Title: Lecture 4: Propagation of light through atmospheric turbulence
1Lecture 4Propagation of light through
atmospheric turbulence
- Claire Max
- Astro 289C, UC Santa Cruz
- January 17, 2008
2Outline for today
- Kolmogorov turbulence
- Physics
- Assumptions
- Derived spectrum
- Effect of Kolmogorov turbulence on the
propagation of light
3Temperature profile in atmosphere
- Strong temperature gradient in troposphere, at
low altitudes
4Wind shear mixes layers with different
temperatures
- Wind shear ? Kelvin Helmholtz instability
- If two regions have different temperatures,
turbulent temperature fluctuations ?T will result
Computer simulation
5Real Kelvin-Helmholtz instability measured by
FM-CW radar
- Colors show intensity of radar return signal.
- Radio waves are backscattered by the turbulence.
6Turbulence strength vs. time of day
Day
Night
Day
Night
Night
Day
Night
- Theory for different heights Theory vs.
data - Balance heat fluxes in surface layer
- Credit Wesely and Alcaraz, JGR (1973)
7Leonardo da Vincis view of turbulence
8Kolmogorov turbulence in a nutshell
- Big whorls have little whorls,
- Which feed on their velocity
- Little whorls have smaller whorls,
- And so on unto viscosity.
L. F. Richardson (1881-1953)
9Kolmogorov turbulence, cartoon
ground
10Kolmogorov turbulence, in words
- Assume energy is added to system at largest
scales - outer scale L0 - Then energy cascades from larger to smaller
scales (turbulent eddies break down into
smaller and smaller structures). - Size scales where this takes place Inertial
range. - Finally, eddy size becomes so small that it is
subject to dissipation from viscosity. Inner
scale l0 - L0 ranges from 10s to 100s of meters l0 is a
few mm
11Example Breakup of Kelvin-Helmholtz vortex
- Computer simulation
- Start with large coherent vortex structure, as is
formed in Kelvin-Helmholtz instability - Watch it develop smaller and smaller substructure
- Analogous to Kolmogorov cascade from large eddies
to small ones - From small k to large k
12How large is the Outer Scale?
- Dedicated instrument, the Generalized Seeing
Monitor (GSM), built by Dept. of Astrophysics,
Nice Univ.)
13Outer Scale 15 - 30 m, from Generalized Seeing
Monitor measurements
- F. Martin et al. , Astron. Astrophys. Supp.
v.144, p.39, June 2000 - http//www-astro.unice.fr/GSM/Missions.html
14Concept Question
- What do you think really determines the outer
scale in the boundary layer? At the tropopause? - Hints?
15The Kolmogorov turbulence model, derived from
dimensional analysis
- u velocity, energy dissipation rate per
unit mass, ? viscosity, l0 inner scale, l
local spatial scale - Energy/mass u2/2 ? u2
- Energy dissipation rate per unit mass
16What is the inner scale l0 ?
- Navier Stokes Equations
- n viscosity, u velocity, ppressure, r
mass density - Take product of 1st equation with u, keep only
the viscosity term on the right side
(hypothesized to be dominant at l0 )
17Inner scale l0 , continued
- Two equations to solve for l0
- Solve for l0
- where the Reynolds number is
18Reynolds number
- Reynolds number
- Here L is a typical length scale, u is a typical
velocity, n is the viscosity - Re inertial stresses / viscous stresses
- 0 - 1 Creeping flow
- 1 - 100 Laminar flow, strong Re dependence
- 100 - 1,000 Boundary layer
- 1,000 - 10,000 Transition to slightly turbulent
- 104 - 106 Turbulent, moderate Re dependence
- gt 106 Strong turbulence, small Re dependence
19Derive the Kolmogorov Power Spectrum using
dimensional analysis
- 1-D power spectrum of velocity fluctuations k
2p / l - For dimensional analysis, divide by k
-
- 3-D power spectrum divide by k3
- For rigorous calculation see V. I. Tatarski,
1961, Wave Propagation in a Turbulent Medium,
McGraw-Hill, NY
20Lab experiments agree
- Air jet, 10 cm diameter (Champagne, 1978)
- Assumptions turbulence is homogeneous,
isotropic, stationary in time
Credit Gary Chanan, UCI
Slope -5/3
Power (arbitrary units)
Slope -5/3
l0
L0
k (cm-1)
21Structure functions are used a lot in AO. What
are they?
- Mean values of meteorological variables change
over minutes to hours. Examples T, p, humidity - If f(t) is a non-stationary random variable,
- Ft(t) f ( t t) - f ( t) is a difference
function that is stationary for small t . - Structure function is measure of intensity of
fluctuations of f (t) over a time
scale ? t - Df(t) lt Ft(t) 2gt lt f (t t) - f ( t)
2 gt -
22Structure function for atmospheric fluctuations
- Scaling law we derived earlier for Kolmogorov
turbulence - u2 e 2/3 l2/3 r 2/3
- Heuristic derivation Velocity structure function
u2 - Du ( r ) lt u (x ) - u ( x r ) 2 gt
Cu2 r 2/3 - here Cu2 constant to clean up the look of
the equation
23Derivation of Du from dimensional analysis
- If turbulence is homogenous, isotropic,
stationary - where f is a dimensionless function of a
dimensionless argument. - Dimensions of a are u2, dimensions of b are
length, and they must depend only on and n
(the only free parameters in the problem). - n cm2 s-1 erg s-1 gm-1 cm2
s-3
24Du, continued
- The only combinations of and n with the right
dimensions are - So
25What about temperature and index of refraction
fluctuations?
- Temperature fluctuations are carried around
passively by the velocity field (for
incompressible fluids). - So T and N have structure functions similar to u
- DT ( r ) lt T (x ) - T ( x r ) 2 gt CT2
r 2/3 - DN ( r ) lt N (x ) - N ( x r ) 2 gt CN2
r 2/3
26How do you measure index of refraction
fluctuations in situ?
- Refractivity
- Index fluctuations
- So measure ?T , p, and T calculate CN2
27Simplest way to measure CN2 is to use
fast-response thermometers
- DT ( r ) lt T (x ) - T ( x r ) 2 gt CT2 r
2/3 - Example mount fast-response temperature probes
at different locations along a bar - X X X X X X
- Form spatial correlations of each time-series T(t)
28Assumptions of Kolmogorov turbulence theory
- Medium is incompressible
- External energy is input on largest scales
(only), dissipated on smallest scales (only) - Smooth cascade
- Valid only in inertial range between scales L0
and l0 - Turbulence is
- Homogeneous
- Isotropic
- In practice, Kolmogorov model works surprisingly
well!
29Typical values of CN2
- Index of refraction structure function
- DN ( r ) lt N (x ) - N ( x r ) 2
gt CN2 r 2/3 - Night-time boundary layer CN2 10-13 - 10-15
m-2/3
Paranal, Chile, VLT
30Turbulence profiles from SCIDAR
Eight minute time period (C. Dainty, Imperial
College)
Starfire Optical Range, Albuquerque NM
Siding Spring, Australia
31Atmospheric Turbulence Main Points
- The dominant locations for index of refraction
fluctuations that affect astronomers are the
atmospheric boundary layer and the tropopause - Atmospheric turbulence (mostly) obeys Kolmogorov
statistics - Kolmogorov turbulence is derived from dimensional
analysis (heat flux in heat flux in turbulence) - Structure functions derived from Kolmogorov
turbulence are proportional to r2/3 - All else will follow from these points!
32Part 2 Effect of turbulence on spatial coherence
function of light
33Definitions - Structure Function and Correlation
Function
- Structure function Mean square difference
- Covariance function Spatial correlation of a
function with itself
34Relation between structure function and
covariance function
- A problem on the homework for next week
- Derive this relationship
- Hint expand the product in the definition of D?
( r ) and assume homogeneity to take the averages
35Definitions - Spatial Coherence Function
- Spatial coherence function of field is defined as
- Covariance for complex fns
- Note that Quirrenbach and Hardy call this
function but Ive called it
C? (r) in order to avoid confusion with the
correlation function B? ( r ) . C? (r) is a
measure of how related the field ? is at one
position (e.g. x) to its values at neighboring
positions (say x r ). -
36Now evaluate spatial coherence function C? (r)
- For a Gaussian random variable ? with zero
mean, -
- So
- So finding spatial coherence function C? (r)
amounts to evaluating the structure function for
phase D? ( r ) !
37Next solve for D? ( r ) in terms of the
turbulence strength CN2
- We want to evaluate
- Recall that
- So next we need to evaluate
38Solve for D? ( r ) in terms of the turbulence
strength CN2, continued
- But for
a wave propagating - vertically (in z direction) from height h to
height h ?h. - Here n(x, z) is the index of refraction.
- Hence
39Solve for D? ( r ) in terms of the turbulence
strength CN2, continued
40Solve for D? ( r ) in terms of the turbulence
strength CN2, continued
- Now we can evaluate D? ( r )
41Solve for D? ( r ) in terms of the turbulence
strength CN2, completed
42Finally we can evaluate the spatial coherence
function C? (r)
For a slant path you can add factor ( sec ? )5/3
to account for dependence on zenith angle ?
Concept Question Note the scaling of the
coherence function with separation, wavelength,
turbulence strength. Think of a physical reason
for each.
43Given the spatial coherence function, calculate
effect on telescope resolution
- Define optical transfer functions of telescope,
atmosphere - Define r0 as the telescope diameter where the two
optical transfer functions are equal - Calculate expression for r0
44Define optical transfer function (OTF)
- Imaging in the presence of imperfect optics (or
aberrations in atmosphere) in intensity units - Image Object ? Point Spread Function
- I O ? PSF ? ? dx O( x - r ) PSF ( x )
- Take Fourier Transform F ( I ) F (O ) F ( PSF
) - Optical Transfer Function is Fourier Transform of
PSF - OTF F ( PSF )
convolved with
45Examples of PSFs and their Optical Transfer
Functions
Seeing limited OTF
Seeing limited PSF
Intensity
?-1
?
l / r0
l / D
r0 / l
D / l
Diffraction limited PSF
Diffraction limited OTF
Intensity
?-1
?
l / r0
l / D
D / l
r0 / l
46Now describe optical transfer function of the
telescope in the presence of turbulence
- OTF for the whole imaging system (telescope plus
atmosphere) - S ( f ) B ( f ) ? T ( f )
- Here B ( f ) is the optical transfer fn. of the
atmosphere and T ( f) is the optical transfer fn.
of the telescope (units of f are cycles per
meter). - f is often normalized to cycles per
diffraction-limit angle (l / D). - Measure the resolving power of the imaging system
by - R ? df S ( f ) ? df B ( f ) ? T ( f )
47Derivation of r0
- R of a perfect telescope with a purely circular
aperture of (small) diameter d is - R ? df T ( f ) ( p / 4 ) ( d / l )2
- (uses solution for diffraction from a circular
aperture) - Define a circular aperture r0 such that the R of
the telescope (without any turbulence) is equal
to the R of the atmosphere alone - ? df B ( f ) ? df T ( f ) ? ( p / 4 ) ( r0
/ l )2 -
48Derivation of r0 , continued
- Now we have to evaluate the contribution of the
atmospheres OTF ? df B ( f ) - B ( f ) C? ( l f ) (to go from cycles per
meter to cycles per wavelength)
49Derivation of r0 , continued
- Now we need to do the integral in order to solve
for r0 - ( p / 4 ) ( r0 / l )2 ? df B ( f ) ? df
exp (- K f 5/3) - Now solve for K
- K 3.44 (r0 / l )-5/3
- B ( f ) exp - 3.44 ( l f / r0 )5/3 exp -
3.44 ( ? / r0 )5/3
Replace by r
50Derivation of r0 , concluded
51Scaling of r0
- r0 is size of subaperture, sets scale of all AO
correction - r0 gets smaller when turbulence is strong (CN2
large) - r0 gets bigger at longer wavelengths AO is
easier in the IR than with visible light - r0 gets smaller quickly as telescope looks
toward the horizon (larger zenith angles ? )
52Typical values of r0
- Usually r0 is given at a 0.5 micron wavelength
for reference purposes. Its up to you to scale
it by ?-1.2 to evaluate r0 at your favorite
wavelength. - At excellent sites such as Mauna Kea in Hawaii,
r0 at 0.5 micron is 10 - 30 cm. But there is a
big range from night to night, and at times also
within a night.
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54Next time All sorts of good things come from
knowing r0
- Timescales of turbulence
- Isoplanatic angle AO performance degrades as
astronomical targets get farther from guide star -
55Assignment (see web page for details)
- Reading for Tuesday anisoplanatism, tip-tilt
errors, other contributors to total wavefront
error of an AO system (see web) - Homework for next Thursday (see web)