Title: Exploring Chemical Analysis 3e
1______________________________________
Class, Wednesday, Dec 1, 2004 Announcements
- Changes from schedule in the syllabus
- pH and Spectrometer Labs due Friday, Dec 10.
- Last time we discussed Exam 3 on Friday, Dec
10. Will you be able to work longer than an hour
at that time, or do you wish to have Exam 3 on
Wednesday, Dec 8? The class decided Wed, Dec 8
for Exam 3. Ill finish lecturing on this
Friday, so you have Mon and Fri of next week off. - Final Exam, 1000 AM, Wed., Dec 15.
-
-
2______________________________________
Titration Curve Problem for a weak acid
- 40.00 mL of a 0.03320 M alcohol and water
solution of - p-cresol is going to be titrated with a 0.05000 M
solution of KOH. Select 5 or 6 meaningful points
for this titration. Use these points to sketch
the approximate titration curve to be expected. -
-
3______________________________________
Titration Curve Problem for a weak acid the
solution
- Let HCres represent the acid p-cresol. The
chemical equation before the addition of any
titrant may then be written as -
- HCres H2O lt gt Cres- H3O
- and Ka Cres- H3O / HCres
-
-
4______________________________________
Titration Curve Problem for a weak acid the
solution
- The first step is to calculate the volume of KOH
titrant reach the equivalence point. - At the equivalence point,
- the mmol of H mmol of OH-, or
- Vacid x Concacid Vbase x Concbase
- (40.00 mL)(0.03320 M) Vbase x 0.05000 M
- Vbase 26.66 mL, the volume of KOH at eq. pt.
-
-
-
5______________________________________
Titration Curve Problem for a weak acid the
solution
- 2) The following points at selected to calculate
the values of the pH at those points -
- at VKOH 0.00, 8.00, 20.00, 26.66, 30.00,
35.00 mL selection of the ½ V eq pt might also
be helpful because at this point, the pH pKa -
-
-
6______________________________________
Titration Curve Problem for a weak acid the
solution
- 3) The pH values were calculated as described
last lecture for the points selected. Also,
recall from last lecture there are two points and
two regions. They are - Vo, weak acid
- V8.00 and V20.00, buffer region
- V26.66 , the eq pt, the weak conj base of the
acid. - V 30.00 and V35.00, region after eq pt,
dilution of - excess titrant
- Selection of the ½ V eq pt (1/2 x 26.66)
13.33 might also be helpful because at this
point, the pH pKa. The results of these
calculations are shown in the table of the next
slide. -
-
-
7______________________________________
Titration Curve Problem for a weak acid the
solution
8______________________________________
Titration Curve Problem for a weak acid the
solution
Notes 1) This is not a great titration curve
because the break at the eq pt (25.66 mL) is so
small. 2) the change between V 0 and 8 is
large probably good to make an additional
calculation in this area, say at V 4 or 5 mL.
9______________________________________
Titration Curve Problem for a Weak Base
10______________________________________
Friday we will discuss the following problem
work on it on your own between now and then.
- The conjugate acid of the weak base cyclohexamine
has a pKa 10.57. 30.00 mL of a 0.06000 M
solution of cyclohexamine is to be titrated with
a 0.04500 M solution of standard HCl. Find
points (pH values) at Vo, 0.25 Vept, 0.50 Vept
0.75 Vept , Vept , 1.1Vept and 1.2 Vept. Use
these points to sketch a titration curve. -
-