Title: Algebra Learning how to solve equations
1AlgebraLearning how to solve equations
2What is algebra all about?
- The primary purpose of algebra is to solve
problems by using equations. Algebraic equations
(equations used in algebra) include a variable.
This variable represents what we are trying to
find out the unknown. - So we use algebra when we need to solve a problem
using an equation.
3How could we use algebra in real life?
- People solve algebraic problems on a daily basis
without even thinking about it. For example, if
we know how many students go to our school and
how many of those students are in junior high, we
can use algebra to solve for the number of high
school students. - Algebra can be used to solve simple problems like
this, but it is much more effective with slightly
more complex problems
4How could we use algebra in real life?
- An example of a more difficult problem we can
solve algebra for, is as follows - Suppose your sister goes shopping with three
weeks allowance, spends 17, and has 7 left
over. What is her weekly allowance? - In this example, we solve using algebra in two
steps, which we will look at later.
5One step equations and -
- The main goal when solving equations is to get
the variable on its own on one side of the equal
sign. - To do this, we have to use reverse operations to
move all numbers to the other side of the equal
sign. - What ever you do, remember the golden rule for
equations
6One step equations and -
- Whatever you do to one side of an equation, do
also to the other side. - Never forget this!
7One step equations and -
- Ex. x 3 8
- Our goal is to get the x by itself on the left,
so we need to move the 3 to the other side with
reverse operations. - x 3 3 8 3
- Notice that we also subtracted 3 on the right,
according to our golden rule. - x 0 5 so x 5
8One step equations and -
- Ex. 7 x 16
- Our goal is to get the x by itself on the left,
so we need to move the 7 to the other side with
reverse operations. 7 is positive, so we
subtract - 7 7 x 16 - 7
- Notice that we also subtracted 7 on the right,
according to our golden rule. - 0 x 9 so x 9
9One step equations and -
- Ex. x 5 13
- Our goal is to get the x by itself on the left,
so we need to move the 5 to the other side with
reverse operations. - x - 5 5 13 5
- Notice that we also added 5 on the right,
according to our golden rule. - x 18
10One step equations and -
- Ex. 16 x 9
- This is a special case after we move the 16,
well be left with - x. Subtract 16 on both
sides. - 16 16 x 9 16
- Now we have - x - 7 We can cancel
the negatives (both sides can be divided by (-1) - x 7
11One step equations and -
- Ex. 4 x 10
- Move the 4 to the left by subracting on both
sides. - 4 4 x 10 - 4
- Now we have - x 6 We cant be left
with a negative variable, so move the negative to
the other side - x - 6
12Practicing One-Step Equations Adding and
Subtracting
- Solve each of the equations. Show all steps (as
shown in the examples). - x 4 7 2. x 8 19
- 3. x 7 15 4. x 3 12
13Practicing One-Step Equations Adding and
Subtracting
- 5. 5 x 7 6. 13 x 19
- 7. 2 x 15 8. 6 x 12
- 9. 1 x 0 10. 53 x 97
14 15Practicing One-Step Equations Adding and
Subtracting
- 17. 8 - x 7 18. 4 - x 1
- 19. 9 - x 2 20. 12 - x 5
- 21. 14 - x 4 22. 40 - x 24
16Practicing One-Step Equations Adding and
Subtracting
- 23. x - 4 7 24. 5 x 8
- 25. 15 - x 11 26. x 15 23
- 27. 16 - x 3 28. x 13 3
17One step equations ? and ?
- Solving equations with ? and ? works much the
same way as and - . We still aim to get the
variable by itself on one side by using reverse
operations. - So if we are ?ing, we ? to get the variable by
itself and vice versa. - Note, if we multiply, we put the variable right
beside the number like this 5x. - If we divide, we sometimes express as a fraction
like this
18One step equations ? and ?
- Ex. 4x 8
- Our goal is to get the x by itself on the left,
so we need to move the 4 to the other side with
reverse operations. -
- Notice that we also divided by 4 on the right,
according to our golden rule. - 1x 2 so x 2
19One step equations ? and ?
- Ex. 4
- Our goal is to get the x by itself on the left,
so we need to move the 3 to the other side with
reverse operations. - ? 3 4 ? 3
- Notice that we also multiplied by 3 on the
right, according to our golden rule. - x ? 1 12 so x 12
20One step equations ? and ?
- Ex. 2
- This is a special case where we have to move the
variable instead. We will multiply each side by x
first ? x 2 ? x - Now the xs cancel on the left and we are left
with - 8 ? 1 2x so 8 2x
- Now we can solve by ?ing both sides by 2 .
- so 4 1 ? x so 4 x
21Practicing One-Step Equations Multiplying and
Dividing
- Solve each of the equations. Show all steps (as
shown in the examples). - 29. 4x 8 30. 6x 18
- 31. 3x 15 32. 2x 12
22Practicing One-Step Equations Multiplying and
Dividing
- 33. 5x 25 34. 1x 19
- 35. 7x 63 36. 6x 24
- 37. 15x 0 38. 2x 100
23Practicing One-Step Equations Multiplying and
Dividing
- 39. 2 40. 4
- 41. 5 42. 23
- 43. 0 44. 20
24Practicing One-Step Equations Multiplying and
Dividing
- 45. 2 46. 4
- 47. 5 48. 13
- 49. 8 50. 3
25Verifying answers to equations
- Whenever you solve an equation, you should check
your answer. Today we will learn an easy way to
do this. - Ex. Lets say we discovered that for the
equation x 3 10, x 7Now we use the left
side right side method to check our answer
26Verifying answers to equations
- Left Side Right Side
- x 3 10
- (7) 3 10
- 10 10
- Since the left and right sides are equal, we know
that our solution, x 7, is correct.
27Verifying answers to equations
- Is x 16 the solution for 5 ?
- Left Side Right Side
5
5
5.3125
5
The left side and right side are not equal, so x
? 16
28Practice verifying answers to equations
- For the numbers listed below, verify your answer
using the left side right side method of the
answers you found so far this unit. Example for
1 below, verfiy your answer to 1 that you did
earlier this unit (x 4 7) - 1. 6.
- 12. 18.
29Practice verifying answers to equations
30Solving two-step equations
- So far weve solved equations with one operation
, -, ?, or ?. - Now were going to solve equations that have two
operations. - We can do this in the same way weve done so far,
but we have to add another step.
31Solving two-step equations
- When we solve these two-step equations, we
continue to move numbers to the other side of the
equation, away from the variable. - When there is more than one number to move, we
work from the outside in. We start with the
numbers not attached to the variable. - Ex. 2a 5 13
- In this example, we first move the 5 because it
is not attached to the variable. Then we work
with the 2.
32Solving two-step equations
- Ex. 2a 5 13
- - 5 - 5
- 2a 0 8
- 2a 8
- 2 2
- a 4
First we subtract 5 on both sides because the 5
is not attached to the variable. Then we are
left with a simple one-step equation to solve.
33Solving two-step equations
- Ex. - 3 2
- 3 3
- 0 5
- 5 ? 4
- 1 ? b 20
- b 20
First we add 3 on both sides because the 3 is not
attached to the variable. Then we multiply both
sides by 4 to cancel the 4 on the left, and leave
the variable by itself.
34Solving two-step equations
- There are two ways to solve this equation
- 1st method
- Ex. 19 3c 13
- - 19 - 19
- - 3c - 6
- - 3 - 3
- c 2
In this method, we subtract both sides by 19
because it is not attached to the variable. Then
we are left with -3c -6. Now we have to divide
both sides by 3. Remember that a negative
divided by a negative leaves a positive!
35Solving two-step equations
- 2nd method
- Ex. 19 3c 13
- 3c 3c
- 19 0 13 3c
- - 13 - 13
- 6 3c
- 3 3
- 2 c
In this method, we move the 3c over to the right
so that we dont have a negative variable. Then
we subtract 13 on both sides so that we are left
with 6 3c. Then we can easily solve for c.
36Solving two-step equations
- We will solve these together in class
- 1. 3d 5 23 2. 2 - 1
37Solving two-step equations
38Verifying answers to two-step equations
- We use the same method that we used for one-step
equations. Now that we have two steps, remember
to use order of operations (BEDMAS). - The following are a few examples (the solution
found is in brackets) - Ex 1 2a 6 -4 (1)
- Ex 2 4b 7 -21 (-6)
- Ex 3 10 -1 (-66)
39Verifying answers to two-step equations Example 1
- a 1 is the correct answer.
Left Side 2a - 6 2(1) 6 2 6 -4
Right Side -4 -4 -4 -4
40Verifying answers to two-step equations Example 3
- f -66 is NOT the correct answer.
Left Side 10 10 -11 10 -1
Right Side 1 1 1 1
41Practice verifying answers to two-step equations
- Verify answers on a separate piece of paper using
the left side right side method, for the
following questions which you completed on a
separate piece of paper - s 3, 8, 14, 22, 28, 31, 34, 39, 41, 46
42Problem solving with equations
- When you are trying to solve a word problem, you
should do 4 steps to help you - Step 1 Define the variable
- Step 2 Set up the equation
- Step 3 Solve for the variable and make sure
your answer makes sense - Step 4 State the solution in a sentence
43Problem solving with equations
- Ex. Ellen works for McDonalds and gets paid
8.00 per hour. She wants to buy a snowboard
that costs 304.95, and she has already saved
155 towards this cost. How many more hours will
she have to work until she has enough money for
the snowboard? - Step 1 Define the variable.
- We are trying to find the number of hours she
needs to work, so let the number of hours be h.
44Problem solving with equations
- Ex. continued
- Step 2 Set up the equation.
- Total saved must equal 304.95.
- Total saved must be what she has saved already
plus the money she will make from working. - So 155 money from working 304.95
- Money from working equals 8.00 times the number
of hours , which is h. - So 155 8h 304.95
45Problem solving with equations
- Ex. continued
- Step 3 Solve for the variable and ask yourself
whether it makes sense. - 155 8h 304.95
- - 155 - 155
- 8h 149.95
- 8 8
- h 18.74
- This sounds about right, but she cant work only
part of an hour, so lets say 19 hours. - Step 4 Sentence Ellen must work 19 more hours
until she can buy the snowboard.
46Practice solving problems with equations
- The following problems use one-step equations.
Using the 4 steps, solve at least 6 questions on
a separate piece of paper and put in your
workbook. - 1. Alicia paid 4.85 for a sandwich and juice.
If the price of the sandwich was 3.50, how much
was the juice? - 2. Jonathan is paid 8.40 per hour. How much
will he be paid if he works 5 and a half hours?
47Practice solving problems with equations
- A can of chili costs 2.79. How many whole cans
of chili can you buy with twenty dollars? - Sarah is a waitress at Boston Pizza. She just got
a raise of 1.20 per hour and now makes 9.15 per
hour. What was her wage before the raise? - Mark wants to buy his mother a microwave for her
birthday. The cost of the microwave is 174.39.
If Mark makes 8.75 per hour, how many full hours
does Mark have to work to save up for the
microwave?
48Practice solving problems with equations
- A recipe for apple pie requires 4 ½ cups of
apples. If 2 ¾ cups are in the mixing bowl, how
many more cups of apples are needed? - Loaves of bread are advertised at a price of
three for 2.79. How much is this per loaf? - Lauras parents took her out to dinner on her
sixteenth birthday. The amount of the bill was
102.85. Her parents left 120. How much was
the tip?
49Practice solving problems with equations
- The following problems use two-step equations.
Using the 4 steps, solve at least 6 questions
again on a separate piece of paper and put in
your workbook. - 1. The school volleyball team went through a
drive-thru fast food restaurant on the way home
from a tournament. They ordered nine milkshakes
and twelve hamburgers. The manager paid the bill
of 42.21. They players tried to figure out how
much they owed, and one person remembered that
the cost of one hamburger was 2.10. What was
the price of one milkshake?
50Practice solving problems with equations
- Carl, James, and Rob decided to celebrate the end
of the semester by going out for dinner. At the
end of the meal, they each contributed an equal
amount to the cost. Then they realized they
forgot the tip, so they added an extra 6.00. If
the entire cost of the dinner, including the tip,
was 45, how much did each boy pay before adding
the tip? - On her last visit to the grocery store, Larissa
spent half the money she had on fruits and
vegetables. She also bought a loaf of bread for
1.39. If she had 2.36 left after paying for
her groceries, how much money did she have when
she entered the store?
51Practice solving problems with equations
- During a recent trip to the grocery store, Brian
bought 2 dozen eggs and a litre of milk. His
total came to 3.87. If a litre of milk cost
1.49, what was the price of one dozen eggs? - Tamara would like to buy a new pair of jeans
which cost 74.90, tax included, and she has
already saved 35 toward their cost. Her job as
a server pays 7.65 per hour. How many hours
will Tamara have to work to buy the jeans? - Kevin works as a server at a busy family
restaurant. Last Saturday he spent one-sixth of
his tips on dinner after his shift. The cab ride
home was 3.75, which he also paid from his tips
that day. The total amount he spent was 11.75.
How much did he make in tips?
52Practice solving problems with equations
- Jadin baked three kinds of cookies chocolate
chip, oatmeal raisin, and peanut butter. He made
equal numbers of chocolate chip and peanut butter
cookies. He also made thirty oatmeal raisin
cookies. He baked a total of 110 cookies. How
many peanut butter cookies did he make? - The best player on the Mullets hockey team scored
30 goals last season, which was one third of the
total goals scored for the team. If the Mullets
total goals scored last season was 15 less than
their rivals, the Skullets, how many did the
Skullets score?
53Practice solving problems with equations
- The Mullets won the local hockey championship and
celebrated by ordering pizza pepperoni and
hawaiian. Pepperoni pizzas cost 10.00 each and
a third of the bill paid for the hawaiian pizzas.
If the total amount of the bill was 60.00, how
many pepperoni pizzas were ordered? - For a school event, cans of pop were ordered.
Each can cost 0.63, and all unopened cans could
be returned for a full refund. The final amount
paid was 272.16 after 18 unopened cans were
returned. How many cans did the school order in
total?