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Vertical Curves

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Road conditions. Curve, D = 4 , I = 53 PC at Sta 24 45, Elev = 299.75' ... Road top is 40' wide, crown is 0.015 ft/ft. Superelevation = 4%, Runoff = 400 feet ... – PowerPoint PPT presentation

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Title: Vertical Curves


1
Vertical Curves
  • Sometimes required when two gradients meet
  • Transition too abrupt
  • Sight Distances
  • Note terms
  • Distances measured horizontally
  • Tangent offsets indicate cut or fill from flat
    grade to curve

2
Parabolic Curve
  • Form y ax2 bx c
  • Three important relationships
  • Curve at midpoint is always halfway between PVI
    and a line connecting PVC and PVT.
  • Tangent offsets vary with the square of the
    distance from PVC.
  • Second differences between equal points are equal.

3
Parabolic Example
  • Extend g1, divide into 6 equal parts
  • If offset at 1 a
  • Offset2 4a
  • Offset3 9a
  • ACV similar to ABB
  • CV BB/2 18a
  • CM MV 9a

4
Vertical Curve by Proportions
  • Problem 21-3
  • g1 4, g2 -2.1
  • PVT 4650, E 682.24
  • L 8 sta (800 ft)
  • Sta PVC Sta PVI L/2 4250, EPVC 682.24
    4(4 Sta) 666.24
  • Sta PVT Sta PVI L/2 5050, EPVT 682.24
    4 Sta(-2.1) 673.84

5
Problem 21-3 (Cont.)
  • Find yPVT, yMid
  • yPVT EPVC g1L EPVT 666.24 (4)(8
    Sta) 673.84 24.40
  • yMid yPVT(4/8)2 24.40(.5)2 6.10, or

6
Problem 21-3, Cont.
  • Ascending E EPVC g1x y
  • y43 (-6.10)(0.5)2/(4)2 -0.10
  • E43 666.24 (4)(0.5 sta) 0.10 668.14
  • y44 (-6.10)(1.5)2/(4)2 -0.86
  • E43 666.24 (4)(1.5 sta) 0.86 671.38
  • Descending E EPVT g2x y
  • Sta 4700, x from PVT 3.5 sta
  • y47 (-6.10)(3.5)2/(4)2 -4.67
  • E47 673.84 - (-2.1)(3.5 sta) 4.67 676.52

7
Curve Equation
  • Elev c bx ax2
  • c ElevA
  • b g1 (in )
  • x in Sta
  • ElevX ElevAg1xax2
  • Rate of Change
  • d2y/dx2 2a
  • a (g2-g1)/2L

8
Vertical Curve Equation
  • Change in grade A g2-g1
  • Rate of change r A/L
  • High or Low Point
  • Occurs when grade 0
  • Grade changes from g1 to 0 at rate r

9
Problem 21-3 by Equation
  • A (-2.1 4) -6.1
  • r A/L -6.1/8 Sta -.7625 /Sta
  • E43 666.24 4(0.5) - 0.38125(.5)2 668.14
  • E44 666.24 4(1.5) - 0.38125(1.5)2 671.38
  • E4650 666.24 4(4.0) - 0.38125(4.0)2 676.14
  • E47 666.24 4(4.5) - 0.38125(4.5)2 676.52
  • High Point X -g1/r -4/-0.7625 5.2469 Sta
  • E4774.59 666.24 4(5.2469) - .38125(5.2469)2
    676.73
  • E48 666.24 4(5.5) - 0.38125(5.5)2 676.71

10
Curve Thru a Point
  • Say you want the curve to pass through a point of
    known Sta, Elev
  • Select L to force curve through point
  • Two possible solutions
  • Tangent Offsets Author
  • Equation

11
Thru Point - Tangent Offset
  • xP Distance from PVI to Point, in Sta
  • yB offset from the back tangent
  • yF offset from forward tangent

12
Thru Point Tangent Offset
13
Thru Point Equation
  • yB yF (g2 - g1)xP
  • yB yF 2(EP - EPVI) - (g2 g1)xP
  • Recall A g2 - g1
  • xP Distance from PVI to point, in Sta

14
Superelevation
  • Crown 0.015 0.02 ft/ft
  • Superelevation
  • Transverse Slope
  • Depends on Side friction, speed, D
  • Max 8- 10
  • Runoff transition from flat to banked
  • Linear change
  • Min 100-250 ft
  • Max 500-600 ft

15
Superelevation Example
  • Road conditions
  • Curve, D 4 , I 53
  • PC at Sta 2445, Elev 299.75
  • Centerline grade from PC to PT is 3.5
  • Road top is 40 wide, crown is 0.015 ft/ft
  • Superelevation 4, Runoff 400 feet
  • Design
  • PC Centerline at 299.75
  • At PC need full superelevation, ? .04(20)
    0.80
  • Out shoulder at 300.55, In shoulder at 298.95

16
Runoff
  • PC at Sta 2445, Elev 299.75
  • Out shoulder at 300.55, In shoulder at 298.95
  • 400 foot runoff start at Sta 2045
  • Centerline at 313.75
  • Crown at 0.01520 0.30
  • Out and In Shoulders at 313.45
  • Linear transition
  • Roll outside crown up to 1.5 (0.015 ft/ft)
  • Roll both shoulders to 4
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