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EOF

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EOF. Both Q and Qa Diagonalized (1) satisfied. Both am and em orthogonal. am (em) is eigenvector of Qa(Q) EOT-normal. Q is diagonalized. Qa is not diagonalized ... – PowerPoint PPT presentation

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Title: EOF


1
EOT-normal Q is diagonalized Qa is not
diagonalized (1) is satisfied with am orthogonal
Q tells about Teleconnections
Matrix Q with elements qij? f(si,t)f(sj,t) t

iteration
Rotation
EOF Both Q and Qa Diagonalized (1) satisfied
Both am and em orthogonal am (em) is eigenvector
of Qa(Q)
Laudable goal f(s,t)? am(t)em(s) (1) m

Discrete Data set f(s,t) 1 t nt 1 s ns
Arbitrary state
Rotation
iteration
Matrix Qa with elements qija?f(s,ti)f(s,tj) s

EOT-alternative Q is not diagonalized Qa is
diagonalized (1) is satisfied with em orthogonal
Qa tells about Analogues
Fig.5.6 Summary of EOT/F procedures.
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