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Exploring Chemical Analysis 3e

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The results of these calculations are shown in the table of the next ... probably good to make an additional calculation in this area, say at V = 4 or 5 mL. ... – PowerPoint PPT presentation

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Title: Exploring Chemical Analysis 3e


1
______________________________________
Class, Wednesday, Dec 1, 2004 Announcements
  • Changes from schedule in the syllabus
  • pH and Spectrometer Labs due Friday, Dec 10.
  • Last time we discussed Exam 3 on Friday, Dec
    10. Will you be able to work longer than an hour
    at that time, or do you wish to have Exam 3 on
    Wednesday, Dec 8? The class decided Wed, Dec 8
    for Exam 3. Ill finish lecturing on this
    Friday, so you have Mon and Fri of next week off.
  • Final Exam, 1000 AM, Wed., Dec 15.

2
______________________________________
Titration Curve Problem for a weak acid
  • 40.00 mL of a 0.03320 M alcohol and water
    solution of
  • p-cresol is going to be titrated with a 0.05000 M
    solution of KOH. Select 5 or 6 meaningful points
    for this titration. Use these points to sketch
    the approximate titration curve to be expected.

3
______________________________________
Titration Curve Problem for a weak acid the
solution
  • Let HCres represent the acid p-cresol. The
    chemical equation before the addition of any
    titrant may then be written as
  • HCres H2O lt gt Cres- H3O
  • and Ka Cres- H3O / HCres

4
______________________________________
Titration Curve Problem for a weak acid the
solution
  • The first step is to calculate the volume of KOH
    titrant reach the equivalence point.
  • At the equivalence point,
  • the mmol of H mmol of OH-, or
  • Vacid x Concacid Vbase x Concbase
  • (40.00 mL)(0.03320 M) Vbase x 0.05000 M
  • Vbase 26.66 mL, the volume of KOH at eq. pt.

5
______________________________________
Titration Curve Problem for a weak acid the
solution
  • 2) The following points at selected to calculate
    the values of the pH at those points
  • at VKOH 0.00, 8.00, 20.00, 26.66, 30.00,
    35.00 mL selection of the ½ V eq pt might also
    be helpful because at this point, the pH pKa

6
______________________________________
Titration Curve Problem for a weak acid the
solution
  • 3) The pH values were calculated as described
    last lecture for the points selected. Also,
    recall from last lecture there are two points and
    two regions. They are
  • Vo, weak acid
  • V8.00 and V20.00, buffer region
  • V26.66 , the eq pt, the weak conj base of the
    acid.
  • V 30.00 and V35.00, region after eq pt,
    dilution of
  • excess titrant
  • Selection of the ½ V eq pt (1/2 x 26.66)
    13.33 might also be helpful because at this
    point, the pH pKa. The results of these
    calculations are shown in the table of the next
    slide.

7
______________________________________
Titration Curve Problem for a weak acid the
solution

8
______________________________________
Titration Curve Problem for a weak acid the
solution
Notes 1) This is not a great titration curve
because the break at the eq pt (25.66 mL) is so
small. 2) the change between V 0 and 8 is
large probably good to make an additional
calculation in this area, say at V 4 or 5 mL.

9
______________________________________
Titration Curve Problem for a Weak Base

10
______________________________________
Friday we will discuss the following problem
work on it on your own between now and then.
  • The conjugate acid of the weak base cyclohexamine
    has a pKa 10.57. 30.00 mL of a 0.06000 M
    solution of cyclohexamine is to be titrated with
    a 0.04500 M solution of standard HCl. Find
    points (pH values) at Vo, 0.25 Vept, 0.50 Vept
    0.75 Vept , Vept , 1.1Vept and 1.2 Vept. Use
    these points to sketch a titration curve.
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