Title: I estimate my grade on exam 2 to be:
1I estimate my grade on exam 2 to be
Physics 1710Warm-up Quiz
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2Physics 1710Chapter 13 Apps Gravity
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- Center of Gravity (comparison)
CM
CM
Ball Fg - mg
CG
Moon Fg - GmM/r2
3Physics 1710Chapter 13 Apps Gravity
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- What is the mass of the earth?
- How do you know?
Peer Instruction Time
4Physics 1710Chapter 13 Apps Gravity
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- What is the mass of the earth?
- How do you know? g?
Fg - mg
Fg - mg'
Peer Instruction Time
5Physics 1710Chapter 13 Apps Gravity
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- 1' Lecture
- The moduli of elasticity (Y, E, B) characterizes
the stress-strain relation - stress modulus strain s Y e
- The force of attraction between two bodies with
mass M and m, respectively, is proportional to
the product of their masses and inversely
proportional to the distance between their
centers squared. - Fg - rG Mm/d 2
- G 6.673 x 10 11 N m2 /kg2 2/3 x 10 10 N m2
/kg2
6Physics 1710Chapter 13 Apps Gravity
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- Elasticity
- Definitions
- Stress s the deforming force per unit area.
- Strain e the unit deformation.
- Stress modulus x strain
- s F/A Y e
7Physics 1710Chapter 13 Apps Gravity
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- Elasticity
-
- Stress s Strain e Curve
Stress s (N/m2)
s Y e
Strain e ?L/L ()
8Physics 1710Chapter 13 Apps Gravity
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- Elasticity
- Stress s the deforming force per unit area.
- Strain e the unit deformation.
- Tensile/Compressive Stress Youngs Modulus E
- Stress modulus x strain
- s F/A E e E ?L/L
?L
L
s E e
9Physics 1710Chapter 13 Apps Gravity
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- Elasticity
- Stress s the deforming force per unit area.
- Strain e the unit deformation.
- Shear Modulus G
- Stress modulus x strain
- s F/A G e G ?x/h
L
?x
h
s
10Physics 1710Chapter 13 Apps Gravity
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- Elasticity
- Stress s the deforming force per unit area.
- Strain e the unit deformation.
- Hydraulic Stress Bulk Modulus B
- Stress modulus x strain
- s F/A p B e B ?V/V
?V
p
V
11Which spring should have the larger spring
constant, a short spring (0.1 m long) or a longer
spring (0.3 m long)? F -k x
Physics 1710Chapter 13 Apps Gravity
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- k larger for shorter spring.
- k larger for longer spring.
- k the same for both springs.
- None of the above.
12Physics 1710Chapter 12 Apps Gravity
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F -k x? s F/A E e E ?L/L F - A E x/
L k A E/L
What about a thicker (bigger A) wire?
13Physics 1710Chapter 13 Apps Gravity
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- Isaac Newtons
- Universal Law of GravitationF - G M m/ d 2
d moon
14Physics 1710Chapter 13 Apps Gravity
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- Keplers Laws
- The orbits are ellipses. (Contrary to Aristotle
and Ptolemy.) - A central force F ? 1/ r 2 or r 2
- The areal velocity is a constant.
- Angular momentum is conserved
- ½ v r ?t constant implies that
- rmv L constant.
- T 2 ? r 3 implies F ? 1/ r 2, only.
?
r3
T 2
15Physics 1710Chapter 12 Apps Gravity
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- How did Newton figure out UL of G?
- Fact a moon circling a planet has an
acceleration of a v 2 /r - Fact a F/m.
- Fact Kepler had found that the square of the
period T was proportional to the cube of the
radius of the orbit r - T 2 k r 3 .
- Thus
- v 2p r / T
16Physics 1710Chapter 12 Apps Gravity
- And
- T 2 (2pr) 2 /(F r /m) k r 3
- Thus
- F (2p) 2 m/(k r 2 )
- An inverse square law, with k 1/ (2p) 2G
M - F G Mm/ r 2 ,
- But what value is G?
17Physics 1710Chapter 13 Apps Gravity
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- Isaac Newtons
- Universal Law of GravitationF - G M m/ d 2
d moon
F g m g G M ? / R? 2
18Physics 1710Chapter 12 Apps Gravity
g G M / R?2 G M ? gR ? 2 (9.80
N/kg)(6.37x10 6 m)2 3.99x10 14 N m 2/kg
Need to know G or M.
19Physics 1710Chapter 13 Apps Gravity
- Henry Cavendish
- And the
- Cavendish Experiment
M
m
d
20Physics 1710Chapter 13 Apps Gravity
- G 6.673 x 10 -11 N ?m 2 /kg 2
- G 2/3 x 10 -10 N ?m 2 /kg 2
- (to an accuracy of 0.1)
So, M ? (3.99x10 14 N m 2/kg)/(6.673 x 10-11 N
?m 2/kg 2) 5.98 x10 24 kg
21Physics 1710Chapter 13 Apps Gravity
F - G M m/ d 2 What is the order of magnitude
of the attraction between two people (m 100 kg)
separated by a distance of 1m?
M
m
d
22What is the order of magnitude of the attraction
between two people (m 100 kg) separated by a
distance of 1m?
Physics 1710Chapter 13 Apps Gravity
- 9.8 N.
- 980. N
- 6.7 X 10 - 7 N
- 6.7 X 10 - 9 N
- None of the above
23Physics 1710Chapter 13 Apps Gravity
F - G M m/ d 2 F - (6.67 x10 11 N ?m 2 /kg
2)(100 kg)(100kg )/(1 m) 2 F - 6.67 x10 7 N
Equivalent weight F/g 67 ng
M
m
d
24Physics 1710Chapter 13 Apps Gravity
- Summary
- Keplers Laws
- The orbits of the planets are ellipses.
- The areal velocity of a planet is constant.
- The cube of the radius of a planets orbit
- is proportional to the square of the period.
- F - G M m/ d 2