Title: Discrete Random Variables
1Discrete Random Variables
2Random Variables
- A random variable is a function that assigns
numerical values to all the outcomes in the
sample space.
3Notation
- We will use capital letters from the end of the
alphabet to represent a random variable. - Usually Y
- The corresponding lower case letter will
represent a particular value of the random
variable. - P(Y y) is the probability that the random
variable Y is equal to the value y.
4Discrete and Continuous Random Variables
- A continuous random variable can take any value
in an interval of the real number line. - Usually measurements
- A discrete random variable can take a countable
number of distinct values. - Usually counts
5Discrete and Continuous Random Variables
- Discrete or continuous?
- Time until a projectile returns to earth.
- The number of times a transistor in computer
memory changes state in one operation. - The volume of gasoline that is lost to
evaporation during the filling of a gas tank. - The outside diameter of a machined shaft.
- The number of chapters in your test book.
6Discrete Numeric Random Variables
- A small airport in New Zealand is interested in
the number of late aircraft arrivals per day.
Every day for a year it counts the daily number
of late arrivals. - Let random variable Y Number of aircraft in
one day that arrive late.
7Discrete Numeric Random Variables
- What is the probability that on any randomly
chosen day that 3 aircrafts are late? - What is the chance that on any randomly chosen
day at least 1 aircraft is late?
8Discrete Numeric Random Variables
- An assembly consists of three mechanical
components. Suppose that the probabilities that
the first, second, and third components meet
their specifications are 0.90, 0.95 and 0.99
respectively. Assume the components are
independent. - Let Si the event that component i is within its
specification.
9Possible Outcomes for One assembly
0.00495
0.00005
Let Y Number of components within specification
in a randomly chosen assembly
Y 0 1 2
3 P(Yy) 0.00005 0.00635 0.14715
0.84645
10Discrete Random Variables
- Probability mass function
- p(y) P(Y y)
- Note
- 0 lt p(y) lt 1 for every value of y
- and
11Probability Function for a Discrete Random
Variable can be expressed as a table or graph and
sometimes as a formula.
Y 0 1 2
3 P(Yy) 0.00005 0.00635 0.14715
0.84645
12Cumulative Distribution Function
- If Y is a random variable, then the cumulative
distribution function is denoted by F(y). - F(y) P(Y lt y)
13Number of components within specification for a
randomly chosen assembly
Distribution Function
Y 0 1 2
3 P(Yy) 0.00005 0.00635 0.14715
0.84645
Cumulative Distribution Function
Y 0 1 2
3 P(Ylty) 0.00005 0.00640 0.15355
1.0000
14Cumulative Distribution Function
Distribution Function
P(Y lt y)
P(Y y)
15Expected Value
- Note, this distribution is the distribution for a
population - The expected value of the population is the
population mean, µ, for the distribution.
Y 0 1 2
3 P(Yy) 0.00005 0.00635 0.14715
0.84645
16Number of Components within Specification on a
Randomly Chosen Assembly
17Variance
- The variance of the population is the expected
value of (Y - µ)2.
Y 0 1 2
3 P(Yy) 0.00005 0.00635 0.14715
0.84645
18Computational Formula for Variance
19Population Standard Deviation
20We receive 75 of a certain part from Supplier A
and 25 from supplier B. Two of these parts are
used in an assembly. Let Y number of parts from
Supplier A in the assembly. What is the expected
value of Y?
21A project manager for an engineering firm
submitted bids on three projects. The following
table summarizes the firms chances of having the
three projects accepted.
Project A B C Prob
of accept 0.30 0.80 0.10
Assuming the projects are independent of one
another, what is the probability that the firm
will have all three projects accepted?
22What is the probability of having at least one
project accepted?
Project A B C Prob
of accept 0.30 0.80 0.10
23Let Y number of projects accepted.
y 0 1 2 3
p(y) 0.126 0.572 0.278 0.024
What is the expected number of projects accepted?
24Let Y number of projects accepted.
y 0 1 2 3
p(y) 0.126 0.572 0.278 0.024
What is the variance for number of projects
accepted?
25Rules of Expectation
- E(c) c
- E(cY) cE(Y)
- E(X Y) E(X) E(Y)
26Rules of Variance
- Var(c) 0
- Var(cY) c2Var(Y)
- Var(X Y) Var(X) Var(Y)
- when X and Y are independent.
27Binomial Random Variable
- Suppose we toss a fair coin 20 times, counting
the number of heads. - This is an example of a binomial experiment.
- The possible outcomes can be represented with a
binomial random variable which follows a binomial
distribution.
28Binomial Experiment
- There are n identical trials.
- There are two possible outcomes for each trial
success and failure. - Outcomes are independent from trial to trial.
- Probability of success, p, remains constant from
trial to trial. - Let Y denote the number of success. Then Y has a
Binomial distribution, denoted by YB(n, p).
29Binomial Experiment
- Each toss of the coin is a trial. We performed 20
trials. So n 20. - The two possible outcomes of a trial are heads or
tails. Since we are counting heads, heads is a
success, while tails is a failure. - Are the outcomes of our trials independent of one
another? - Probability of success (heads) is 0.50
30Binomial Experiment
- A manufacturer of water filters for refrigerators
monitors the process for defective filters.
Historically, this process averages 5 defective
filters. - Suppose five filters are randomly selected for
testing. We are interested in the number of
defectives in the sample. - Define a trial.
- Calculate n.
- Define a success.
- Are the outcomes independent from trial to trial?
- Calculate p.
31Water Filters
- A manufacturer of water filters for refrigerators
monitors the process for defective filters.
Historically, this process averages 5 defective
filters. Five filters are randomly selected. - Find the probability that all five filters are
defective. - Find the probability that no filters are
defective. - Find the probability that exactly 1 filter is
defective.
32- A manufacturer of water filters for refrigerators
monitors the process for defective filters.
Historically, this process averages 5 defective
filters. Five filters are randomly selected. - Find the probability that exactly 2 filters are
defective.
- 5(.05)2(.95)3
- 10(.05)2(.95)3
- 15(.05)2(.95)3
33Combinations
- Number of ways to choose r distinct objects from
n distinct objects
n choose r
34Recall
- n!
- 5! (5)(4)(3)(2)(1) 120
- 7! (7)(6)(5)(4)(3)(2)(1) 5040
- 1! 1
- 0! 1
35Probability Function for a Binomial Random
Variable
for y 0, 1, 2, ,n
36If Y follows a Binomial Distribution
- Binomial standard deviation
37Suppose we are producing 15 defective filters.
Let Y Number of Defective Filters in a Sample
of 10
38What is the approximate probability that there
will be at least 1 defective filter in a sample
of 10?
A. 0.20 B. 0.35 C. 0.80 D. 0.90
39Historically, 10 of homes in Florida have radon
levels higher than that recommended by the EPA.
In a random sample of 20 homes, find the
probability that exactly 3 have radon levels
higher than the EPA recommendation.
40If a manufacturing process has a 0.03 defective
rate, what is the probability that at least one
of the next 25 units inspected will be defective?
- (0.03)1 (0.97)24
- 1 (0.03)1 (0.97)24
- 1 (0.03)0 (0.97)25
- 1 (0.03)25
41A manufacturing process has a 0.03 defective
rate. If we randomly sample 25 units
- What is the probability that less than 6 will be
defective? - What is the probability that 4 or more are
defective? - What is the probability that between 2 and 5,
inclusive, are defective?
42Insulated Wire
- Consider a process that produces insulated copper
wire. Historically the process has averaged 2.6
breaks in the insulation per 1000 meters of wire.
We want to find the probability that 1000 meters
of wire will have 1 or fewer breaks in
insulation? - Is this a binomial problem?
43Poisson Distribution
- Poisson distribution can be used to model the
number of events occurring in a continuous time
or space. - Let Y number of breaks in 1000 meters of wire.
- P(Y lt 1) P(Y 0) P(Y 1)
44Poisson Distribution
for y 0, 1, 2,
where ? is the average number of occurrences per
base unit. and t is the number of base units
inspected.
Further
45Insulated Wire
Let Y Number of breaks in 1000 meters of wire.
? 2.6 and t 1
The expected number of breaks in 1000 meters of
wire is 2.6.
46Insulated Wire
- If we were inspecting 2000 meters of wire, ?t
2.62 5.2 - If we were inspecting 500 meters of wire, ?t
2.60.5 1.3
47Conditions for a Poisson Distribution
- Areas of inspection are independent of one
another. - The probability of the event occurring at any
particular point in space or time is negligible. - The mean remains constant over all areas of
inspection.
48Suppose we average 5 radioactive particles
passing a counter in 1 millisecond. What is the
probability that exactly 3 particles will pass in
one millisecond?
49Suppose we average 5 radioactive particles
passing a counter in 1 millisecond. What is the
probability that exactly 10 particles will pass
in the next three milliseconds?