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Using Parametric Equations to Model Motion

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An archer shoots an arrow with an initial velocity of 60 m/s at an angle of 4.8 ... The target is 70 meters away and the bow is held 1.4 meters off the ground. ... – PowerPoint PPT presentation

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Title: Using Parametric Equations to Model Motion


1
Section 8-7
  • Using Parametric Equations to Model Motion

2
Vocabulary
  • Projectiles objects that are launched
  • Trajectory the path of the projectile
  • Range horizontal distance that a projectile
    travels
  • Motion described in terms of its position,
    velocity, and acceleration

3
Parametric Equations
  • X tvcos?
  • Y tvsin? ½ gt2 h0

t time v initial velocity g gravity, -9.8
m/s2 or -32 ft/s2 h0 initial height
4
Example 1
  • A football player kicks a ball with an initial
    velocity of 40 ft/s at a 40 angle with the
    ground.
  • How far has the ball traveled after 0.8 seconds?
  • First write the equations
  • X t(40)cos40 30.64t
  • Y t(40)sin40 ½ (-32)t2 25.71t 16t2

5
Continued
  • Plug in 0.8 for t
  • X 30.64(.8) 24.5 ft. (horiz.)
  • Y 25.71(.8) 16 (.8)2 10.3 ft. (vert.)

6
Example 2
  • Hole 4 is 220 yds. to the pin. The initial
    velocity is 160 ft/s with a 28 7-wood.
  • Can the ball reach the pin?
  • Write the equations
  • X t(160)cos28 141.3t
  • Y t(160)sin28 ½ (-32)t2 75.1t 16t2

7
Continued
  • First find t when y 0.
  • 0 75t 16t2
  • 0 t (75 16t)
  • t 0 or t 75/16 4.7 seconds
  • Now find x after 4.7 seconds
  • X 141.3t
  • X 141.3(4.7) 662 feet
  • 662 ft. 220.7 yards
  • So Yes!?

8
Example 3
  • An archer shoots an arrow with an initial
    velocity of 60 m/s at an angle of 4.8 with the
    horizontal.
  • The target is 70 meters away and the bow is held
    1.4 meters off the ground.
  • How far off the ground will the arrow be when it
    hits the target?

9
Continued
  • First write the equations
  • X t(60)cos4.8 59.8t
  • Y t(60)sin4.8 ½ (-9.8)t2 1.4
  • 5.0t 4.9t2 1.4
  • Now, find out how long it takes to hit the
    target.
  • 70 59.8t
  • t 1.17 seconds

10
Continued
  • Plug in t 1.17 into the equation for y.
  • Y 5.0t 4.9t2 1.4
  • 5.0(1.17) 4.9(1.17)2 1.4
  • .54
  • Therefore, the arrow will be .54 meters off the
    ground when it hits the target.

11
Homework
  • Page 453-455
  • 8-12, 16-17
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