Title: EE 230: Optical Fiber Communication Lecture 17
1 EE 230 Optical Fiber Communication Lecture 17
System Considerations
From the movie Warriors of the Net
2Basic Network Topologies
3Bitrate Distance Graph for various point to point
link technologies
4System Design
- Determine wavelength, link distance, and
bit-error rate - Work out power budget
- Work out risetime budget
- Work out cost budget
5Power Budget Steps
- Start with BER and bit rate, determine bandwidth
B based on coding method - Given BER, determine Q factor and S/N ratio
- B 1/2?RLC gives the maximum load resistance RL
based on B and C - Based on RL and M, determine detector sensitivity
(minimum power for S/N) - Add system margin, typically 6 dB, to determine
necessary power at receiver
6Power budget steps, continued
- Add power penalties, if necessary, for extinction
ratio, intensity noise (includes S/N degradation
by amplifiers), timing jitter - Add loss of fiber based on link distance
- Include loss contributions from connections and
splices - End up with required power of transmitter, or
maximum length of fiber for a given transmitter
power
7Power budget example
- Imagine we want to set up a link operating at
1550 nm with a bit rate of 1 Gb/s using the RZ
format and a BER of 10-9. We want to use a PIN
photodiode, which at this wavelength should be
InGaAs. The R0 for the diode is 0.9 A/W and its
dark current is 4 nA.
8Bandwidth required for bit rate
- For NRZ format, B0.5 times bit rate
- For RZ format, Bbit rate
- For this example, the bandwidth B is equal to the
bit rate, 109 /s.
9Bandwidth limit
- C2 pF for this photodiode.
- B 1/2?RLC, so the load resistance RL must be
(2?BC)-1 79.6 ?
10Q Factor, S/N Ratio, and BER
- For our BER of 10-9, Q6 and S/N144
11Minimum signal power required
- Method 1
- Signal to noise ratio is equal to
- where R0 is responsivity, M is multiplier, id
- is dark current, and PS is signal power. If we
set this expression equal to the SNR of 144 we
calculated, the required signal power PS turns
out to be 6.09x10-6 W -22.2 dBm.
12Noise Equivalent Power (NEP)
- Method 2
- NEP is the signal power at which S/N1
- Units are W/Hz1/2
- In this case, M1 and the dark current 4 nA.
- The factor outside the radical is 1/R0. We can
thus determine the NEP by multiplying the above
result by the square root of the bandwidth. The
result is 5.1x10-7 W, which equals -33.0 dBm.
13NEP Method, continued
- Since Q is proportional to the square root of
SNR, multiplying the NEP by that square root will
give us the minimum acceptable power. - In this case, SNR144, so the minimum power is 12
times NEP 6.12x10-6 W -22.1 dB, the same
result as the other method.
14Extinction ratio penalty
- Corrects for emission from transmitter during 0
bits - Extinction ratio rexP0/P1
- If our extinction ratio is 0.1, the penalty is
0.87 dB.
15Intensity noise penalty
- Corrects for power fluctuations during 1 bits
- rI inverse of SNR of transmitter and amplifier
output - If the SNR of the amplified source is 13 dB 20,
then rI 0.05 and we will have to raise the
power at the receiver by dI to keep the desired
SNR. - Since Q 6, dI 0.41 dB.
16Timing jitter penalty
- Parameter B?fraction of bit period over which
apparent clock time varies - If our jitter represents 10 of the bit period,
the power penalty is 0.34 dB
17Fiber attenuation
- If the attenuation in the fiber is 0.2 dB/km and
the link is 80 km long, the total loss in the
fiber will be 16.0 dB
18Example results
- Minimum power required for receiver
- -22.1 dBm
- Safety margin 6.0 dB
- Extinction ratio power penalty 0.87 dB
- S/N power penalty 0.41 dB
- Timing jitter power penalty 0.34 dB
- Fiber loss over 80 km 16.0 dB
- Total minimum transmitter power
- 1.52 dBm 1.42 mW
19Further steps
- Alternatively, previous data could be used with a
fixed transmitter power to determine maximum
length of a fiber link - If power budget does not add up, one can
- replace PIN photodiode with APD
- add an EDFA to the link
20Power Budget Example
21Risetime Budget
22Rise time budget components
- bit rate and coding format determine upper limit
of rise time - rise time of transmitter (from manufacturer
laser faster than LED) - pulse spread due to dispersion
- rise time of receiver (from manufacturer PIN
faster than APD) - Rise time components are combined by taking the
square root of sums of squares
23Upper limit for rise time
- For NRZ format, Tr0.70/B
- For RZ format, Tr0.35/B
- In this case, choose RZ format. Tr must thus be
less than or equal to 0.35/109 350 ps - To add a safety margin of x, multiply B by
(1x/100) before calculating rise time budget
limit
24Group Velocity Dispersion-based rise time
- Calculate from laser optical bandwidth if known,
or from modulation rate - In this case, D17 ps/nm-km, L80 km, and
??0.016 nm, so tf21.8 ps.
25Modal dispersion rise time
- For multimode fiber, time spread due to modal
dispersion is based on core index and fiber
length L. - For step-index fiber
- For graded-index fiber
26Total rise time
- For this example, tMD0, tTR100 ps, tRC0.5 ns,
and tGVD 21.8 ps as before. tr is therefore 510
ps, and the rise time budget does not meet the
limit. - Can use NRZ format
- Use faster detector or transmitter
- Use graded-index fiber for less dispersion
27Computer Based Link Simulation
Computer Simulation is often used to model
opticla links to account for the complex
interaction between components and nonlinear
effects Commercial simulation tools are now
available such as Linksim from RSoft and the
tools from VPI Systems
Fiber-Optic Communication Systems-G. Agrawal