Title: IDEAL SOLUTIONS, FUGACITY, ACTIVITY, AND STANDARD STATES
1TOPIC 3
- IDEAL SOLUTIONS, FUGACITY, ACTIVITY, AND STANDARD
STATES
2I. PARTIAL AND APPARENT MOLAR PROPERTIES
3MOLAR VS. PARTIAL MOLAR QUANTITIES
- Molar values of state functions are defined as
follows - etc. These are useful only in the case of
single-component systems and dependent only on
pressure and temperature, not composition. - Partial molar quantities are defined according
to - These are dependent on T, P, and composition.
4PHYSICAL INTERPRETATION OF PARTIAL MOLAR VOLUMES
- The partial molar volume of component i in a
system is equal to the infinitesimal increase or
decrease in the volume, divided by the
infinitesimal number of moles of the substance
which is added, while maintaining T, P and
quantities of all other components constant. - Another way to visualize this is to think of the
change in volume on adding a small amount of
component i to an infinite total volume of the
system. - Note partial molar quantities can be positive or
negative!
5SUMMING PARTIAL MOLAR QUANTITIES
- The total value for a state function of a system
is obtained by summing the partial molar volumes
of its components according to - We can manipulate partial molar quantities in a
manner identical to the way we manipulate total
quantities. - As with total state functions, we cannot know
absolute values, only differences (except for V
and S)!
6- We can also express the summations in terms of
molar state functions and mole fractions - In the case of the volume of a two-component
system, e.g., NaCl-H2O, we can write
7Schematic plot of the molar volume of aqueous
NaCl solutions as a function of mole fraction of
NaCl.
8HOW TO DETERMINE PARTIAL MOLAR VOLUME
- Refer to the previous diagram. Triangles A and B
are similar, so it is true that
but
so
comparison with
shows that
So the partial molar volumes can be determined
from the intercepts of a line tangent to the plot
of volume vs. mole fraction.
9PARTIAL MOLAR FREE ENERGY -THE CHEMICAL POTENTIAL
Chemical potential
- The previous relationships also apply
It can also be shown that
10Schematic plot of chemical potential vs. mole
fraction for a binary system
11COMPOSITIONAL CHANGES
- The Master equations that we developed previously
for one-component systems can now be written as
12AN ADDITIONAL REQUIREMENT FOR EQUILIBRIUM
- Consider a system with components i, j, k, l,
distributed among phases ?, ?, ?, ?, - At equilibrium it must be true that
- ?i? ?i? ?i? ?i?
- ?j? ?j? ?j? ?j? ...
- ?k? ?k? ?k? ?k? ...
- ?l? ?l? ?l? ?l? ...
- etc.
13- Chemical potentials represent the slope of the
Gibbs free energy surface in compositional space.
Thus, a component will move from a phase in which
it has a high chemical potential, to one in which
it has a low chemical potential, until its
chemical potential in all phases is the same. - Specific example Consider a silicate melt in
equilibrium with forsterite (Mg2SiO4), and
enstatite (Mg2Si2O6). At equilibrium the
following must be true - ? Mgmelt ?MgFo ?MgEn
- ?Simelt ?SiFo ?SiEn
- ?Omelt ?OFo ?OEn
14GIBBS-DUHEM EQUATION
- For a homogenous phase of two components, A and
B, the Master Equation becomes - If we now specify equilibrium at constant T and P
- Now, we have shown above that
- Differentiating this we obtain
15GIBBS-DUHEM EQUATION - CONTINUED
- At equilibrium
- Substituting the previous expression
- we obtain
- In the general case we get the Gibbs-Duhem
equation
16GIBBS-DUHEM EQUATION - CONTINUED
- Starting with the expression
- If we divide through both sides by dXA we get
- And now dividing by nA nB we get
17APPARENT MOLAR QUANTITIES
- Although in principle, partial molar quantities
can be measured from intercepts of lines tangent
to a plot of state functions vs. mole fraction as
outlined previously, they are not determined this
way in practice. - In practice, apparent molar quantities are
determined. For a state function like volume, the
apparent molar volume, ?V, is given by - ?V (V - n1V1)/n2
- where n1, and n2 are the number of moles of
solvent and solute, respectively, and V1 is the
molar volume of pure solvent.
18Total volume of a solution as a function of
solute concentration. Illustrates the difference
between partial and apparent molar volume.
19- The apparent molar volume is the volume that
would be attributed to one mole of solute in
solution if it is assumed that the solvent
contributes the same volume it has in the pure
state. - Starting with the definition of apparent molar
volume - ?V (V - n1V1)/n2
- we can rearrange to get
- V n1V1 n2 ?V
- and dividing by (n1 n2),
- V X1V1 X2 ?V
- Thus, the volume of solution can be calculated
knowing ?V instead of the partial molar volume.
20Comparison of apparent molar and partial molar
volumes
21PARTIAL MOLAR VOLUMES FROM APPARENT MOLAR VOLUMES
or
- If ?V measurements are fit by an equation of the
type ?V a bm cm2 - then we have V2 m(b 2cm) a bm cm2 or
- V2 a 2bm 3cm2
22II. IDEAL SOLUTIONS
23THERMODYNAMICS OF IDEAL SOLUTIONS
- An ideal solution is one that satisfies the
following equation ?i - ?i RT ln Xi - where ?i is the chemical potential of some
component i in a solution and ?i is the chemical
potential of that component in the pure form. - Recall that
- substituting we get
24- These equations tell us that the free energy of
an ideal solution is the sum of two terms the
free energy of a mechanical mixture, and a free
energy of ideal mixing.
25ENTHALPY AND VOLUME OF AN IDEAL SOLUTION
If i is a pure substance.
- There is no volume or enthalpy change upon ideal
mixing. In other words
However, there is a change in entropy upon ideal
mixing. Because the solution is more disordered,
entropy increases!
26ENTROPY OF MIXING
- but we have ?Gideal mix ?Hideal mix -T?Sideal
mix - and ?Hideal mix 0
- so
Thus, the only contribution to ?Gideal mix is an
entropy contribution!
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30III. FUGACITY AND ACTIVITY
31FUGACITY
- Starting with dG VdP - SdT
- at constant T this becomes dG VdP
- For an ideal gas dG (RT/P)dP RT dln P
- This is true for ideal gases only, but it would
be nice to have a similar form for real fluids. - dG RT dln ? where ? is the fugacity
- ? ?/P ? 1 as P ? 0
- ? is the fugacity coefficient
- ? ?P
- Fugacity may be thought of as a thermodynamic
pressure it has units of pressure.
32MEASUREMENT OF FUGACITY
33Alternatively, we can begin again with
But we now define the compressibility factor Z
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35- The above equation is the basis of the
experimental determination of fugacities from
P-V-T data. - We can substitute into the integral (Z-1)/P
calculated from any equation of state, or we can
integrate graphically.
36CALCULATION OF EQUILIBRIUM BOUNDARIES INVOLVING
FLUIDS
- A number of mineral reactions involve only solid
minerals and either H2O or CO2, e.g. - KAl3Si3O10(OH)2 ? KAlSi3O8 Al2O3 H2O
- or
- CaCO3 SiO2 ? CaSiO3 CO2
- or in general
- A(s) ? B(s) C(fluid)
- ?rV VB VC - VA (VB - VA) VC
- ?rV ?sV Vfluid
37- The pressure integral for the solids is then
evaluated using the constant ?sV approximation
and that for the fluid is evaluated using
fugacities.
For the muscovite breakdown reaction above, we
can start with the equation
38- ?rV VKspar Vcor VH2O - Vmusc
- ?rV (VKspar Vcor - Vmusc) VH2O
- ?rV ?sV VH2O
A function of pressure and temperature!
39FUGACITIES IN GASEOUS SOLUTIONS
- Starting with the following, in terms of partial
molar volumes
We obtain the expression for the fugacity
coefficient of a component in a solution
40ALL CONSTITUENTS HAVE A FUGACITY
- The expression dG RT dln ?
- may be integrated between two states 1 and 2 to
give - G2 - G1 RT ln (?2/?1)
- This equation applies to a pure one-component
system. For a solution we must use chemical
potentials and we write - ?i - ?i RT ln (?i/?i)
- This equation makes no stipulation as to the
state of component i, and can therefore refer to
solid, liquid or gas.
41- Solids and liquids therefore are also associated
with a fugacity. In some cases, this fugacity can
be thought of as a vapor pressure. Fugacity can
also be thought of as an escaping tendency. - However, in some cases, a vapor phase may not
exist, but a fugacity always exists. One must
realize that the fugacity is a thermodynamic
model parameter, not always an approximation to a
real pressure. - Fugacities of solid phases or individual
components of solid solutions are not generally
known. - Fugacities are absolute physical properties.
42ACTIVITIES
- The absolute values of the fugacities of solids
and liquids cannot always be determined, but
their ratios can be. - Consider ?i - ?i RT ln (?i/?i)
- If we let one of these states be a reference
state, this can be rewritten - ?i - ?i RT ln (?i/?i)
- We now define the activity of constituent i to be
- ai ?i/?i
- Thus
- ?i - ?i RT ln ai
43DALTONS LAW
- Dalton (1811) discovered that, at low total
pressures, a mixture of gases exerts a pressure
equal to the sum of the pressures that each
constituent gas would exert if each alone
occupied the same volume. - Strictly true only for ideal gases, but is
approximately true at low total pressure where
real gases approach ideality. For each gas we
have - P1V n1RT
- P2V n2RT
- etc.
- For the gas mixture we have
44- If we divide the expression for each constituent
by the expression for the mixture we obtain -
- etc.
- or
- P1 X1Ptotal
- P2 X2Ptotal
- etc.
- Ptotal P1 P2 P3
- P1, P2, etc. are called the partial pressures.
45HENRYS LAW
- Henry (1803) was studying the solubility of gases
in liquids. He found that the amount of gas
dissolved in a liquid in contact with it was
directly proportional to the pressure on the gas,
i.e., - Pi Kh,iXi
- Kh,i is a constant called the Henrys Law
constant. - In practice, this law holds only at relatively
low values of Pi.
46RAOULTS LAW
- Raoult (1887) studied vapor-liquid systems in
which two or more liquid components were mixed in
known proportions and the liquid was equilibrated
with its own vapor. The composition of the vapor
was then determined. The total vapor pressure of
the system was low, so the vapor behaved ideally
and conformed to Daltons law. In such systems,
the partial pressures of the gaseous components
were found to be a linear function of the their
mole fraction in the liquid.
47- Thus, for a binary system A-B, he obtained
- PA XAPAº and PB XBPBº
- where PAº and PBº are the vapor pressures of pure
components A and B, respectively.
48- The only way that such a simple relationship as
Raoults law can hold is if the intermolecular
forces between A-A, B-B, and A-B are identical.
Solutions in which this is the case are called
ideal solutions. - The most general way of expressing Raoults Law
is - Pi XiPiº
- Very few systems follow Raoults Law over the
entire range of composition from Xi 0 to Xi
1. However, Raoults Law often applies to the
solvent in dilute solutions, whereas the solute
in dilute solutions follows Henrys Law.
49Partial pressure in the mixture
acetone-chloroform at 35.2C. This mixture
exhibits negative deviations from Raoults Law
50Partial pressure in the mixture carbon
disulfide-acetone at 35.2C. This mixture
exhibits positive deviations from Raoults Law
51THE GIBBS-DUHEM EQUATION REVISITED
- Previously we derived the Gibbs-Duhem equation
for a binary solution - This can be rearranged to give
52- This equation shows that the slopes of tangents
to curves of chemical potential vs. mole fraction
for binary solutions are not independent of one
another. - For example, if XB 0, and
has a finite - value, then .
- If XA 0.5, then
etc.
53Chemical potentials in solutions of carbon
disulfide and acetone.
Gibbs-Duhem Equation
54THE DUHEM-MARGULES EQUATION
- Starting with the Gibbs-Duhem equation
- If we recall that d?i RT dln ?i we can make
the substitution and obtain
55When the vapors are nearly perfect gases, we may
substitute partial pressures for fugacities to
obtain the approximate relation
Realizing that dXB -dXA, and that d ln P d
P/P we can rewrite this as
56Application of the Duhem-Margules equation.
Partial pressure is plotted on the Y-axis.
Duhem-Margules Equation
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59THE LEWIS FUGACITY RULE
- This is a variation on Raoults Law
- fimixture Xifipure
- This states that the fugacity of a constituent in
a mixture is equal to its mole fraction times
its fugacity in the pure state. - Many substances that do not obey Raoults Law do
in fact obey the Lewis Fugacity Rule.
60IDEAL MIXING AND ACTIVITY
- If we compare the definition of the activity
- ai ?i/?i
- and a rearrangement of the Lewis Fugacity Rule
- Xi fimixture/fipure
- we see that for solutions that obey the Lewis
Fugacity Rule - ai Xi
- We can also now write
- ?i - ?i RT ln Xi
- which is considered another form of Raoults Law.
61Activity relations for an ideal binary system.
It turns out that these relations hold not only
for liquid and gaseous solutions, but also for
solid solutions.
62NON-IDEAL MIXING
- As already discussed, most real solutions do not
conform to Raoults Law over the entire
compositional range. - However, whether solid, liquid or gas, in many
solutions, the component in excess (solvent)
follows Raoults Law and the minor component
(solute) follows Henrys Law over a limited range
at low mole fractions.
63Positive deviation from Raoults Law
64ANOTHER NIFTY APPLICATION OF THE GIBBS-DUHEM
EQUATION
- Task Prove that, if the solute in a binary
solution obeys Henrys Law, then the solvent
obeys Raoults Law. - Starting with the Gibbs-Duhem equation for a
binary system - and dividing through both sides by nA nB we get
- At low pressures we have d?i RT dln Pi
65- So we can now write
- Now if component A is the solute and obeys
Henrys Law we have PA Kh,AXA - Taking the natural logarithm of both sides we
have - ln PA ln Kh,A ln XA
- Now differentiating we get
- d ln PA d ln XA
- so now
66- Now -dXB dXA so
- Now we integrate from XB 1 to XB XB
- where PB is the partial pressure of B when XB
1, i.e., the partial pressure of pure B.
Raoults Law!
67ACTIVITY COEFFICIENTS
- The ideal solution is useful as a model with
which real solutions are compared. - This comparison is effected by taking the ratio
of the activity of the real solution relative to
that of the ideal solution. This ratio is called
the activity coefficient. - Deviations from Raoults Law are expressed by the
Raoultian activity coefficient ?R - ai ?R,iXi
68- Deviations from Henrys Law are expressed by the
Henryian activity coefficient ?H - ai ?H,iXi
- Activity coefficients, because they are ratios of
activities, are unitless. - A major difference between the two types of
activity coefficients is that - ?R ? 1 as X ? 1, but
- ?H ? 1 as X ? 0
- Thus, ?H is usually more useful for solutes in
dilute solutions.
69IV. STANDARD STATES
70STANDARD STATES
- Because the activity is the ratio of two
fugacities, i.e., - ai ?i/?i
- the value of the activity depends on the
reference state chosen for ?i. This state we
usually refer to as the standard state. - The choice of the standard state is completely
arbitrary. - The standard state need not be a real state. It
is only necessary that we be able to calculate or
measure the ratio of the fugacity of the
constituent in the real state to that in the
standard state.
71A STANDARD STATE HAS FOUR ATTRIBUTES
- Temperature
- Pressure
- Composition
- A particular, well-defined state (e.g., ideal
gas, ideal solution, solid, liquid, etc.) - If desirable, we can permit T or P to be
variable, i.e., on a sliding scale.
72STANDARD STATES FOR GASES
- Single Ideal Gas
- Starting with the relationship ?2 - ?1 RT ln
(P2/P1) - we can assign our standard state to be the ideal
gas at 1 bar and any temperature. In this case we
can write ? - ? RT ln P - and ? - ? is the difference in chemical
potential between an ideal gas at T and P, and an
ideal gas at T and 1 bar.
73- Ideal mixture of ideal gases
- For such a mixture we can write
- ?1 - ?1 RT ln (X1P)/(X1P)
- If we choose our standard state to be the pure
ideal gas 1 at any temperature and 1 bar, then
X1 1 and P 1, so ?1 - ?1 RT ln (X1P)
RT ln P1 - Non-ideal gases
- For non-ideal gases we would write
- ?1 - ?1 RT ln (f1/f1)
- but recall that lim (fi/Pi)Pi?0 1. So if we
chose our standard state to be the pure, ideal
gas at any temperature and P 1 bar, we get
74- ?1 - ?1 RT ln f1
- This equation is frequently written, but rarely
understood. It only has meaning if the standard
state is specified to be the pure ideal gas at
any temperature and 1 bar. - This is the most commonly chosen standard state
for gases and supercritical fluids. However,
there is no reason why this particular standard
state has to be chosen. We could just as easily
choose 1) the pure ideal gas at any T and 10
bars 2) a pure real gas at 25C and 1 bar 3) a
specific mixture of gases at any T and ? bars or
4) any other well-defined standard state.
75LIQUIDS AND SOLIDS
- The following equation applies to liquids and
solids as well - ?i - ?i RT ln (fi/fi)
- Fixed pressure standard state
- The standard state is chosen to be the pure phase
at the temperature of interest and 1 bar. Then
fi 1, so ai fi. In this case, it is
necessary to know fi at each and every set of P-T
conditions of interest. - Variable pressure standard state
- The standard state is the pure phase at the
pressure and temperature of interest.
76- Under these conditions, fi fi, so ai 1. The
only way the activity of a solid deviates from
unity under this standard state is when the solid
is not pure, but is a solid solution. - It may seem that the second standard state is
easier to deal with in terms of pressure
corrections. However, with the first standard
state, the pressure correction is applied to fi,
whereas in the second standard state, the
correction is applied to ?i. In either case,
volume data for the constituent are required to
make the correction.
77AQUEOUS SOLUTIONS
- The activities of solutes in dilute solutions are
more closely approximated with Henrys Law than
Raoults Law. Thus, a somewhat different standard
state is applied. We start with the equation
expressing the difference in chemical potentials
between two solutions with different molalities - ?i - ?i RT ln (?Hm/?Hm)
- If we let one solution be the standard state, we
can write - ?i - ?i RT ln (?Hm)/(?Hm)
78- We then define the standard state to be the
hypothetically ideal one-molal solution at the
temperature and pressure of interest. Under these
conditions ?H 1 and m 1, so (?Hm) 1, and
we write - ?i - ?i RT ln ?Hm
- This somewhat strange standard state is
necessary, because if we let the standard state
be the infinitely dilute solution, we would have
?H 1 and m 0, so (?Hm) 0, which would
result in an undefined value of - ?i - ?i RT ln (?Hm)/ (?Hm)