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Section 15'1 Local Extrema

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Definition of Local Extrema. Let P be a point in the domain of f. Then ... Definition of Critical Points ... Second Derivative Test for Functions of Two Variables ... – PowerPoint PPT presentation

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Title: Section 15'1 Local Extrema


1
Section 15.1Local Extrema
2
Definition of Local Extrema
  • Let P be a point in the domain of f. Then
  • f has a local maximum at the point P0 if f(P0 )
    f(P) for all points P near P0
  • f has a local minimum at the point P0 if f(P0 )
    f(P) for all points P near P0
  • These definitions are similar to those we saw
    back in single variable calculus
  • How did we determine local extrema back then?

3
Definition of Critical Points
  • Suppose a function has a local maximum at P0
    which does not lie on the boundary of the domain
  • Recall that the gradient vector (if it is
    defined and nonzero) points in the direction of
    maximum increase
  • What is direction of the maximum rate of increase
    at P0?
  • Thus we have critical points where the gradient
    is the zero vector or is undefined

4
Definition of Critical Points
  • P0 is a critical point of f if

5
Example
  • Find the critical points of the following
    functions
  • We will use maple to determine what is going on
    at these critical points
  • We need a test for determining whats going on at
    our critical points

6
Second Derivative Test
  • Old Stuff Suppose f has a critical point at x
    a, continuous first and second derivatives (at x
    a) and f(a) 0, then
  • Using a 2nd degree Taylor polynomial we have
  • Which is a quadratic whose concavity depends on
    the sign of f(a)

7
Second Derivative Test for y f(x)
  • Suppose f has a critical point at x a,
    continuous first and second derivatives (at x
    a) and f(a) 0, then
  • f(a) gt 0 ? f(a) is a local minimum
  • f(a) lt 0 ? f(a) is a local maximum
  • f(a) 0 ? no conclusion can be drawn

8
Second Derivative Test for Functions of Two
Variables
  • Suppose Q is defined by
  • Then
  • Note

9
  • Based on this form, what do you think we need in
    order to have our graph be concave up in the x
    direction? y direction?

10
  • Given
  • If a gt 0 and 4ac-b2 gt 0 ? Q has a local min at
    (0,0)
  • If a lt 0 and 4ac-b2 gt 0 ? Q has a local max at
    (0,0)
  • If a gt 0 and 4ac-b2 lt 0 ? Q has a saddle point at
    (0,0)
  • If a lt 0 and 4ac-b2 lt 0 ? Q has a saddle point at
    (0,0)
  • If 4ac-b2 0 no conclusion can be drawn

11
Second Derivative Test for Functions of Two
Variables
  • Suppose f(x,y) has continuous 1st and 2nd parital
    derivatives at (0,0), that (0,0) is a critical
    point and f(0,0) 0. From 14.7 we know

12
  • Given
  • we have
  • So
  • Thus we have our discriminant and we can restate
    our previous conclusions

13
Second Derivative Test for Functions of Two
Variables
  • If f has a critical point at P0 then the
    discriminant is
  • If D gt 0 and
  • fxx(P0) gt 0 ? f(P0) is a local minimum
  • fxx(P0) lt 0 ? f(P0) is a local maximum
  • If D lt 0 ? f(P0) is a saddle point
  • If D 0 ? no conclusion can be drawn from the
    second derivative test
  • Note Since we solved for this test by completing
    the square in terms of x, we use the second
    partial of x

14
Examples
  • 2 from the book
  • 4 from the book
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