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Solutions to first order first degree pde of the type. P p Q q =R ... Using multipliers 2x, -1, -1 we obtain 2x dx dy dz = 0 which on integration gives ...
... if we can find another relation involving x,y,z,p,q such as (x,y,z,p,q)=0 ....(3) ... q=c2 y/z Substituting this value of q in (ii), p = c (z2-c2y2)/z ...