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Filter

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The average ac power (Pav) is the power dissipated on the load resistor. ... real power Pav(unit: watts): power absorbed by the load resistance. ... – PowerPoint PPT presentation

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Title: Filter


1
Filter Transfer Function
To determine filter type, look how HV as a
function of frequency
Z1 and Z2 could include multiple components
2
RLC at Resonance
  • At resonance
  • current is max.
  • Zeq R
  • current and voltage are in phase.
  • the higher Q, the narrower the resonant peak.

3
Exam II Review AC Power
Average power
rms value
  • The average ac power (Pav) is the power
    dissipated on the load resistor.
  • 0?cosq?1, dependent on the complex load.
  • ideal power factor cosq 1, ZR, pure
    resistive load

4
AC Power instantaneous and average power
5
Complex Power
  • real power Pav(unit watts) power absorbed by
    the load resistance.
  • reactive power Q (unit volt-amperes-reactive,
    VAR) exchange of energy between the source and
    the reactive part of the load. No net power is
    gained or lost during the process. QQL-QC, if
    Qlt0, the load is capacitive, Qgt0, the load is
    inductive
  • Apparent power SVrmsIrms (unit
    volt-amperes, VA) computed by measuring the rms
    load voltage and currents without regard for the
    phase angle.

6
Example 7.8, P345 power factor correction
7
Transformer
Transformation of Voltage
Transformation of Resistance
8
Residential Wiring
GFCI
9
Example Midterm 1998
  • An electrical engineering major has designed and
    constructed a motor for your sophomore design
    project. It has been wound with an inductance of
    16 mH and a resistance of 3.0 ohm. You had
    specified that it be optimized for the best
    possible power factor at 60 Hz consequently, a
    354 microFarad capacitor was added in parallel
    with the motor, as shown below.
  • a. Operated at 120 V, what is the current through
    the motor when operated at 60 Hz?
  • b. What power is delivered by the voltage source?
  • c. What power is dissipated by the motor?
  • Your complete project was so innovative that your
    engineering professor entered it in an
    international competition. You arrive in Germany
    for the competition before remembering that the
    line frequency there is 50 Hz.
  • d. What is the power factor of this circuit at
    50 Hz?
  • e. What capacitance do you need to replace 354 mF
    capacitor in order to correct the power factor
    back to unity?

10
Example Cont.
a. Operated at 120 V, what is the current through
the motor when operated at 60 Hz?
b. What power is delivered by the voltage source?
d. What is the power factor of this circuit at
50 Hz?
e. What capacitance do you need to correct the
power factor back to unity?
Note you calculate S only on the motor part!
Negative just means Capacitor
11
Example 3 1st Fall 199
  • An electrical engineering firm has designed a
    motor for your sophomore design project. You
    specified that it should be wound with an
    inductance of 16 mH and a resistance of 3.0  ohm.
    You had specified that it be optimized for the
    best possible power factor at 60 Hz
    consequently, a 354 mF capacitor was added in
    parallel with the motor. Unfortunately the motor
    was actually wound with an inductance of 61 mH
    and a resistance of 30 ohm because of
    typographical errors in the FAX to the motor
    manufacturer.
  •                                                 
                                                      
                                         
  • What power is delivered by the voltage source?
  • What power is dissipated by the motor?
  • What capacitance do you need to replace 354 mF
    capacitor in order to correct the power factor
    back to unity?

12
Example Cont.
a. What power is delivered by the voltage source?
b. What power is dissipated by the motor?
d. What capacitance do you need to correct the
power factor back to unity?
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