Title: Experiment 2
1Experiment 2
- Part A Intro to Transfer Functions and AC
Sweeps - Part B Phasors, Transfer Functions and Filters
- Part C Using Transfer Functions and RLC
Circuits - Part D Equivalent Impedance and DC Sweeps
2In Class Solution
Question 1 From diagram A Which of the
following statements is true given the direction
of the current flow. c.) P2 gt P1Current flow
from high pressure to low pressure therefore P2
must be greater than P1.Question 2 Draw the
circuit equivalent of diagram A, label current
flow and voltage ( and on the voltage
source).Question 3 Draw an AC signal with the
following parameters Vp-p6V Vave0V Frequency
2KHzLabel the axis, label the amplitude and
period
Diagram A
3In Class Solution
Amp 3V
Period 0.5ms
4Circuit Analysis (Combination Method)
5Part A
-
- Introduction to Transfer Functions and Phasors
- Complex Polar Coordinates
- Complex Impedance (Z)
- AC Sweeps
6Transfer Functions
- The transfer function describes the behavior of a
circuit at Vout for all possible Vin.
7Simple Example
8More Complicated Example
What is H now?
- H now depends upon the input frequency (w 2pf)
because the capacitor and inductor make the
voltages change with the change in current.
9How do we model H?
- We want a way to combine the effect of the
components in terms of their influence on the
amplitude and the phase. - We can only do this because the signals are
sinusoids - cycle in time
- derivatives and integrals are just phase shifts
and amplitude changes
10We will define Phasors
- A phasor is a function of the amplitude and phase
of a sinusoidal signal - Phasors allow us to manipulate sinusoids in terms
of amplitude and phase changes. - Phasors are based on complex polar coordinates.
- Using phasors and complex numbers we will be able
to find transfer functions for circuits.
11Review of Polar Coordinates
point P is at ( rpcosqp , rpsinqp )
12Review of Complex Numbers
- zp is a single number represented by two numbers
- zp has a real part (xp) and an imaginary part
(yp)
13Complex Polar Coordinates
- z xjy where x is A cosf and y is A sinf
- wt cycles once around the origin once for each
cycle of the sinusoidal wave (w2pf)
14Now we can define Phasors
- The real part is our signal.
- The two parts allow us to determine the influence
of the phase and amplitude changes
mathematically. - After we manipulate the numbers, we discard the
imaginary part.
15The VIR of Phasors
- The influence of each component is given by Z,
its complex impedance - Once we have Z, we can use phasors to analyze
circuits in much the same way that we analyze
resistive circuits except we will be using the
complex polar representation.
16Magnitude and Phase
- Phasors have a magnitude and a phase derived from
polar coordinates rules.
17Influence of Resistor on Circuit
- Resistor modifies the amplitude of the signal by
R - Resistor has no effect on the phase
18Influence of Inductor on Circuit
Note cosqsin(qp/2)
- Inductor modifies the amplitude of the signal by
wL - Inductor shifts the phase by p/2
19Influence of Capacitor on Circuit
- Capacitor modifies the amplitude of the signal by
1/wC - Capacitor shifts the phase by -p/2
20Understanding the influence of Phase
21Complex Impedance
- Z defines the influence of a component on the
amplitude and phase of a circuit - Resistors ZR R
- change the amplitude by R
- Capacitors ZC1/jwC
- change the amplitude by 1/wC
- shift the phase -90 (1/j-j)
- Inductors ZLjwL
- change the amplitude by wL
- shift the phase 90 (j)
22AC Sweeps
AC Source sweeps from 1Hz to 10K Hz
Transient at 10 Hz Transient at
100 Hz Transient at 1k Hz
23Notes on Logarithmic Scales
24Capture/PSpice Notes
- Showing the real and imaginary part of the signal
- in Capture PSpice-gtMarkers-gtAdvanced
- -gtReal Part of Voltage
- -gtImaginary Part of Voltage
- in PSpice Add Trace
- real part R( )
- imaginary part IMG( )
- Showing the phase of the signal
- in Capture
- PSpice-gtMarkers-gtAdvanced-gtPhase of Voltage
- in PSPice Add Trace
- phase P( )
25Part B
-
- Phasors
- Complex Transfer Functions
- Filters
26Definition of a Phasor
- The real part is our signal.
- The two parts allow us to determine the influence
of the phase and amplitude changes
mathematically. - After we manipulate the numbers, we discard the
imaginary part.
27Phasor References
- http//ccrma-www.stanford.edu/jos/filters/Phasor_
Notation.html - http//www.ligo.caltech.edu/vsanni/ph3/ExpACCircu
its/ACCircuits.pdf - http//ptolemy.eecs.berkeley.edu/eecs20/berkeley/p
hasors/demo/phasors.html
28Phasor Applet
29Adding Phasors Other Applets
30Magnitude and Phase
- Phasors have a magnitude and a phase derived from
polar coordinates rules.
31Eulers Formula
32Manipulating Phasors (1)
- Note wt is eliminated by the ratio
- This gives the phase change between signal 1 and
signal 2
33Manipulating Phasors (2)
34Complex Transfer Functions
- If we use phasors, we can define H for all
circuits in this way. - If we use complex impedances, we can combine all
components the way we combine resistors. - H and V are now functions of j and w
35Complex Impedance
- Z defines the influence of a component on the
amplitude and phase of a circuit - Resistors ZR R
- Capacitors ZC1/jwC
- Inductors ZLjwL
- We can use the rules for resistors to analyze
circuits with capacitors and inductors if we use
phasors and complex impedance.
36Simple Example
37Simple Example (continued)
38In Class Problems
Question 1 What is the equation for Rtotal?
(Combining R1, R2, R3, R4, and R5?) Question 2
What is the value for Rtotal? Question 3 What
is the transfer function for the above circuit?
39High and Low Pass Filters
High Pass Filter H 0 at w 0 H 1 at w H
0.707 at wc
wc2pfc
fc
Low Pass Filter H 1 at w 0 H 0 at w H
0.707 at wc
wc2pfc
fc
40Corner Frequency
- The corner frequency of an RC or RL circuit tells
us where it transitions from low to high or visa
versa. - We define it as the place where
- For RC circuits
- For RL circuits
41Corner Frequency of our example
42H(jw), wc, and filters
- We can use the transfer function, H(jw), and the
corner frequency, wc, to easily determine the
characteristics of a filter. - If we consider the behavior of the transfer
function as w approaches 0 and infinity and look
for when H nears 0 and 1, we can identify high
and low pass filters. - The corner frequency gives us the point where the
filter changes
43Taking limits
- At low frequencies, (ie. w10-3), lowest power of
w dominates - At high frequencies (ie. w 103), highest power
of w dominates
44Taking limits -- Example
- At low frequencies, (lowest power)
- At high frequencies, (highest power)
45Our example at low frequencies
46Our example at high frequencies
47Our example is a low pass filter
What about the phase?
48Our example has a phase shift
49Part C
-
- Using Transfer Functions
- Capacitor Impedance Proof
- More Filters
- Transfer Functions of RLC Circuits
50Using H to find Vout
51Simple Example (with numbers)
52Capacitor Impedance Proof
Prove
53Band Filters
Band Pass Filter H 0 at w 0 H 0 at w H
1 at w02pf0
f0
Band Reject Filter H 1 at w 0 H 1 at w
H 0 at w0 2pf0
f0
54Resonant Frequency
- The resonant frequency of an RLC circuit tells us
where it reaches a maximum or minimum. - This can define the center of the band (on a band
filter) or the location of the transition (on a
high or low pass filter). - The equation for the resonant frequency of an RLC
circuit is
55Another Example
56At Very Low Frequencies
At Very High Frequencies
57At the Resonant Frequency
if L1mH, C0.1uF and R100W w0100k rad/sec
f016k Hz H01
58Our example is a low pass filter
Phase f 0 at w 0 f -180 at w
-90
Magnitude H 1 at w 0 H 0 at w
1
f016k Hz
Actual circuit resonance is only at the
theoretical resonant frequency, f0, when there
is no resistance.
59Part D
- Equivalent Impedance
- Transfer Functions of More Complex Circuits
60Equivalent Impedance
- Even though this filter has parallel components,
we can still handle it. - We can combine complex impedances like resistors
to find the equivalent impedance of the
components combined.
61Equivalent Impedance
62Determine H
63At Very Low Frequencies
At Very High Frequencies
64At the Resonant Frequency
65Our example is a band pass filter
Magnitude H 0 at w 0 H1 at w0 H 0 at w
Phase f 90 at w 0 f 0 at w0 f -90 at w
f0
66In Class Problems
Question 1 What is the equation for Rtotal?
(Combining R1, R2, R3, R4, and
R5?) (R5R4)(R2R3/R2R3)/ (R5R4)(R2R3/R2R
3) R1 Question 2 What is the value for
Rtotal? 10 ohms Question 3 What is the
transfer function for the above circuit? (next
slides)
67Find voltage at this point, then use voltage
divider (only use this in series)
68VB0.6V
Now use the voltage divider to find Vout
Were not done thoughwe are looking for the
transfer function HVout/Vin so remember