Title: Mass Balance
1Mass Balance
- Use Phosphorus
- (Other nonvolatile elements are similar)
2Concept of Mass Balance
- Elements are neither created nor destroyed.
- Elements which enter a system either exit the
system or are stored. - The composition of animal productsmeat, eggs,
milk, etc. is not significantly affected by what
the animal eats. (Diet can control flavor, odor,
etc.)
3Some Exceptions
- Bones are influenced by mineral intake
- Calcium, Phosphorus, for example.
4Farm Produced Feed
Gases
Ration
Manure
Mineral Supplements
Milk
5How much P was in the manure?
- We know how much P was in the supplement
- We know how much P was in the feed
- We know how much milk was produced
- The P content of milk is constant0.09
- There is no gaseous phase in P
- Hencewe know how much P is in manure
6Phosphorus in Manure
- P manure P feed P milk
- P feed P farm feed P supplement
- P milk Total milk x 0.009
7Example
- A mature dairy cow consumes 55 lb of dry matter
per day. It is 0.42 P. - She produces 70 lb of milk per day.
- P manure 55 x 0.0042 70 x 0.0009
- P manure 0.17 lb P
8Tradeoffs in Nutrient Balance
- Some phosphorus is exported
- the animals either gain weight which is some
fraction P and are marketed - Or they produce a product which is some fraction
P and it is marketed - If more P is imported in supplement and/or
fertilizer, there is net import of P.
9Enterprise Level BalanceDairy
- Phosphorus
- Dr. Beede exampledaily intake of 100 g
- 32 g goes to milk
- 68 g goes to manure (assume no growth)
- 68 g/d x 365 d x (454 g/lb) 54.67 lb (P)
- 124.3 lb (P2O5)
10Differences with other Elements
- Carbon
- Some is respired as CO2
- Nitrogen
- Can evolve as ammonia, N2, or NOx
- Is stored in protein
- Some other elements have a gaseous phase
11Enterprise Level BalanceDairy
- Carbon
- Where does it go? (Beede, p. 27)
- Heat 40
- Manure 35
- Milk 20
- Methane 5
12Carbon, cont
- Daily DM intakeabout 50/d
- Annual intake18,000
- Assume all corn silage
- Yield at 24 T/A
- You need
- (18,000)/(24 x 2,000) 0.375 A
- By the waythats about 300 lb of methane!
13There is a Difference Among Animals
- The biggest difference is in digestive systems
- Ruminantscan process fiber
- Non-ruminantscant
- Because of differences in systems
- There is a difference in conversion of feeds
- There is a difference in ability to use natural P
14Ability to Convert Feed
- Feed ConversionFeed to gain ratio (FGR)
- Numbers to memorize
- 1 Fish
- 2 Poultry
- 3 Swine
- 4 Cattle
15Ruminants and Non-ruminants
- Ever had the joy of releasing gas produced in the
rumen of a cow? - Chewing is the first step in processing the
feed. This is no small task as the cow makes
40,000 to 60,000 jaw movements per day as it
chews and rechews regurgitated feed. Then it
passes down a 2 1/2 to 3 foot tube called the
esophagus into a large fermentation vat of 40 to
50 gallon capacity. Here digestion of feed goes
on by 500,000 billion bacteria and 50 billion
protozoa living and multiplying there. These
small organisms have several unique
characteristics which allow the cow to thrive in
situations which would be impossible for other
animals to live. They digest fiber found in hay,
silage, and pasture for energy, make protein from
nitrogen, and synthesize B vitamins for their
host, the cow.
16Ability to Utilize Natural P
- P naturally occurs in feed
- Some of it is in phytic acid form, some isnt
- Ruminants have an enzyme (phytase) that makes the
non-available stuff available - Phytase is available to add to feed, and it will
make more P available. Not all phytase is equal.
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18Dairy P continued
- Assume 24 T/A silage production
- Uptake (MWPS-18, p 10.3)62.5 lb/A
- 124.3 lb/ 62.5 lb/A 2 A per cow
- Its obvious that there is great savings for
reducing P feeding. - Dr. Beede example would imply that we could
reduce P feeding 30 IF we could improve
availability
19Dairy P continued
- Reduce P intake by 30. Now feed 70 g/d.
- Milk is still 32 g/d
- Manure is now 38 g/d
- Required land is now
- 38 g/d x 365 d / 454 g/lb 30.55 lb P
- 69.4 lb P2O5
- 69.4 lb/62.5 lb/A 1.11 A per cow.
20Enterprise level balanceSwine
- Lets assume a relatively simple operation
growing feed (corn and soybeans), feeding
finishers, and applying manure.
21Odor
100 Pigs
Water
Products
Waste
Feed
Chemicals
Fertilizer
Rain
Nutrients
Ration
Land Application
Corn
Soil 10 A
Supplement
Soybeans
Runoff
Drainage
22P based manure application
- Following NRC P recommendations
- 150 hog needs 12.42 g P daily (5.03 g available)
- average over 50 to 250 lbs is 11.56 g
- Assume a 25 soybean meal, 75 corn ration
- Assume 46 bu beans and 148 bu corn
23Feed and Nutrients per Hog
- From 50 to 250, hog will consume 510 of feed.
- The feed will include 2.264 lb P
- The hog will retain 1.053 lb P
- The balance--1.211 lb goes back to the land
- The crop will take up 0.432 lb
- The balance--0.779 lb requires more land
- 0.22 A soybeans OR 0.16 A corn OR 0.17A in
proportion
24Quick Check on Area Needed
Animals per Acre Animals per Acre
Type Best Poss Likely
Finishing Hogs 15 10
Finishing Spaces 5 3.3
Farrow to Finish (per sow) 0.5
Lactating Cow w/ heifers 1.0 0.67
Lactating Cow w/o heifers 0.5 0.33
25Corn uptake N/PversusN/P of manure
- Corn Manure
- N/P 2.5 1.32 (fresh)
- 0.66 (field)
- Overall result is if we apply based on crop
uptake of actual field N, we will overapply P
by Corn 2.5/0.66 3.8 - Thats an excess of about 150 lb/A!
26Why 75 Corn, 25 Soybean
- My Theory
- Corn soybeans rotation
- 148 bu corn is 8288 lb corn per acre
- 46 bu soybeans is 2760 lb soybeans per acre
- Corn is 8288/(82882760) 75
- Soybeans are 2760/(82882760) 25
- The Outcome is the same for a 3-crop
rotationcorn, soybeans, wheat, e.g.
27County Level Balance
- Look at crops as a use (removal) of nutrients
- Look at manure as a source of nutrients
- Supplement as necessary
- It tells you Michigan farmers ignore the nutrient
value of manure
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30The State of Michigan
31Whats the take-home message?
- Give credit for nutrients in manure.
- Apply additional fertilizer as needed AFTER
giving credit. - Put the manure where its needed, not where its
easy to get rid of.