large diameter bars - The size of reinforcing bars should not exceed
11. Spacing of re-bars should be limited to a
maximum of 12 in. Concrete cover should be at
least 2 in. - In circular tanks the locations of horizontal
splices should be staggered by not less than one
lap length or 3 ft. - Reinforcement splices should confirm to ACI 318
- Chapter 12 of ACI 318 for determining splice
lengths. - The length depends on the class of splice, clear
cover, clear distance between adjacent bars, and
the size of the bar, concrete used, bar coating
etc.
16CRACK CONTROL
- Crack widths must be minimized in tank walls to
prevent leakage and corrosion of reinforcement - A criterion for flexural crack width is provided
in ACI 318. This is based on the Gergely-Lutz
equation zfs(dcA)1/3 - Where z quantity limiting distribution of
flexural re-bar - dc concrete cover measured from extreme tension
fiber to center of bar located closest. - A effective tension area of concrete
surrounding the flexural tension reinforcement
having the same centroid as the reinforcement,
divided by the number of bars.
17CRACK CONTROL
- In ACI 350, the cover is taken equal to 2.0 in.
for any cover greater than 2.0 in. - Rearranging the equation and solving for the
maximum bar spacing give max spacing z3/(2 dc2
fs3) - Using the limiting value of z given by ACI 350,
the maximum bar spacing can be computed - For ACI 350, z has a limiting value of 115 k/in.
- For severe environmental exposures, z 95 k/in.
18ANALYSIS OF VARIOUS TANKS
- Wall with fixed base and free top triangular
load - Wall with hinged base and free top triangular
load and trapezoidal load - Wall with shear applied at top
- Wall with shear applied at base
- Wall with moment applied at top
- Wall with moment applied at base
19CIRCULAR TANK ANALYSIS
- In practice, it would be rare that a base would
be fixed against rotation and such an assumption
would lead to an improperly designed wall. - For the tank structure, assume
- Height H 20 ft.
- Diameter of inside D 54 ft.
- Weight of liquid w 62.5 lb/ft3
- Shrinkage coefficient C 0.0003
- Elasticity of steel Es 29 x 106 psi
- Ratio of Es/Ec n 8
- Concrete compressive strength fc 4000 psi
- Yield strength of reinforcement fy 60,000 psi
20CIRCULAR TANK ANALYSIS
- It is difficult to predict the behavior of the
subgrade and its effect upon restraint at the
base. But, it is more reasonable to assume that
the base is hinged rather than fixed, which
results in more conservative design. - For a wall with a hinged base and free top, the
coefficients to determine the ring tension,
moments, and shears in the tank wall are shown in
Tables A-5, A-7, and A-12 of the Appendix - Each of these tables, presents the results as
functions of H2/Dt, which is a parameter. - The values of thickness t cannot be calculated
till the ring tension T is calculated. - Assume, thickness t 10 in.
- Therefore, H2/Dt (202)/(54 x 10/12) 8.89
(approx. 9 in.)
21Table A-5 showing the ring tension values
22Table A-7, A-12 showing the moment and shear
23CIRCULAR TANK ANALYSIS
- In these tables, 0.0 H corresponds to the top of
the tank, and 1.0 H corresponds to the bottom of
the tank. - The ring tension per foot of height is computed
by multiplying wu HR by the coefficients in Table
A-5 for the values of H2/Dt9.0 - wu for the case of ring tension is computed as
- wu sanitary coefficient x (1.7 x Lateral
Forces)wu 1.65 x (1.7 x 62.5) 175.3 lb/ft3 - Therefore, wu HR 175.3 x 20 x 54/2 94, 662
lb/ft3 - The value of wu HR corresponds to the behavior
where the base is free to slide. Since, it cannot
do that, the value of wu HR must be multiplied by
coefficients from Table A-5
24CIRCULAR TANK ANALYSIS
- A plus sign indicates tension, so there is a
slight compression at the top, but it is very
small. - The ring tension is zero at the base since it is
assumed that the base has no radial displacement - Figure compares the ring tension for tanks with
free sliding base, fixed base, and hinged base.
25CIRCULAR TANK ANALYSIS
- Which case is conservative? (Fixed or hinged
base) - The amount of ring steel required is given by
- As maximum ring tension / (0.9 Fy)
- As 67494/(0.9 60000) 1.25 in2/ft.
- Therefore at 0.7H use 6bars spaced at 8 in. on
center in two curtains. - Resulting As 1.32in2/ft.
- The reinforcement along the height of the wall
can be determined similarly, but it is better to
have the same bar and spacing. - Concrete cracking check
- The maximum tensile stress in the concrete under
service loads including the effects of shrinkage
is - fc CEsAs Tmax, unfactored/AcnAs 272
psi lt 400 psi - Therefore, adequate
26CIRCULAR TANK ANALYSIS
- The moments in vertical wall strips that are
considered 1 ft. wide are computed by multiplying
wuH3 by the coefficients from table A-7. - The value of wu for flexure sanitary
coefficient x (1.7 x lateral forces) - Therefore, wu 1.3 x 1.7 x 62.5 138.1 lb/ft3
- Therefore wuH3 138.1 x 203 1,104,800 ft-lb/ft
- The computed moments along the height are shown
in the Table. - The figure includes the moment for both the
hinged and fix conditions
27CIRCULAR TANK ANALYSIS
- The actual restraint is somewhere in between
fixed and hinged, but probably closer to hinged. - For the exterior face, the hinged condition
provides a conservative although not wasteful
design - Depending on the fixity of the base, reinforcing
may be required to resist moment on the interior
face at the lower portion of the wall. - The required reinforcement for the outside face
of the wall for a maximum moment of 5,524
ft-lb/ft. is - Mu/(f fc bd2) 0.0273 (where d t cover
dbar/2) - From the standard design aid of Appendix A, take
the value of 0.0273 and obtain a value for w from
the Table. - Obtain w0.0278
- Required As w bdfc/fy 0.167 in2
28CIRCULAR TANK ANALYSIS
- r0.167/(12 x 7.5) 0.00189
- rmin 200/Fy 0.0033 gt 0.00189
- Use 5 bars at the maximum allowable spacing of
12 in. - As 0.31 in2 and r 0.0035
- The shear capacity of a 10 in. wall with fc4000
psi is - Vc 2 (fc)0.5 bwd 11,384 kips
- Therefore, f Vc 0.85 x 11,284 9676 kips
- The applied shear is given by multiplying wu H2
with the coefficient from Table A-12 - The value of wu is determined with sanitary
coefficient 1.0 (assuming that no steel rft.
will be needed) - wuH2 1.0 x 1.7 x 62.5 x 202 42,520 kips
- Applied shear Vu 0.092 x wuH2 3912 kips lt
fVc
29RECTANGULAR TANK DESIGN
- The cylindrical shape is structurally best suited
for tank construction, but rectangular tanks are
frequently preferred for specific purposes - Rectangular tanks can be used instead of circular
tanks when the footprint needs to be reduced - Rectangular tanks are used where partitions or
tanks with more than one cell are needed. - The behavior of rectangular tanks is different
from the behavior of circular tanks - The behavior of circular tanks is axisymmetric.
That is the reason for our analysis of only unit
width of the tank - The ring tension in circular tanks was uniform
around the circumference
30RECTANGULAR TANK DESIGN
- The design of rectangular tanks is very similar
in concept to the design of circular tanks - The loading combinations are the same. The
modifications for the liquid pressure loading
factor and the sanitary coefficient are the same.
- The major differences are the calculated moments,
shears, and tensions in the rectangular tank
walls. - The requirements for durability are the same for
rectangular and circular tanks. This is related
to crack width control, which is achieved using
the Gergely Lutz parameter z. - The requirements for reinforcement (minimum or
otherwise) are very similar to those for circular
tanks. - The loading conditions that must be considered
for the design are similar to those for circular
tanks.
31RECTANGULAR TANK DESIGN
- The restraint condition at the base is needed to
determine deflection, shears and bending moments
for loading conditions. - Base restraint conditions considered in the
publication include both hinged and fixed edges. - However, in reality, neither of these two
extremes actually exist. - It is important that the designer understand the
degree of restraint provided by the reinforcing
that extends into the footing from the tank wall.
- If the designer is unsure, both extremes should
be investigated. - Buoyancy Forces must be considered in the design
process - The lifting force of the water pressure is
resisted by the weight of the tank and the weight
of soil on top of the slab
32RECTANGULAR TANK BEHAVIOR
Mx moment per unit width about the x-axis
stretching the fibers in the y direction when the
plate is in the x-y plane. This moment determines
the steel in the y (vertical direction).
My moment per unit width about the y-axis
stretching the fibers in the x direction when the
plate is in the x-y plane. This moment determines
the steel in the x (horizontal direction).
Mz moment per unit width about the z-axis
stretching the fibers in the y direction when the
plate is in the y-z plane. This moment determines
the steel in the y (vertical direction).
33RECTANGULAR TANK BEHAVIOR
- Mxy or Myz torsion or twisting moments for
plate or wall in the x-y and y-z planes,
respectively. - All these moments can be computed using the
equations - Mx(Mx Coeff.) x q a2/1000
- My(My Coeff.) x q a2/1000
- Mz(Mz Coeff.) x q a2/1000
- Mxy(Mxy Coeff.) x q a2/1000
- Myz(Myz Coeff.) x q a2/1000
- These coefficients are presented in Tables 2 and
3 for rectangular tanks - The shear in one wall becomes axial tension in
the adjacent wall. Follow force equilibrium -
explain in class.
34RECTANGULAR TANK BEHAVIOR
- The twisting moment effects such as Mxy may be
used to add to the effects of orthogonal moments
Mx and My for the purpose of determining the
steel reinforcement - The Principal of Minimum Resistance may be used
for determining the equivalent orthogonal moments
for design - Where positive moments produce tension
- Mtx Mx Mxy
- Mty My Mxy
- However, if the calculated Mtx lt 0,
- then Mtx0 and MtyMy Mxy2/Mx gt 0
- If the calculated Mty lt 0
- Then Mty 0 and Mtx Mx Mxy2/My gt 0
- Similar equations for where negative moments
produce tension