Title: 1.7 Solving Inequalities
11.7 Solving Inequalities
- Algebra II
- Mrs. Spitz
- Fall 2006
2Lesson Objectives
- After studying this lesson, you should be able
to - Solve an inequality and graph the solution set,
and - Use inequalities to solve problems
3Assignment
- Pg. 39 11-32 and 38
- EC problems 39-45
4Application
- Jose and Kyle are soccer players on the Taos High
School team. If you compare their scoring for
the season, only one of the following statements
will be true. - Jose scored fewer goals than Kyle.
- Jose scored the same number of goals as Kyle.
- Jose scored more goals than Kyle
5Application
- Let j represent the number of goals Jose scored
and k represent the number of goals Kyle scored.
You can compare the scoring using an inequality
or an equation. - j lt k j k j gt k
- This is an illustration of the trichotomy
property.
6Trichotomy Property
- For any two real numbers, a and b, exactly one of
the following statements is true - a lt b a b a gt b
7Addition and Subtraction properties for
Inequalities
- Adding the same number to each side on an
inequality does not change the truth of the
inequality. - For any real numbers, a, b, and c
- 1. If agtb, then a c gt b c and a c gt b c
- 2. If altb, then a clt b c and a c lt b c
- These properties can be used to solve an
inequality. The solution set of an equality can
be graphed on a number line.
8Example 1 Solve 8x 5 lt 7x - 3
- 8x 5 lt 7x 3
- -7x 8x 5 lt -7x 7x 3 Add -7x to each side
- x 5 lt -3
- x 5 (-5) lt -3 (-5) Add -5 to each side
- x lt -8
A circle means this point is NOT included.
9Example 1 Solve 8x 5 lt 7x - 3
- Any real number less than -8 is a solution.
To check, substitute -8 for x in the inequality.
The two sides should be equal. Then substitute a
number less than -8. The inequality should be
true, or if it isnt you made a math error.
A circle means this point is NOT included.
10NoteYou know that 15 gt -6 is a true inequality.
What happens if you multiply the numbers on each
side by a positive number or a negative number?
Is it still true?
- 15 gt -6
- 7(15) gt 7(-6)
- 105 gt -42 true
- Multiply the inequality by other positive number.
Do you think the inequality will always remain
true?
- 15 gt -6
- -?(15)gt-?(-6)
- -5 gt 2 false
- If you reverse the inequality, the statement is
true. - -5 lt 2 true
- Try other negative numbers as multipliers.
This suggests that when you multiply each side of
an inequality by a negative number, the order of
the inequality must be reversed. These examples
suggest the following properties.
11Multiplication/Division properties for
Inequalities
Multiplication and Division Properties of
Inequalities for positive numbers If a lt b and
c gt 0, then ac lt bc and   lt   If a gt b and
c gt 0, then ac gt bc and   gt
  Multiplication and Division Properties of
Inequalities for negative numbers If a lt b and
c lt 0, then ac gt bc and   gt   If a gt b and
c lt 0, then ac lt bc and   lt   Note All
the above properties apply to and .
12Example 2 Solve -0.5ylt6. Graph the solution
set.
- -0.5y lt 6
- (-2)(-0.5y) gt (-2)(6) Reverse the inequality
sign because each side is multiplied by a
negative - y gt -12
- Any real number greater than -12 is a solution.
-12
13Example 3 Solve x x 4. 7Graph
the solution set.
- x x 4 7
- -7x x 4 Multiply each side by 7
- -8x 4 Add x to each side
- x - 1 Divide each side by -8 reversing the
inequality sign. - 2 A dot means this point is
included. - The solution set is xx -½.
-1/2
14Note
- Inequalities can be used to solve many verbal
problems. You solve problems with inequalities
the same way you solve problems with equations.
15Example 4 the problem
- Judy Kildow received a 10,000 inheritance that
she wishes to invest. She wants to earn at least
780 in interest this year so she can buy a
stereo system with her earnings. She will invest
some of the money in bonds that earn about 6
interest annually and the rest in stock that she
expects to earn 9 interest annually. What is
the minimum she should invest in the stock? The
phrase at least 780 means greater than or equal
to 780
16Ex. 4
- EXPLORE Let n the amount invested in stocks.
Then 10,000 n amount invested in bonds. - PLAN
- (rate)(amount) (rate)(amount) min desired
- (0.09)(n) (0.06)(10,000 n) 780
- SOLVE
- 0.09n 600 0.06n 780 Set up equation
- 0.03n 780 Combine like terms
- n
6000 Divide by 0.03 to solve - Judy must invest at least 6,000 in stock.
17Dont forget the last step!
- EXAMINE OR CHECK Find the amount of interest
she will earn from investing 6,000 in stocks and
4,000 in bonds. Is the total at least 780? - 6 of 4,000 240
- 9 of 6,000 540
- Total 780
- Check an amount more than 6,000 in stocks. Be
sure the total is greater than 780.
18Finally . . .
- Set notation
- x x 5
- Dont forget to graph the solution set.
- Remind your teacher she has some number lines for
you. They are generic and may not work in all
settings.