Title: AST Senior Review Major Recommendations
1Instrumentation ConceptsGround-based Optical
Telescopes
Keith Taylor (IAG/USP)? Aug-Nov, 2008
Aug-Sep, 2008
IAG-USP (Keith Taylor)?
2The Fabry-Perot(French translation Perot-Fabry)
- Fabry-Perot etalon works by constructive
interference of light from multiple reflections
between two exactly parallel surfaces - Usually a gap between two precisely manufactured
plates of some material - glass for an optical FP
- sapphire for infra-red FP
- The gap is usually air (or vacuum)
- Interference Filters (IFs) have high refractive
index materials. - Inner surfaces are coated with a reflective
surface.
3 Fabry-Perot
- Light enters etalon and is subjected to multiple
reflections - Transmission spectrum has numerous narrow peaks
at wavelengths where path difference results in
constructive interference - need blocking filters to use as narrow band
filter - Width and depth of peaks depends on reflectivity
of etalon surfaces finesse
4FP notation
- ? refractive index of air
- a amplitude of incident ray
- r fraction of amplitude reflected light at
air/glass interface - r fraction of amplitude of reflected light at
glass/air interface - t fraction of amplitude transmitted light at
air/glass interface - t fraction of amplitude transmitted light at
air/glass interface - l gap between reflective surfaces
- ? angle of incidence
- m order of interference
- ? wavelength of radiation k wave number
(2?c/?) - ? phase difference between successive
reflective rays
5Stokes' treatment of reflectionat a surface
- The principal of reversibility states that if you
reverse the direction of all rays at a surface,
the amplitudes will remain the same.
Reversibility implies att arr a art
art 0
Therefore r ?r tt (1 ? r2)
6 Reflectivity r Transmissivity t (1
? r)
atr8t
atr6t
atr4t
atr2t
att
By inspection, the reflective rays obey ARei?
a(r (1 ? r2)rei? r3e2i? r5e3i?
?
l
7Convert from amplitudesto intensities
To get the transmitted intensity (IT) multiply
Aei? by its complex conjugate
8 from which we can derivethe Airy Function
and the reflected intensity R r2
The FP Airy Function
9FP in reflection and transmission
- IT is a maximum when sin(?/2) 0
- ie when 2?l.cos? m?
- Constructive interference
- This is also the condition for when
- IR is a minimum
- Destructive interference
NB For zero reflection all beams after the first
reflection are destructive of this first
reflection.
10Free Spectral Range (FSR ??) Finesse (N)
11More games with Finesse
This reduces to the familiar expression R
mNR the product of the (order of recombining
beams) In turn this means that we can identify
the finesse N with the of recombining beams (or
the e-fold decay of that quantity).
12Problems with absorptionin the coatings
- For the maximum transmitted intensity the
important quantity is (A/T). Even though A may
be very small, if T is also small (hence R
large), (A/T) may become large and the Tmax will
may be very low. Eg - Let R 99.7 and A 0.2 ? T 0.1
- Max. Intensity 11
- Let R 99.7 and A 0.29 ? T 0.01
- Max. Intensity 0.11
What is happening physically is that while for
each reflection there is very little loss, the
reflectivity is so high that there are many
effective reflections and the total loss becomes
large.
13FPs are dirty OK for emission-lines (HII
regions) (Spirals) (PNe) Not OK
for absorption-lines (Stars) (E-galaxies)
14FPs in practice
- Fabry-Perots are generally used in high order m
to give high resolving power, the free spectral
range (FSR ?/m) is therefore small. - Large gap (d) gives
- Large order (m 2?d.cos?/?)
- Large resolution (R mN)
- Small free spectral range (FSR ?/m)
- Small gap (d) gives
- Problems as d ? 0
FP
IF
15FP interference fringes
Recall Constructive (transmission)
interference, or Destructive
(reflection) interference when 2?d.cos? m?
Note cylindrical symmetry of fringes - cos? term -
White high intensity Black low intensity
16What you see with your eye
Emission-line lab source (Ne, perhaps) note the
yellow fringes
- Orders
- m
- (m-1)
- (m-2)
- (m-3)
-
17FP applications (traditional)
This converts easily to R ?/??
8/?J2 or in other words, R? 2?
- Lets do some typical numbers
- Say DT 4m d 50mm, then for R 20,000 ?J
50 arcsec - cf Grating in Littrow condition R
2d.tan?/?DT - With the same parameters, taking ? 30º Slit
width ? 0.15 arcsec - This is known (in some quarters) as the Jacquinot
Advantage - but why stop there?
18FP with Area Detectors
- FP interferograms
- Confocal with sky image
- Originally with photographic plates
- Good for line emission typically H?
- Fringe distortions due to changes in wavelength
- Used to map velocity fields in late-type
galaxies
- Fundamental ambiguity
- Is fringe distortion due to
- Velocity field perturbation?
- Flux enhancement?
- or both?
19Partial solution Change the gap and repeat
interferogram
20Why only take 2 interferograms?Why not take 2N?
The birth of the TAURUS concept
- Note A single interferogram only contains
(1/N)th of in spatial information - Scanning the FP across a full FSR is a natural
way to - Recover ALL of the spatial information
- Resolve the fundamental ambiguity in the
individual interferograms - Scanning can be achieved in 3 ways
- Changing ? - by tilting the FP or by moving the
image across the fringes - as in photographic interferograms (to
partially resolve ambiguity) - Changing ? - by changing the pressure of a gas
in the FP gap - as in 0th dimensional scanning with eg
propane - Scanning d - by changing the physical gap
between the plates - very difficult since need to maintain
parallelism to ?/2N, at least
TAURUS QI etalons IPCS c1980
21Queensgate Instruments (ET70)
22Queensgate Instruments (Capacitance Micrometry)
FP etalons
- Construction
- Super-flat ?/200 base
- Centre piece (optical contact)
- Top plate
- Capacitors
- X-bridge
- Y-bridge
- Z-bridge ( stonehenge)
Scanning d over 1FSR m ? (m-1) d ? d (?/2)
23Alec Boksenberg and theImage Photon Counting
System (IPCS)
Perfect synthesis
24How big a field?
- From before, Jacquinot central spot given by
- R? 2?
- or R 8?2/?2 8?2(d/DT)2/?J2,
- where ?J is the angle on the sky.
However, given an array detector, we can work
off-axis So, how far? Answer Until the rings
get narrower than ? 2 pixels (the seeing disk)
Now, from the Airy Function we obtain d?/d?
-1/?0.sin(?) The full TAURUS field, ?F is
then ?F 2?2(d/DT)2/R?
?F/?J 20, typically or 400 in ?
25TAURUS Datacube
- Recalling the phase delay equn
- m? 2?l.cos?
- For small values of ?
- ? goes as 1 (?2/2)
- where ? ? tan-1(y-y0/x-x0)
- and (x0,y0) centre of FP fringes
- ?(x1,y1) is shifted in z-dirn
- w.r.t. ?(x0,y0)
- and this ?-shift is thus
- parabolic in ?
- It is also periodic in m. We thus refer to
this shift as a - Phase-correction
- So the surface of constant ? is a
26Wavelength Calibration(converting z to ?)
As shown, surfaces of constant ?, as seen in an
(x,z)-slice are defined by a set of nested
parabolæ, equally spaced in z. Any (x,y)-slice
within the cube cuts through these nested
paraboloids to give the familiar FP fringes
(rings).
Now ?-calibration requires transforming z ? ?
where l(z) l(0) az a is a constant of
proportionality.
Constructive interference on axis (x0,y0)
gives az0 m?0/2? - l(0) but an off-axis
(x,y) point transmits the same ?0 at (z0 pxy)
where apxy l(z0).(sec?xy 1)
27Phase Correction
The 2D phase-map, p(x,y), can be defined such
that p(x,y) m?z0(sec? 1) The phase-map,
p(x,y), can be obtained from a ?-calibration
data-cube by illuminating the FP with a diffuse
monochromatic source of wavelength, ?.
Note Phase-map is discontinuous at each ?z
28The Phase-Map
The phase-map is so called since it can be used
to transform the raw TAURUS cube, with its
strange multi-paraboloidal iso-wavelength
contours into a well-tempered data cube where all
(x,y)-slices are now at constant wavelengths.
The process is called phase-correction since it
represents a periodic function of period, ?z. ie
If the z-value (z) of a phase-shifted pixel
exceeds the z-dimensions of the data-cube, then
the spectra is simply folded back by one FSR to
(z - ?z).
It will be noted that the phase-map (as defined
previously) is independent of ? and hence in
principle any calibration wavelength, ?cal, can
be used to phase-correct a observation data-cube
at an arbitary ?obs, remembering that ?? ? ?2
?z ?/2
But also, the phase-map can be expressed in
?-space as ??xy ?0(1 - cos?) and hence is
also independent of gap, l, and thus applicable
to all FPs at all ?.
29Order (m) and gap (l) determination
The periodicity of the FP interference fringes
makes ?-calibration non-trivial. The
paraboloidal mapping from z ? ? doesnt exactly
help, either!
Nevertheless, using 2 calibration
wavelengths Say ?1 and ?2, peak on-axis at z1
and z2 The trick is to find m1 (and hence m2),
the order of interference. From m we can infer
the gap, l , and hence obtain a ?-calibration
where az0 m?0/2? - l(0) Then
If m1 can be estimated (from manufacturers specs
or absolute capacitance measures) then we can
search for a solution where m2 is an integer.
This can be an iterative process with several
wavelength pairs. Clearly the further ?1 and ?2
are apart, the more accuracy is achieved.
30Wavelength Calibration
If m1 can be estimated (from manufacturers specs
or absolute capacitance measures) then we can
search for a solution where m2 is an integer.
This can be an iterative process with several
wavelength pairs. Clearly the further ?1 and ?2
are apart, the more accuracy is achieved.
Once the interference order, m1, for a known
wavelength, ?1, has been identified then
wavelength calibration is given by
31FPP in collimated beam
- Interference fringes formed at infinity
- Sky and FP fringes are con-focal
- Detector sees FP fringes superimposed on sky
image
FP
IF
32FPI in image plane
- Interference fringes formed at infinity
- Sky and FP fringes are not con-focal
- Detector sees FP plates superimposed on sky
image - ie No FP fringes seen on detector
- FP is not perfectly centred on image plane (out
of focus) to avoid detector seeing dust particles
on plates.
FP
IF
33FP (or Interference Filter)in image plane
The FP still acts as a periodic monochromator but
the angles into the FP (or IF) must not exceed
the Jacquinot criteria, which states that
?2 At f/8 ? 2.tan-1(1/16) 7.2º, so R 500 At f/16 ? 2.tan-1(1/32) 3.6º, so R 2,000
Note the FoV is determined not by the width of
the fringes but by the diameter of the FP.
Also, an IF is simply a solid FP (? 2.1) with
very narrow gap.
34(No Transcript)
35FB observations of NGC 7793 on the 3.60 m. Top
left DSS Blue Band image. Top right Spitzer
infrared array camera (IRAC) 3.6 µm image. Middle
left Ha monochromatic image. Middle right Ha
velocity field. Bottom position-velocity (PV)
diagram.
36FB observations of NGC 7793 on the 36 cm. Top
left DSS Blue Band image. Top right Spitzer
IRAC 3.6 µm image. Middle left Ha monochromatic
image. Middle right Ha velocity field. Bottom
PV diagram.
37ADHOC screen shot (Henri)
38ADHOC screen shot (Henri)