Title: Modern Physics Light as a Particle Quantum Physics Physics
1Modern Physics
2Quantum Physics
- Physics on a very small scale is quantized.
- Quantized phenomena are discontinuous and
discrete. - Atoms can absorb and emit energy, but the energy
intervals are very tiny, and not all energy
levels are allowed for a given atom.
3Quantum physics centers on light
Visible spectrum
Electromagnetic spectrum
4Light is a ray
- We know from geometric optics that light behaves
as a ray. - This means it travels in a straight line.
- When we study ray optics, we ignore the nature of
light, and focus on how it behaves when it hits a
boundary and reflects or refracts at that
boundary.
5But light is also a wave!
- We will study the wave nature of light in more
depth later in the year. - In quantum optics, we use one equation from wave
optics. - c lf
- c 3 x 108m/s (the speed of light in a vacuum)
- l wavelength (m) (distance from crest to crest)
- f frequency (Hz or s-1)
6And light behaves as a particle!
- Light has a dual nature.
- In addition to behaving as a wave, it also
behaves like a particle. - It has energy and momentum, just like particles
do. - Particle behavior is pronounced on a very small
level. - A particle of light is called a photon.
7Calculating photon energy
- The energy of a photon is calculated from it the
frequency of the light. - E hf
- E energy (J or eV)
- h Plancks constant
- 6.625?10-34 J s
- 4.14 ?10-15 eV s
- f frequency of light (s-1, Hz)
8Conceptual checkpoint
- Which has more energy in its photons, a very
bright, powerful red laser or a small key-ring
red laser? - Neither! They both have the same energy per
photon. The big one has more power. - Which has more energy in its photons, a red laser
or a green laser? - The green one has shorter wavelength and higher
frequency. It has more energy per photon.
9The electron-volt (eV)
- The electron-volt is the most useful unit on the
atomic level. - If a moving electron is stopped by 1 V of
electric potential, we say it has 1 electron-volt
(or 1 eV) of kinetic energy. - 1 eV 1.602?10-19 J
10Sample Problem (similar to 30.10)
- What is the frequency and wavelength of a photon
whose energy is 4.0 x 10-19J?
11Solution
- E hf
- 4.0 x 10-19 J (6.625 x 10-34 J s) f
- f 6.04 x 1014 /s (or s-1 or Hz)
- c lf
- 3.00 x 108 m/s l(6.04 x 1014/s)
- l 4.97 x 10-7m 497 nm
12Sample Problem
- The bonding energy of H2 is 104.2 kcal/mol.
Determine the frequency and wavelength of a
photon that could split one atom of H2 into two
separate atoms. (1 kcal 4186 J).
13Solution
- Convert energy from kcal/mole to joules/molecule
- E (104.2)(4186)/6.02x1023) J/molecule
- E 7.2455 x 10-19 J
- Now find frequency and wavelength as in previous
problem - E hf
- 7.2455 x 10-19 J (6.625 x 10-34 J s) f
- f 1.09 x 1015 /s (or s-1 or Hz)
- c lf
- 3.00 x 108 m/s l(1.09 x 1015 )
- l 2.74 x 10-7m 274 nm
14Sample Problem
- How many photons are emitted per second by a
He-Ne laser that emits 3.0 mW of power at a
wavelength of 632.8 nm?
15Solution
- Find total energy in one second from power
- P W/t Etot/t
- Etot P t 3.0 x 10-3 J
- Now see how many photons, n, will produce this
energy - E hf (one photon)
- Etot n hf (for n photons)
- E n hc/l (since wavelength is given and not
frequency) - 3.0 x 10-3
- n (6.625 x 10-34 J s) (3.0 x 108 m/s) /
632.8 x 10-9 m - n 9.55 x 1015
16Quantized atomic energy levels
- This graph shows allowed quantized energy levels
in a hypothetical atom. - More stable states are those in which the atom
has lower energy. - The more negative the state, the more stable the
atom.
17Quantized atomic energy levels
- The highest allowed energy is 0.0 eV. Above this
level, the atom loses its electron. This level is
called the ionization or dissociation level. - The lowest allowed energy is called the ground
state. This is where the atom is most stable. - States between the highest and lowest state are
called excited states.
18Quantized atomic energy levels
- Transitions of the electron within the atom must
occur from one allowed energy level to another. - The atom CANNOT EXIST between energy levels.
19Absorption of photon by atom
- When a photon of light is absorbed by an atom, it
causes an increase in the energy of the atom. - The photon disappears.
- The energy of the atom increases by exactly the
amount of energy contained in the photon. - The photon can be absorbed ONLY if it can produce
an allowed energy increase in the atom.
20Absorption of photon by atom
- When a photon is absorbed, it excites the atom to
higher quantum energy state. - The increase in energy of the atom is given by DE
hf.
Ground state
21Absorption Spectrum
- When an atom absorbs photons, it removes the
photons from the white light striking the atom,
resulting in dark bands in the spectrum. - Therefore, a spectrum with dark bands in it is
called an absorption spectrum.
22Absorption Spectrum
- Absorption spectra always involve atoms going up
in energy level.
23Emission of photon by atom
- When a photon of light is emitted by an atom, it
causes a decrease in the energy of the atom. - A photon of light is created.
- The energy of the atom decreases by exactly the
amount of energy contained in the photon that is
emitted. - The photon can be emitted ONLY if it can produce
an allowed energy decrease in an excited atom.
24Emission of photon by atom
- When a photon is emitted from an atom, the atom
drops to lower quantum energy state. - The drop in energy can be computed by DE hf.
Excited state
25Emission Spectrum
- When an atom emits photons, it glows! The photons
cause bright lines of light in a spectrum. - Therefore, a spectrum with bright bands in it is
called an emission spectrum.
26Emission of photon by atom
- Emission spectra always involve atoms going down
in energy level.
27Sample Problem
- What is the frequency and wavelength of the light
that will cause the atom shown to transition from
the ground state to the first excited state? - Draw the transition.
28Solution
- DE Ef - Ei
- -5.5 eV (-11.5 eV)
- 6.0 eV
- DE Ephoton hf
- f Ephoton /h
- 6.0 eV / 4.14x10-15 eV s
- 1.45 x 1015 Hz
- c fl
- l c/f
- 3.00 x 108 /1.45 x 1015
- 2.1 x 10-7 m 210 nm
29Sample Problem
- What is the longest wavelength of light that when
absorbed will cause the atom shown to ionize from
the ground state? - Draw the transition.
30Solution
- DE Ef - Ei
- 0 eV (-11.5 eV)
- 11.5 eV
- DE Ephoton hf hc/l
- l hc/ Ephoton
- (4.14 x 10-15)(3.00 x 108) /11.5
- 1.08 x 10-7 m 108 nm
31Sample Problem
- The atom shown is in the second excited state.
What frequencies of light are seen in its
emission spectrum? - Draw the transitions.
32Solution
- From second to ground
- Ephoton 8.5 eV
- f E/h
- 8.5 eV / 4.14x10-15 eV s
- 2.05 x 1015 Hz
- From second to first
- E 2.5 eV
- f E/h 6.04 x 1014 Hz
- From first to ground
- E 6.0 eV
- f E/h 1.45 x 1015 Hz
33Remember atoms can absorb photons
- Weve seen that if you shine light on atoms, they
can absorb photons and increase in energy. - The transition shown is the absorption of an 8.0
eV photon by this atom. - You can use Plancks equation to calculate the
frequency and wavelength of this photon.
Ionization level
0.0 eV
-4.0 eV
Ground state (lowest energy level)
-12.0 eV
34Photoelectric Effect
- Some photoactive metals can absorb photons that
not only ionize the metal, but give the electron
enough kinetic energy to escape from the atom and
travel away from it. - The electrons that escape are often called
photoelectrons.
e-
Ionization level
0.0 eV
-8.0 eV
- The binding energy or work function is the
energy necessary to promote the electron to the
ionization level. - The kinetic energy of the electron is the extra
energy provided by the photon.
Ground state (lowest energy level)
-12.0 eV
35Photoelectric Effect
- Photon Energy
- Work Function
- Kinetic Energy
- hf f Kmax
- Kmax hf f
- Kmax Kinetic energy of photoelectrons
- hf energy of the photon
- f binding energy or work function of the
metal.
e-
Ionization level
0.0 eV
-8.0 eV
Ground state (lowest energy level)
-12.0 eV
36Sample problem
- Suppose the maximum wavelength a photon can have
and still eject an electron from a metal is 340
nm. What is the work function of the metal
surface?
37Solution
- The longest wavelength is the lowest energy, and
will provide no extra kinetic energy for the
electron. - Kmax hf f
- f hf Kmax hc/l Kmax
- f 4.14E-153E8 / 340E-9 0
- f 3.7 eV
38Sample problem
- Zinc and cadmium have photoelectric work
functions given by WZn 4.33 eV and WCd 4.22
eV. - A) If illuminated with light of the same
frequency, which one gives photoelectrons with
the most kinetic energy? - B) Calculate the maximum kinetic energy of
photoelectrons from each surface for 275 nm light.
39Solution
- A) Since Cd has the smaller work function, its
photoelectrons have more energy given Kmax hf
f. - B) Kmax hf f and f c/l
- Kmax hc/l - f
- for Cd
- Kmax 4.14E-153E8 / 275E-9 4.22 eV
- Kmax 0.30 eV for Zn
- Kmax 4.14E-153E8 / 275E-9 4.33 eV
- Kmax 0.19 eV
40Review of Photoelectric Effect
- Kmax hf f
- Kmax Kinetic energy of photoelectrons
- hf energy of the photon
- f binding energy or work function of the
metal.
Ionization level
0.0 eV
-8.0 eV
Ground state (lowest energy level)
-12.0 eV
41Question
- The photoelectric equation is Kmax hf f.
Suppose you graph f on horizontal axis and Kmax
on vertical. What information do you get from the
slope and intercept? - Slope Plancks Constant
- Intercept -?
42The Photoelectric Effect experiment
- The Photoelectric Effect experiment is one of the
most famous experiments in modern physics. - The experiment is based on measuring the
frequencies of light shining on a metal, and
measuring the energy of the photoelectrons
produced by seeing how much voltage is needed to
stop them. - Albert Einstein won the Nobel Prize by explaining
the results.
43Photoelectric Effect experiment
At voltages less negative than Vs, the
photoelectrons have enough kinetic energy to
reach the collector.
If the potential is Vs, or more negative than Vs,
the electrons dont have enough energy to reach
the collector, and the current stops.
Collector (-)
metal ()
e-
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e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
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e-
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A
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44Experimental determination of the Kinetic Energy
of a photoelectron
- The kinetic energy of photoelectrons can be
determined from the voltage (stopping potential)
necessary to stop the electron. - If it takes 6.5 Volts to stop the electron, it
has 6.5 eV of kinetic energy.
45Strange results in the Photoelectric Effect
experiment
- Voltage necessary to stop electrons is
independent of intensity (brightness) of light.
It depends only on the lights frequency (or
color). - Photoelectrons are not released below a certain
frequency, regardless of intensity of light. - The release of photoelectrons is instantaneous,
even in very feeble light, provided the frequency
is above the cutoff.
46Voltage versus current for different intensities
of light.
Number of electrons (current) increases with
brightness, but energy of electrons doesnt!
I
V
Vs, the voltage needed to stop the electrons,
doesnt change with light intensity. That means
the kinetic energy of the electrons is
independent of how bright the light is.
Stopping Potential
47Voltage versus current for different frequencies
of light.
Energy of electrons increases as the energy of
the light increases.
f3 gt f2 gt f1
I
V
Vs changes with light frequency. That means the
kinetic energy of the photoelectrons is dependent
on light color.
Stopping Potential
48Graph of Photoelectric Equation
Kmax
Kmax h f - f y m x b
f
49Photoelectric simulations
- Link for simulated photoelectric effect
experiment - http//lectureonline.cl.msu.edu/mmp/kap28/PhotoEf
fect/photo.htm
50Assignment (due Friday next week)
- Run the photoelectric experiment for all three
metals. You must collect at least 5 data points
for each metal. - Graph the data such that Plancks constant can be
determined from the slope and the work function
of the metal can be determined from the
y-intercept. - Your report consists of three data tables and
three graphs, one for each metal. Clearly
indicate the results you got for each metal. - Graphs and tables may be done by hand on graph
paper, or you may use Excel or another
spreadsheet program if you like.
51Wave-Particle Duality
- Waves act like particles sometimes and particles
act like waves sometimes. - This is most easily observed for very energetic
photons (gamma or x-Ray) or very tiny particles
(elections or nucleons)
52Particles and Photons both have Energy
- A moving particle has kinetic energy
- E K ½ mv2
- A particle has most of its energy locked up in
its mass. - E mc2
- A photons energy is calculated using its
frequency - E hf
53Particles and Photons both have Momentum
- For a particle that is moving
- p mv
- For a photon
- p h/?
- Check out the units! They are those of momentum.s
54Particles and Photons both have a Wavelength
- For a photon
- ? c/f
- For a particle
- ? h/p where p mv
- This is referred to as the deBroglie wavelength
55We have experimental proof of Wave-Particle
Duality
- Compton scattering
- Proof that photons have momentum.
- High-energy photons collided with electrons
exhibit conservation of momentum. - Davisson-Germer Experiement
- Verified that electrons have wave properties by
proving that they diffract. - Electrons were shone on a metal surface and
acted like light by diffraction and interference.
56Sample problem
- What is the momentum of photons that have a
wavelength of 620 nm?
57Sample problem
- What is the wavelength of a 2,200 kg elephant
running at 1.2 m/s?