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ASSIGNMENT

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Title: ASSIGNMENT


1
ASSIGNMENT
  • To find structures of all possible Na clusters
    upto atom no 6 and study them.
  • and their IP, internal energy and free energy and
    compare with that of bulk by HF/6-31G(d)
    B3LYP/6-31G(d).

2
INTRODUCTION
  • CLUSTERS
  • HF
  • B3LYP
  • 6-31G(d)
  • GAUSSIAN 03

3
CLUSTERS
  • clusters are the structures intermediate to
    molecules and bulk eg. fullerene
  • metallic clusters have metal bonds as a
    stabilizing force and inter atomic repulsions as
    destabilizing force.
  • certain properties like inter atomic distances,
    IP, free energy vary in clusters as compared to
    that of the bulk.
  • stable conformers have lower energy as compared
    to unstable ones.

4
Exactness....the desire Inexactness....the
need
  • The underlying physical laws necessary for the
    mathematical theory of a large part of physics
    the whole of chemistry are completely known,
    the difficulty is only that the exact
    applications of these laws leads to equations
    much too complicated to be solvable.

    - DIRAC

5
HF
  • In Hartree-fock theory each electron is described
    by an orbital and the total wave functions is
    given as a product of orbitals .
  • HF theory only accounts for the average
    electron-electron interactions, consequently
    neglects the correlations between electrons.
  • HF gives results that are 99 correct.

6
B3LYP
  • Becke's three parameter formulation is a
    Density functional method . They calculate elec
    correlation via elec density functional .
  • DFT functionals partition the electronic energy
    into several components ,which are computed
    separately the KE , the elec-nuclear
    interaction the coulomb repulsion an exchange
    correlation term accounting for the remainder of
    elec-elec interaction.

7
6-31G(d)
  • Split valence basis set like 6-31G have two sizes
    of basis functions for each valence orbital. eg H
    C are represented as
    H
    1s, 1s

    C1s,2s,2s,2px,2py,2pz,2px,2py,2pz
    where starred unstarred orbitals
    differ in size and can form all MOs from linear
    combinations for each atomic orbitals.
  • 6 functions are used for core electrons ,3 for
    more diffused valence electrons 1 for less
    diffused valence electron.

8
  • d is polarized basis. Split valence sets allow
    orbitals to change size but not shape. Polarized
    basis set removes this.
  • p is added to H ,d to 2nd period elements f to
    transition metals.

9
GAUSSIAN
  • It is connected to a system of programs for
    performing variety of semi-empirical ab-initio
    MO calculations.
  • Automated geometry optmizes to either minima or
    saddle points . Optmization is performed by
    default using internal coordinates regardless of
    the input coordinates used .
  • Gaussian programs use gaussian functions as basis
    set. Their general form -
    g(a,r) c
    xn ym zl e(-ar2)

10


a is a constant determining size (radial extent)
of the function.
11
APPROACH TO THE PROBLEM
  • Initial verification of non-existence of highly
    unsymmetrical structures.
  • Trying out different possible structures by HF
    method and next doing freq opt.
  • Ruling out of some more structures
  • Using the output given by HF files in B3LYP .
    (why not the converse ???)
  • Repeating a similar process for the cations.

12
OBSERVATIONS
  • The values of IP, E G and the structure
    given by HF B3LYP are almost same (lt0.5).
  • So the structure of all the conformers we have
    shown in the following slides are from B3LYP.
    Only those structures which are different in HF
    are shown.
  • Some cations with interesting geometry are also
    shown.

13
  • n2
  • HF/B3LYP
  • Linear

14
E,G IP Values for n2
15
  • n3
  • B3LYP
  • Linear
  • Initial input
    90 or 109
    degrees

16
  • n3
  • B3LYP
  • Bent(168.)
  • Initial input
    175 degrees

17
  • n3
  • B3LYP
  • Triangular
    96 degrees
  • Initial input
    58 degrees

18
  • n3
  • HF
  • Triangular
    46 degrees
  • Initial input
    58 degrees

19
E,G IP Values for n3
20
  • n4
  • HF
  • Rhombus
  • Only stable
    conformer

21
  • n4()
  • Linear
  • HF

22
E,G IP Values for n4
23
  • n5
  • HF/B3LYP
  • Planar
  • Only stable
    conformer

24
  • n5()
  • Distorted
    tetrahedral
  • B3LYP

25
E,G IP Values for n5
26
  • n6
  • B3LYP
  • Planar

27
  • n6
  • Pentagonal
    pyramidal
  • B3LYP
  • Most stable
    conformer

28
  • n6()
  • Trapezoidal
    bipyramidal
  • B3LYP

29
E,G IP Values for n6
30
IP PLOT OF MOST STABLE CONFORMER FOR EACH n
  • HF B3LYP (IP in
    1000kcal/mol)








    IP of bulk sodium is
    118.589kcal/mol

31
G PLOT OF MOST STABLE CONFORMER FOR EACH n
  • Mod of G of the most
    stable conformer has been
    plotted for
    each n
  • G in 1000kcal/mol

32
Internal energy plot of the most stable
conformer for each n
  • Mod of E of the most
    stable conformer has
    been
    plotted for each n
  • E in 1000kcal/mol

33
General symmetry in structures
  • Na clusters do not form the geometry that are
    very common like tetrahedral, trigonal
    bipyramidal, square pyramidal.
  • Na clusters upto n5 try to form planar
    structures that are composed of distorted
    triangular units.
  • For n6 also , a planar geometry made of
    triangular units exists though it is not the most
    stable one.
  • The most stable is pentagonal pyramidal,with the
    vertex atom going a little bit out of the plane.

34
POSSIBLE REASONS-
  • The absence of highly symmetrical structures may
    be due to the fact that this will help in
    increasing the average atom-atom distance which
    in turn may help in reducing the repulsions.
  • For larger systems like n6, the geometry leaves
    planarity as this makes metal-metal bonding more
    favorable.

35
Problems Faced....
  • The most common problem was error by link 9999.
    This occurs if the initial guess is
    far apart from a minima. The program ,after
    making several iterations, is unable to find an
    optimum position reports an error.
  • When input had perfect symmetry, the convergence
    could not be achieved .

36
What to do then ???
  • The input should be as close as possible.
    But in large systems it is
    difficult to be too close to the optimized
    geometry. So the last optimized geometry given
    by the error file can be used again.
  • Viewing the movie of error file and the frequency
    in molden can help in eliminating the structures
    which are not possible.
  • Avoid exact symmetry .

37

THANK YOU

BY- Aditya Somani Ashish
Kumar
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