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Chapter 14 Chemical Equilibrium

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There is only one equilibrium constant for a given reaction ... Show that K is the same for 2 different initial conditions. Equilibrium Involving Pressures ... – PowerPoint PPT presentation

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Title: Chapter 14 Chemical Equilibrium


1
Chapter 14 Chemical Equilibrium
  • Equilibrium Conditions
  • Example Reaction NO2 NO2
    N2O4
  • (brown)
    (colorless)
  • This reaction proceeds to the right at the start
  • But, it never goes all the way to completion. It
    reaches a point where the forward and reverse
    reactions are going at the same rate.
  • DNO2 0
  • DN2O4 0
  • Chemical Equilibrium The state where the
    concentrations of all reactants and products
    remain constant with time.

2
  • Some reactions almost reach completion before
    equilibrium is achieved. We say the equilibrium
    lies to the right.
  • 2H2 O2 2H2O
  • Some reactions barely get started before reaching
    equilibrium. We say the equilibrium lies to the
    left.
  • 2CaO 2Ca O2
  • Equilibria are Dynamic
  • Even though DNO2 0, the forward and reverse
    reactions are both occurring.
  • At equilibrium, there is no net change in
    concentration, even though individual molecules
    are constantly reacting.
  • Reaction 1H2O 1CO
    1H2 CO2

3
  • At equilibrium, concentrations dont change, even
    though individual molecules do
  • The equilibrium lies to the right for this
    reaction. There are more products than reactants
    at equilibrium.
  • Why does Equilibrium Occur?
  • Molecules react by colliding (Kinetic theory)
  • The number of collisions depends on concentration
  • H2O and CO are decreased by the forward
    reaction, so the forward reaction slows down.
  • H2 and CO2 are increased by the forward
    reaction, so the reverse reaction speeds up.
  • Eventually, the forward and reverse reactions
    reach the same rate

4
  • Factors that determine where the equilibrium
    position is
  • Initial concentrations
  • Energies of the reactants and products
  • Entropy (disorder is favored)
  • Reaction rates of the forward and reverse
    reactions

5
  • Sample Reaction N2 3H2
    2NH3
  • When we mix any concentrations of these gases at
    room temperature, there are no changes in
    concentration.
  • We might be at equilibrium
  • The reaction rates might be very slow at these
    conditions.
  • The NN bond is very strong (432 kJ/mol) and hard
    to break
  • Entropy favors no forward reaction
  • When a catalyst is added and the reaction is
    heated, the concentrations do change until a real
    equilibrium is reached.
  • H2 disappears three
  • times as fast as N2
  • NH3 appears twice as
  • fast as N2 disappears.

6
  • Equilibrium Constants
  • The Law of Mass Action
  • This is an empirical law discovered in 1864
  • Every reaction has a constant associated with it
    telling us where the equilibrium position is.
  • aA bB cC dD
  • K Equilibrium Constant tells us where the
    equilibrium position is
  • K gt 1 tells us the equilibrium lies to the right
  • K lt 1 tells us the equilibrium lies to the left
  • If we know the concentrations, we can find K from
    its equation
  • K is written without units, even in cases where
    there are units left not cancelled. This is
    correct for nonideal behavior of molecules.
  • Example Write K for 4NH3 7O2
    4NO2 6H2O

If K 1, halfway
7
  • Example N2 3H2
    2NH3
  • Find K if NH3 3.1 x 10-2, N2 0.85, H2
    3.1 x 10-3
  • Find K for the reverse reaction
  • Find K for 0.5 N2 1.5 H2
    NH3
  • Conclusions
  • If K is for a forward reaction, and K is for the
    reverse K 1/K
  • If you multiply a reaction by n, K Kn
  • Equilibrium Position the set of equilibrium
    concentrations
  • There is only one equilibrium constant for a
    given reaction
  • The infinite equilibrium positions depend on
    initial concentrations

8
  • Example 2SO2 O2
    2SO3
  • Show that K is the same for 2 different initial
    conditions
  • Equilibrium Involving Pressures
  • 1. Ideal gas law PV nRT

9
  • N2 3H2 2NH3
  • We can rewrite K using concentration C
  • Since C is proportional to P, the partial
    pressure, we can write a similar equilibrium
    constant KP
  • Example Find KP for 2NO Cl2
    2NOCl
  • PNOCl 1.2 atm, PNO 0.05 atm, PCl2 0.3
    atm
  • How are KP and K related?
  • KP K(RT)Dn
  • Dn (sum of product coefficients) (sum of
    reactant coefficients)
  • 5. Example Find K from KP in the example
    directly above

10
  • Heterogeneous Equilibria
  • Types of Equilibria
  • Homogeneous all species in the same phase (so
    far, gas phase)
  • Heterogeneous species in multiple phases
  • 2CO(g) C(s) CO2(g)
  • Experiments show that K is not effected by how
    much pure solid or liquid is present.
  • Pure solids and liquids are treated as constant
    concentrations, and therefore do not appear in
    the equilibrium expression

11
  • Examples 2H2O(l) 2H2(g)
    O2(g)
  • 2H2O(g) 2H2(g)
    O2(g)
  • Applications of Equilibrium Constants
  • Equilibrium Constants (K) tell us many things
  • Will the reaction go forward? (K gt 1, it will
    move forward)
  • Are current conditions at equilibrium?
  • What conditions will be present when equilibrium
    is achieved?
  • Example A(g) B (g) C (g)
    D (g)
  • Start with 9A molecules and 12B molecules
  • What are the conditions at equilibrium?
  • a) Guess that 5C, 5D, 4A, and 7B

12
  • Can we find out mathematically instead of
    guessing?
  • At Equilibrium
  • Try x 8
  • Yes, we are at equilibrium when x 8
  • This is a general way to solve an equilibrium
    problem ICE Table
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