Title: MATH 10B Review Session
1MATH 10B Review Session
- Franklin Kenter
- March 15, 2009
2Instructions
- For this review session we will be doing actual
problems so that you know what to study for, and
moreover, so that you can identify your
weaknesses and focus in those areas t - Get into groups of 3 or 4. If possible, make a
new friend or two. - For each question, I will taking 3 or 4 groups to
do the problems on the board. Each group that
does so will be rewarded. Then we will go over
the problems afterwards.
3Instructions continued
- While doing these problems, you reference your
notes (even if your group is at the board).
However, every time you reference your notes, YOU
HAVE TO WRITE WHAT YOU REFERENCED ON YOUR NOTE
SHEET! - Lastly, this is a work in progress, please look
out for and point out any mistakes.
4FINALS TIME AND PLACE
- TIMEWed. Mar. 18, 700pm-1000pm
- PLACE depends upon your lecture
- John Eggers (9am Lecture) MANDE AUD
- Michael Volpato (12pm Lecture) WLH 2005
- Shengli Kong (1pm Lecture)
- Last names A L PCYNH 109
- Last names M Z PCYNH 106
- Evelyn Lunasin (4pm Lecture)
- Last names A O LEDDN AUD
- Last names P Z HSS 1330
5Does anyone not know where his or her final is?
- John Eggers (9am Lecture) MANDE AUD
- Michael Volpato (12pm Lecture) WLH 2005
- Shengli Kong (1pm Lecture)
- Last names A L PCYNH 109
- Last names M Z PCYNH 106
- Evelyn Lunasin (4pm Lecture)
- Last names A O LEDDN AUD
- Last names P Z HSS 1330
6Additional Sources For Help This Week
- I will stay here for a short time after.
- All of this information (including this
slideshow) can be found at math.ucsd.edu/fkenter/
- Dan Minsky has office hours Monday and Tuesday
from 4-5pm in APM 6446. - Jacob Hughes will be holding another review
session Tuesday 8-930pm in CENTER 119
7What is the best way to study?
- DO PRACTICE PROBLEMS- as many as you can until
you know it inside and out - Speaking or which
- THERE ARE ALSO OTHER PRACTICE FINALS ON MY
WEBSITE math.ucsd.edu/fkenter/
8Color code!
- ANSWERS will be in a green glowing box
- IMPORTANT CONCEPTS will be in an orange glowing
box. - Guess what my favorite colors are?
9Course Outline (not all inclusive)
- Chapters 5-6 The concept of an integral
- Chapters 5 7.5 Estimating integrals
- Chapter 7 Solving Integrals Algebraically- with
the tools of substitution, by parts, and - partial fractions and trig substitution
- Chapter 7.7-8 Improper Integrals
- Chapter 8 Applications of integrals
specifically- Volumes of solids and - Value of money over time
- Chapter 11 Differential Equations
10Question 1a
- Here is our first question. Its easy, but has a
small little trick - Estimate using
LEFT(1)
11Solution 1a
- Estimate using
LEFT(1) -
- This is the number of subdivisions
NOT the size of ?x. - This means that there is 1 subdivision. ?x
12Solution 1a continued
- So our table (if that is really what you want to
call it a table) looks like this - To get the final answer
- We simply add up all of the rectangles
2
13Question 1b
- That might have been too easy, let us try this
- Estimate
- using LEFT(4), RIGHT(4), MID(4), and TRAP(4)
14Solution 1b (for LEFT(4) )
- ?x
-
- Again, to get the final answer
- We simply add up all of the rectangles
6.75
15Solution 1b (for RIGHT(4) )
- ?x
-
- Again, to get the final answer
- We simply add up all of the rectangles
10.75
16Solution 1b (for MID(4))
- ?x
-
- Again, to get the final answer
- We simply add up all of the rectangles
8.625
17Solution 1b (for TRAP(4))
- You could do a table for this one, but tell you
what, it is much easier to take advantage of the
fact that - TRAP(n) ½ (LEFT(n) RIGHT(n))
- So TRAP(4) ½ (LEFT(4) RIGHT(4))
- ½ (6.75 10.25) 8.5
18Question 1c
- That might have been too easy, let us try this
- Referring to
- Which ones of LEFT(4), RIGHT(4), MID(4), and
TRAP(4) are overestimates? Underestimates? - Why?
19Solution 1c
- Note the following rules
- LEFT is an underestimate if f(x) is increasing,
and an overestimate if f(x) is decreasing. - Conversely, RIGHT is an overestimate if f(x) is
increasing and an underestimate if f(x) is
decreasing. - Likewise, TRAP is an underestimate if f(x) is
concave down, and an overestimate if f(x) is
concave up. - MID is an overestimate if f(x) is concave down,
and an underestimate if f(x) is concave up. - f(x) , is concave up and increasing on
(1,3). - Apply the above rules to determine the answer.
20Estimating Integrals
- A few notes the rules for Question 1c only work
if the integral is strictly increasing (or
decreasing, concave up, or concave down) on the
interval.
21Before we move onThese are basic integrals you
should know!
Except for n-1
22More basic integrals you should know!
23The sine and cosine wheel
Clockwise to Differentiate
24The sine and cosine wheel
Counterclockwise to Integrate
25Question 2a,b,c,d
- Compute the following integrals
26Solution 2a
- What tool do we use? Why?
27Solution 2a
- What tool do we use? Why?
- By parts- namely because substitution will not
work (i.e. no part is the derivative of the
other)
28Solution 2a
- What tool do we use? Why?
- By parts- namely because substitution will not
work (i.e. no part is the derivative of the
other) - The By Parts Formula
29Solution 2a continued
- But which one is u and which on is v'?
30Solution 2a continued
- But which one is u and which on is v'?
- We will make u ln(x). Why?
31Solution 2a continued
- Because is easier to integrate!
- A ranking of functions to choose for u is (in
general) given by - Log
- Inverse Trig
- Polynomials
- Sine and Cosine
32Solution 2a continued
Dont forget C
33Solution 2b
- What tool do we use? Why?
34Solution 2b
- What tool do we use? Why?
- Substitution- because is similar to the
- derivative of (except for a constant
factor).
35Solution 2b
- What tool do we use? Why?
- Substitution- because is similar to the
- derivative of (except for a constant
factor). - Make a quick glance for substitution first-
because substitution is easier!
36Solution 2b
Sometimes solving for dx in terms Of x and du can
be helpful
Cancel xs
Substitution
Resubstitute
37Solution 2b
When using substitution, There should be no xs
in your Substituted integral!!!
Sometimes solving for dx in terms Of x and du can
be helpful
38Short Solution to 2c
- This problem is an example where by parts wraps
around. After doing by parts once, then again,
you will end up with (Remember use LIPS with u
cosx)
39Short Solution to 2c continued
40Question 3a,b,c
- Let R be the area in the plane bounded by the
curves yx, y-x, y0, and y1. - Find the volume of the solid when R is revolved
around the - y-axis
- The line x1
- The line y2
41Notes on Question 3a,b,c
- Always, always draw a picture. It will make life
easier. - Remember that the formula for volumes of
revolution is - furthest function axis of rotation
- nearest function axis of rotation
- Determine the bounds of your integral by finding
the extreme of x (for dx) or y (for dy)
42More Notes on Question 3a,b,c
- If the axis of rotation is vertical, then width
of your donuts slices are going to be dy.
Everything should be in terms of y and dy! - If the extremes for x or y, as appropriate, are
not given to you, try finding the intersections
of curves (i.e. if the region is bounded by
ycos(x) and ysin(x) and you are integrating dx,
solve cos(x)sinx)
43Question 4
- Do the following integrals converge or diverge?
Why?
44Question 5
a) If f(x) is even, find b) If f(x) is odd,
find c) If f(x) is even, find
45Question 6
- Is positive or negative? Why?
- Evaluate
46Question 7
Find the general solution
Find y(1) if t10 when y0
47Question 8
- As a lunar module takes off from the moon, its
acceleration in is given by (t in seconds) - Find the distance traveled in the 3 seconds.
48Solution 8
- Note the following relation
- Acceleration
- Velocity
- Position
- So given Acceleration, to find Position, all we
have to do is integrate twice.
49Solution 8 continued
- Though this is slightly said than done. Every
time you integrate you will left with a C, and
you have to figure out what C is before you
integrate again! - Note that since the lunar module is taking off
we assume that it is stationary (i.e., V0 when
t0).
50Solution 8 continued
WATCH OUT! C is not always 0!
51Solution 8 continued
- Generally, the ground is where P0, since the
lunar module starts on the ground, P0 when
t0, so we can solve for C
52Question 9
- Frank decides to give his son, Franklin, a deal
- Franklin can pay Frank 35 to permanently raise
his allowance 0.25 per month (paid
continuously). If the bank rate is always
constant 5 per year, and Frank will pay
allowance for another 13 years, should Franklin
take the deal? Why or why not?
53Solution 9
Annual Rate.. IN DECIMAL FORM
- Remember this formula? If not, put it on your
notesheet. - Present Value
- So the present value of receiving an extra
quarter every month for 20 years is
Annual cash flow as a function of t
54Solution 9 continued
- So the present value of receiving an extra
quarter every month for 20 years is - Franklin should take the deal because the present
value of the deal is more than 35.