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GENETIC PROBLEMS

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The mother of the wire-haired male was smooth-haired. ... mother carrier or colorblind. daughter: XcXc - colorblind. Question #5 ... – PowerPoint PPT presentation

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Title: GENETIC PROBLEMS


1
GENETICPROBLEMS
2
Question 1
  • How many different kinds of gametes could the
    following individuals produce?
  • 1. aaBb
  • 2. CCDdee
  • 3. AABbCcDD
  • 4. MmNnOoPpQq
  • 5. UUVVWWXXYYZz

3
Question 1
  • Remember the formula 2n
  • Where n of heterozygous
  • 1. aaBb 2
  • 2. CCDdee 2
  • 3. AABbCcDD 4
  • 4. MmNnOoPpQq 32
  • 5. UUVVWWXXYYZz 2

4
Question 2
  • In dogs, wire-haired is due to a dominant gene
    (W), smooth-haired is due to its recessive allele
    (w).
  • WW, Ww wire haired
  • ww smooth haired

5
Question 2A
  • If a homozygous wire-haired dog is mated with a
    smooth-haired dog, what type of offspring could
    be produced.
  • W W
  • w
  • w

6
Question 2A
  • W W
  • w Ww Ww
  • fg F1
    generation
  • w Ww Ww all heterozygous

7
Question 2B
  • What type(s) of offspring could be produced in
    the F2 generation?
  • Must breed the F1 generation to get the F2.
  • Results of F1 Cross Ww x Ww

8
Question 2B
  • W w
  • W WW Ww F2 generation
  • w Ww ww
  • genotype 121 ratio
  • phenotype 31 ratio

9
Question 2C
  • Two wire-haired dogs are mated. Among the
    offspring of their first litter is a
    smooth-haired pup.
  • If these, two wire-haired dogs mate again, what
    are the chances that they will produce another
    smooth-haired pup?
  • What are the chances that the pup will
    wire-haired pup?

10
Question 2C
  • W w
  • W WW Ww F2 generation
  • w Ww ww
  • - 1/4 or 25 chance for smooth-haired
  • - 3/4 or 75 chance for wire-haired

11
Question 2D
  • A wire-haired male is mated with a smooth-haired
    female. The mother of the wire-haired male was
    smooth-haired.
  • What are the phenotypes and genotypes of the pups
    they could produce?
  • Show the results of crossing Ww x ww

12
Question 2D
  • W w
  • w Ww ww
  • w Ww ww
  • phenotypes 11 ratio
  • genotypes 11 ratio

13
Question 3
  • In snapdragons, red flower (R) color is
    incompletely dominant over white flower (r)
    color.
  • The heterozygous (Rr) plants have pink flowers.
  • RR - red flowers
  • Rr - pink flowers
  • rr - white flowers

14
Question 3A
  • If a red-flowered plant is crossed with a
    white-flowered plant, what are the genotypes and
    phenotypes of the plants F1 generation?
  • RR x rr

15
Question 3A
  • R R
  • r Rr Rr F1 generation
  • r Rr Rr
  • phenotypes 100 pink genotypes 100
    heterozygous

16
Question 3B
  • What genotypes and phenotypes will be produced in
    the F2 generation?
  • Rr x Rr

17
Question 3B
  • R r
  • R RR Rr F2 generation
  • r Rr rr
  • phenotypes 121 ratio
  • genotypes 121 ratio

18
Question 3C
  • What kinds of offspring can be produced if a
    red-flowered plant is crossed with a
    pink-flowered plant?
  • RR x Rr

19
Question 3C
  • R R
  • R RR RR
  • r Rr Rr
  • 50 red flowered
  • 50 pink flowered

20
Question 3D
  • What kind of offspring is/are produced if a
    pink-flowered plant is crossed with a
    white-flowered plant?
  • Rr x rr

21
Question 3D
  • R r
  • r Rr rr
  • r Rr rr
  • 50 white flowered
  • 50 pink flowered

22
Question 4
  • In humans, colorblindness (cc) is a recessive
    sex-linked trait.
  • Remember XX - female
  • XY - male

23
Question 4A
  • Two normal people have a colorblind son.
  • What are the genotypes of the parents?
  • XCX_? x XCY
  • What are the genotypes and phenotypes possible
    among their other children?

24
Question 4A
  • XC Y ? parents
  • XC XCXC XCY
  • Xc XCXc XcY
  • 50 female (one normal, one a carrier)
  • 50 male (one normal, one colorblind)

25
Question 4B
  • A couple has a colorblind daughter.
  • What are the possible genotypes and phenotypes of
    the parents and the daughter?

26
Question 4B
  • Xc Y
  • XC XCXc XCY
  • Xc XcXc XcY
  • parents XcY and XCXc or XcXc
  • father colorblind
  • mother carrier or colorblind
  • daughter XcXc - colorblind

27
Question 5
  • In humans, the presence of freckles is due to a
    dominant gene (F) and the non-freckled condition
    is due to its recessive allele (f).
  • Dimpled cheeks (D) are dominant to non-dimpled
    cheeks (d).

28
Question 5A
  • Two persons with freckles and dimpled cheeks have
    two children one has freckles but no dimples
    and one has dimples but no freckles.
  • What are the genotypes of the parents? Parents F
    __D__ x F__D__
  • Children F__dd x ffD__

29
Question 5B
  • What are the possible phenotypes and genotypes of
    the children that they could produce?
  • Cross FfDd x FfDd
  • This is a dihybrid cross

30
Question 5B
  • Possible gametes for both FD Fd fD fd
  • FD Fd fD fd
  • FD FFDD FFDd FfDD FfDd
  • Fd FFDd FFdd FfDd Ffdd
  • fD FfDD FfDd ffDD ffDd
  • fd FfDd Ffdd ffDd ffdd

31
Question 5B
  • Phenotype Freckles/Dimples 9
  • Freckles/no dimples 3
  • no freckles/Dimples 3
  • no freckles/no dimples 1
  • Phenotypic ratio will always been 9331 for
    all F1 dihybrid crosses.

32
Question 5B
  • Genotypic ratio FFDD - 1
  • FFDd - 2
  • FFdd - 1
  • FfDD - 2
  • FfDd - 4
  • Ffdd - 2
  • ffDD - 1
  • ffDd - 2
  • ffdd - 1

33
Question 5C
  • What are the chances that they would have a child
    whom lacks both freckles and dimples?
  • This child will have a genotype of ffdd
  • Answer 1/16

34
Question 5D
  • A person with freckles and dimples whose mother
    lacked both freckles and dimples marries a person
    with freckles but not dimples whose father did
    not have freckles or dimples.
  • Cross FfDd x Ffdd
  • Possible gametes
  • FD Fd fD fd x Fd fd

35
Question 5D
  • What are the chances that they would have a child
    whom lacks both freckles and dimples?
  • FD Fd fD fd
  • Fd FFDd FFdd FfDd Ffdd
  • fd FfDd Ffdd ffDd ffdd
  • Answer 1/8

36
Question 6
  • Sixteen percent of the human population is known
    to be able to wiggle their ears.
  • This trait is determined to be a recessive gene.
  • These is a population genetics question.
  • Use the following equation 1 p2 2pq q2

37
Question 6A
  • What of the population is homozygous dominant for
    this trait?
  • q2 16 or .16 ?q2 ?.16
  • q .4
  • then use 1 p q
  • 1 p .4
  • 1- .4 p
  • p .6
  • Now use p2 for answer .62 .36 or 36

38
Question 6B
  • What of the population is heterozygous for this
    trait?
  • We know that q .4 and p .6
  • Now use 2pq for answer 2(.6)(.4) .48 or 48

39
Question 7
  • In dogs, the inheritance of hair color involves a
    gene B for black hair and gene b for brown hair
    b.
  • A dominant C is also involved. It must be
    present for the color to be synthesized.
  • If this gene is not present, a blond condition
    results.
  • BB, Bb - black hair CC, Cc - color
  • bb - brown hair cc - blond

40
Question 7A
  • A brown haired male, whose father was a blond, is
    mated with a black haired female, whose mother
    was brown haired and her father was blond.
  • Male bbCc (gametes bC bc)
  • Female BbCc (gametes BC Bc bC bc)
  • What is the expected ratios of their offspring?

41
Question 7A
  • BC Bc bC bc
  • bC BbCC BbCc bbCC bbCc
  • bc BbCc Bbcc bbCc bbcc
  • Offspring ratios
  • Black 3/8
  • Brown 3/8
  • Blond 2/8 or 1/4

42
Question 8
  • Henry Anonymous, a film star, was involved in a
    paternity case. The woman bringing suit had two
    children, on whose blood type was A and the other
    whose blood type was B.
  • Her blood type was O, the same as Henrys!
  • The judge in the case awarded damages to the
    woman damages to the woman, saying that Henry had
    to be the father of at least one of the children.

43
Question 8A
  • Obviously, the judge should be sentenced to
    Biology. For Henry to have been the father of
    both children, his blood type would have had to
    be what?
  • IA IB ? Answer
  • i IAi IBi
  • i IAi IBi

44
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