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Computer Architecture

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age .word 0:100 ; 100 words initialized to zero ... b Xy: # Unconditional branch. Lanbl: IF ... then. If (count == max) I = 5; else. I = 20; ... – PowerPoint PPT presentation

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Title: Computer Architecture


1
Computer Architecture
  • Lecture 2
  • Instruction Set Principles

2
Intro to Assembly LanguageMIPS and Intel
  • Variables and Constants
  • int count 10, I, j, k
  • count .word 10
  • i .word
  • j .word

Count DD 10 i DD ? j DD ?
3
Byte size variables
  • char sum 1, total 5
  • char uni10 university

sum .byte 1 total .byte 5 uni .byte
u,n, i etc
sum db 1 total db 5 uni db u,n, i
etc
4
Strings
  • string str (hello world)

str .asciiz hello world
str db hello world
5
Arrays
  • int age100

age .word 0100 100 words initialized to zero
age dw 100 dup(0) 100 words initialized to zero
6
Assignment
  • count count 1

la R1, count (load address works in spim)
R1 has address of count lw R2, 0(R1) R2
has the value of count addi R2, R2, 1
Increment sw R2, 0(R1) Save count, if need be
7
Another Example
  • i age20 age0 count
  • la R3, age R3 has base address of age
  • lw R4, 80R3 20 4 80, R4 age20
  • lw R5, 0(R3) R5 age0
  • add R4, R4, R5
  • add R4, R4, R2 R2 had value of count above

8
Control
  • count 0
  • while (count lt 21)
  • agecount agecount1
  • count count1
  • addi R2, R0, 0 R2 count 0
  • lable1
  • mul R6, R2, 4 R6 has address of
  • countth element
  • add R6, R6, R4 R2 count, R4 age
  • R6 address of countage
  • lw R7, 4(R6) R7 agecount1
  • sw R7, 0(r6) agecount R7
  • addi R2, R2, 1 Count count 1
  • slti R8, R2, 21
  • R8 1 if countlt21

9
For Statement
  • Total 0
  • For (i 0 iltcount i )
  • total agei total
  • la R1, age R1 has address of count
  • lw R2, 0(R1) R2 has the value of count
  • addi R5, R0, 0 i 0 R5 is i
  • addi R15, R0, 0 total 0 R15 is total
  • Xy slt R11,R5,R10 check R5 is R5 lt R10 (R10
    is count)
  • be R11, R0, lable loop until
  • mul R6, R5, 4 R6 has address of ith element
    of age
  • add R6, R6, R4 R4 address of age
  • lw R20, 0(R6) R20 agei
  • add R15, R15, R20 total total agei
  • sw R15, 0(R22) R22 is address of total
  • addi R5,R5,1 i i1
  • b Xy Unconditional branch
  • Lanbl

10
IF then
  • If (count max)
  • I 5
  • else
  • I 20
  • assume R4 has the value of count, R7 has value
    of MAX and I is R5
  • bne R4, R7, else
  • addi R5, R0, 5
  • b exit
  • else addi R5, R0, 20
  • exit

11
Classifying Instruction Set Architectures
  • Stack
  • Register- Register
  • Register Memory
  • Accumulator
  • Memory Memory
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